逗号前后的字符串交换
String Swap Before and After Comma
下面有table
AdviserName
-----------
Tearle, Michael Hearn
Hearn Tearle, Michael
Van Der Welden, Luke
Welden, Luke Van Der
Brennan, Sony G
G Brennan, Sony
Rhammasamysundaran, Vishnu Brahma Kuma
Brahma Kuma Rhammasamysundaran, Vishnu
基本上我需要重新排列,所以它变成了 FirstName MiddleName LastName。例如 Michael Hearn Tearle 或 Sony G Brennan 或 Luke Van Der Welden。
我使用了以下语法,但不知何故它不喜欢中间名在逗号之前,例如 Hearn Tearle, Michael。
If(OBJECT_ID('tempdb..#tempX') Is Not Null)
Drop Table #tempX
create table #tempX (AdviserName varchar(max))
insert into #tempX (AdviserName)
values ('Tearle, Michael Hearn'),('Hearn Tearle, Michael'),('Van Der Welden, Luke'),('Welden, Luke Van Der'),('Brennan, Sony G'),('G Brennan, Sony'),('Rhammasamysundaran, Vishnu Brahma Kuma '), ('Brahma Kuma Rhammasamysundaran, Vishnu ')
--select * from #tempX
select substring(advisername, charindex(',', replace(advisername, ' ', '')) + 1, len(advisername))+' '+ left(advisername, charindex(',', advisername) -1) as AdviserName from #tempX
结果如下。
AdviserName
--------------------------------------
Michael Hearn Tearle
, Michael Hearn Tearle
n, Luke Van Der Welden
Luke Van Der Welden
Sony G Brennan
, Sony G Brennan
Vishnu Brahma Kuma Rhammasamysundaran
n, Vishnu Brahma Kuma Rhammasamysundaran
如何进行查询以同时满足逗号前和逗号后的中间名?
我正在使用 SQL Server 2012。
谢谢大家。
试试这个
If(OBJECT_ID('tempdb..#tempX') Is Not Null)
Drop Table #tempX
create table #tempX (AdviserName varchar(max))
insert into #tempX (AdviserName)
values ('Tearle, Michael Hearn'),('Hearn Tearle, Michael'),('Van Der Welden, Luke'),('Welden, Luke Van Der'),('Brennan, Sony G'),('G Brennan, Sony'),('Rhammasamysundaran, Vishnu Brahma Kuma '), ('Brahma Kuma Rhammasamysundaran, Vishnu ')
select
AdviserName,
replace(replace(
SUBSTRING(AdviserName,charindex(',',AdviserName),len(AdviserName))
+' '+
SUBSTRING(AdviserName,1,charindex(',',AdviserName))
,',',''),' ',' ')
from #tempX
;with d as
(select AdviserName, charindex(',',AdviserName) as comma from #tempX)
select
ltrim(rtrim(substring(advisername,comma+1,100)))+' '+ltrim(rtrim(left(advisername,comma-1)))
from d
下面有table
AdviserName
-----------
Tearle, Michael Hearn
Hearn Tearle, Michael
Van Der Welden, Luke
Welden, Luke Van Der
Brennan, Sony G
G Brennan, Sony
Rhammasamysundaran, Vishnu Brahma Kuma
Brahma Kuma Rhammasamysundaran, Vishnu
基本上我需要重新排列,所以它变成了 FirstName MiddleName LastName。例如 Michael Hearn Tearle 或 Sony G Brennan 或 Luke Van Der Welden。
我使用了以下语法,但不知何故它不喜欢中间名在逗号之前,例如 Hearn Tearle, Michael。
If(OBJECT_ID('tempdb..#tempX') Is Not Null)
Drop Table #tempX
create table #tempX (AdviserName varchar(max))
insert into #tempX (AdviserName)
values ('Tearle, Michael Hearn'),('Hearn Tearle, Michael'),('Van Der Welden, Luke'),('Welden, Luke Van Der'),('Brennan, Sony G'),('G Brennan, Sony'),('Rhammasamysundaran, Vishnu Brahma Kuma '), ('Brahma Kuma Rhammasamysundaran, Vishnu ')
--select * from #tempX
select substring(advisername, charindex(',', replace(advisername, ' ', '')) + 1, len(advisername))+' '+ left(advisername, charindex(',', advisername) -1) as AdviserName from #tempX
结果如下。
AdviserName
--------------------------------------
Michael Hearn Tearle
, Michael Hearn Tearle
n, Luke Van Der Welden
Luke Van Der Welden
Sony G Brennan
, Sony G Brennan
Vishnu Brahma Kuma Rhammasamysundaran
n, Vishnu Brahma Kuma Rhammasamysundaran
如何进行查询以同时满足逗号前和逗号后的中间名?
我正在使用 SQL Server 2012。
谢谢大家。
试试这个
If(OBJECT_ID('tempdb..#tempX') Is Not Null)
Drop Table #tempX
create table #tempX (AdviserName varchar(max))
insert into #tempX (AdviserName)
values ('Tearle, Michael Hearn'),('Hearn Tearle, Michael'),('Van Der Welden, Luke'),('Welden, Luke Van Der'),('Brennan, Sony G'),('G Brennan, Sony'),('Rhammasamysundaran, Vishnu Brahma Kuma '), ('Brahma Kuma Rhammasamysundaran, Vishnu ')
select
AdviserName,
replace(replace(
SUBSTRING(AdviserName,charindex(',',AdviserName),len(AdviserName))
+' '+
SUBSTRING(AdviserName,1,charindex(',',AdviserName))
,',',''),' ',' ')
from #tempX
;with d as
(select AdviserName, charindex(',',AdviserName) as comma from #tempX)
select
ltrim(rtrim(substring(advisername,comma+1,100)))+' '+ltrim(rtrim(left(advisername,comma-1)))
from d