Callback is not a function 错误在selectize
Callback is not a function error in selectize
我正在做一个 yii2-basic 项目,我为我的表单使用了 selectize 扩展。
当我 运行 这部分时 returns 一个错误:回调不是一个函数
report_cp 是一个下拉字段,在选择一个值后它将启用第二个字段并将具有 url + 所选值的函数设置为 report_cs.load
这里是 JsFiddle link https://jsfiddle.net/6uhLts2w/5/ 用测试 json server
替换了 urls
var report_cp; // all these are dropdown inputs
var report_cs; // at start disabled, will enable after report_cp value selected
var report_cnt; // at start disabled, will enable after report_cs value selected
report_cp = $('#reports-cp').selectize({
onChange: function(value) {
if (!value.length) return;
report_cs.enable();
report_cs.load(function (query, callback) {
if (!query.length) return callback();
$.getJSON('../search/sections?id=' + value, { query: encodeURIComponent(query) }, function (data) { callback(data); })//error is right here
.fail(function () { callback(); });
});
},
load:function (query, callback) { //retrieve select options from database
if (!query.length) return callback();
$.getJSON('../search/companies', { query: encodeURIComponent(query) }, function (data) { callback(data); })
.fail(function () { callback(); });
},
valueField: 'id',
labelField: 'name',
searchField: ['name'],
persist: false,
createOnBlur: true,
maxItems: 1,
create: true
});
report_cs = $('#reports-cs').selectize({
onChange: function(value) {
if (!value.length) return;
report_cs.load(function (query, callback) {
if (!query.length) return callback();
$.getJSON('../search/contacts?id=' + value, { query: encodeURIComponent(query) }, function (data) { callback(data); report_cs.enable(); })
.fail(function () { callback(); });
});
},
valueField: 'id',
labelField: 'name',
searchField: ['name'],
persist: false,
createOnBlur: false,
maxItems: 1,
create: false
});
//report_cnt same as report_cs goes here...
Loads options by invoking the provided function. The function should accept one argument (callback) and invoke the callback with the results once they are available.
所以你应该使用 report_cs.load(function (callback) {}...
我正在做一个 yii2-basic 项目,我为我的表单使用了 selectize 扩展。 当我 运行 这部分时 returns 一个错误:回调不是一个函数
report_cp 是一个下拉字段,在选择一个值后它将启用第二个字段并将具有 url + 所选值的函数设置为 report_cs.load
这里是 JsFiddle link https://jsfiddle.net/6uhLts2w/5/ 用测试 json server
替换了 urls var report_cp; // all these are dropdown inputs
var report_cs; // at start disabled, will enable after report_cp value selected
var report_cnt; // at start disabled, will enable after report_cs value selected
report_cp = $('#reports-cp').selectize({
onChange: function(value) {
if (!value.length) return;
report_cs.enable();
report_cs.load(function (query, callback) {
if (!query.length) return callback();
$.getJSON('../search/sections?id=' + value, { query: encodeURIComponent(query) }, function (data) { callback(data); })//error is right here
.fail(function () { callback(); });
});
},
load:function (query, callback) { //retrieve select options from database
if (!query.length) return callback();
$.getJSON('../search/companies', { query: encodeURIComponent(query) }, function (data) { callback(data); })
.fail(function () { callback(); });
},
valueField: 'id',
labelField: 'name',
searchField: ['name'],
persist: false,
createOnBlur: true,
maxItems: 1,
create: true
});
report_cs = $('#reports-cs').selectize({
onChange: function(value) {
if (!value.length) return;
report_cs.load(function (query, callback) {
if (!query.length) return callback();
$.getJSON('../search/contacts?id=' + value, { query: encodeURIComponent(query) }, function (data) { callback(data); report_cs.enable(); })
.fail(function () { callback(); });
});
},
valueField: 'id',
labelField: 'name',
searchField: ['name'],
persist: false,
createOnBlur: false,
maxItems: 1,
create: false
});
//report_cnt same as report_cs goes here...
Loads options by invoking the provided function. The function should accept one argument (callback) and invoke the callback with the results once they are available.
所以你应该使用 report_cs.load(function (callback) {}...