为什么我会得到额外的字符？
Why am I getting extra characters?
计划说明
我使用 .BLKW 为用户输入的每个字符分配 20 个位置，现在，我只想显示用户在第一个提示时键入的字符串。 （这将是一个猪拉丁翻译器，因此是第二个提示；但现在我只想看看我是否可以打印出用户输入）
问题
问题是当我 运行 它时，我在最后得到额外的字符。
例如：
English Word: apple
Pig-Latin Word: apple
English Word: at
Pig-Latin Word: atple
English Word: set
Pig-Latin Word: setle
我的程序
.ORIG x3000
START ST R1,SAVER1
ST R2,SAVER2
ST R3,SAVER3
LD R5,ENTER
REPEAT LEA R0,PROMPT ; loading the starting address of prompt
PUTS ; displays PROMPT on screen
LEA R4,ENGLWORD ; sets aside memory locations for typed characters
INPUT GETC ; now that user has typed, read char into R0
ADD R6,R5,R0 ; adds the negative value of the ASCII enter key code to the input character
BRz PIGPROMPT ; if the sum of the ASCII codes from step before is 0, that means user pressed enter so go to PIGPROMPT
OUT ; write char in R0 to console
STR R0,R4,#0 ; store typed character into memory location
ADD R4,R4,#1 ; increment memory location so you write next character to the next location
BRnzp INPUT ; break no matter what to the INPUT step to receive next typed character
PIGPROMPT LEA R0,PIG ; loads starting address of pig latin prompt
PUTS ; displays pig latin prompt on screen
LEA R0,ENGLWORD
PUTS
BRnzp REPEAT
LD R1,SAVER1 ; restore R1 to original value
LD R2,SAVER2 ; restore R2 to original value
LD R3,SAVER3 ; restore R3 to original value
HALT
SAVER1 .BLKW 1 ; allocates 1 memory location for SAVER1
SAVER2 .BLKW 1 ; allocates 1 memory location for SAVER2
SAVER3 .BLKW 1 ; allocates 1 memory location for SAVER3
ENGLWORD .BLKW #20
ENTER .FILL xFFF6 ; the negative value of the ASCII code for the enter key
NEWLINE .FILL x000A
PROMPT .STRINGZ "\nEnglish Word: " ; initializes a sequence of stringLength+1 memory locations to hold string
PIG .STRINGZ "\nPig-Latin Word: "
DSR .FILL xFE04
DDR .FILL xFE06
KBSR .FILL xFE00
KBDR .FILL xFE02
.END
尝试的解决方案
我在想，问题出在整个程序中，R4 保存着第一个用户输入的字符串。因此，对于一个解决方案，我考虑在显示后清除 R4，以便它准备好接受下一个用户输入。有谁知道我会怎么做？
这里的关键是 PUTS 的工作原理——它打印从 R0 中的地址开始的所有字符，直到它到达 0（'\0' 而不是 '0'）。
第一次运行它，内存将包含['A','P','P','L','E' ]，如果您在加载程序时没有随机化内存内容，则后跟零。这意味着 PUTS 调用将 return "APPLE"。当您输入新单词时，它不会清除内存，因此输入 "at" 将导致 ['A'、'T'、'P'、'L' ,'E']，您的打印例程将打印 "ATPLE".
为了正确完成单词，您需要在要打印的最后一个字符之后的元素中添加一个'\0' (a.k.a. 0)。换句话说，如果您的内存包含 ['A'、'T'、'\0'、'L'、'E']，您的打印例程将打印 "AT"。
Aqua 说得对，PUTs 命令正在寻找一个零以停止将字符打印到屏幕上。我在 PIGPROMPT 之后添加了两行代码，它似乎按预期工作。
修订：
.ORIG x3000
START ST R1,SAVER1
ST R2,SAVER2
ST R3,SAVER3
LD R5,ENTER
REPEAT LEA R0,PROMPT ; loading the starting address of prompt
PUTS ; displays PROMPT on screen
LEA R4,ENGLWORD ; sets aside memory locations for typed characters
INPUT GETC ; now that user has typed, read char into R0
ADD R6,R5,R0 ; adds the negative value of the ASCII enter keycode to the input character
BRz PIGPROMPT ; if the sum of the ASCII codes from step before is 0, that means user pressed enter so go to PIGPROMPT
OUT ; write char in R0 to console
STR R0,R4,#0 ; store typed character into memory location
ADD R4,R4,#1 ; increment memory location so you write next character to the next location
BRnzp INPUT ; break no matter what to the INPUT step to receive next typed character
PIGPROMPT AND R0, R0, #0 ; clear R0
STR R0,R4,#0 ; store typed character into memory location
LEA R0,PIG ; loads starting address of pig latin prompt
PUTS ; displays pig latin prompt on screen
LEA R0,ENGLWORD
PUTS
BRnzp REPEAT
LD R1,SAVER1 ; restore R1 to original value
LD R2,SAVER2 ; restore R2 to original value
LD R3,SAVER3 ; restore R3 to original value
HALT
SAVER1 .BLKW 1 ; allocates 1 memory location for SAVER1
SAVER2 .BLKW 1 ; allocates 1 memory location for SAVER2
SAVER3 .BLKW 1 ; allocates 1 memory location for SAVER3
ENGLWORD .BLKW #20
ENTER .FILL xFFF6 ; the negative value of the ASCII code for the enter key
NEWLINE .FILL x000A
PROMPT .STRINGZ "\nEnglish Word: " ; initializes a sequence of stringLength+1 memory locations to hold string
PIG .STRINGZ "\nPig-Latin Word: "
DSR .FILL xFE04
DDR .FILL xFE06
KBSR .FILL xFE00
KBDR .FILL xFE02
.END
我所做的只是在用户字符串的末尾存储一个“0”值，这样当调用 PUTs 时它将停在零值处。
计划说明
我使用 .BLKW 为用户输入的每个字符分配 20 个位置，现在，我只想显示用户在第一个提示时键入的字符串。 （这将是一个猪拉丁翻译器，因此是第二个提示；但现在我只想看看我是否可以打印出用户输入）
问题
问题是当我 运行 它时，我在最后得到额外的字符。
例如：
English Word: apple
Pig-Latin Word: apple
English Word: at
Pig-Latin Word: atple
English Word: set
Pig-Latin Word: setle
我的程序
.ORIG x3000
START ST R1,SAVER1
ST R2,SAVER2
ST R3,SAVER3
LD R5,ENTER
REPEAT LEA R0,PROMPT ; loading the starting address of prompt
PUTS ; displays PROMPT on screen
LEA R4,ENGLWORD ; sets aside memory locations for typed characters
INPUT GETC ; now that user has typed, read char into R0
ADD R6,R5,R0 ; adds the negative value of the ASCII enter key code to the input character
BRz PIGPROMPT ; if the sum of the ASCII codes from step before is 0, that means user pressed enter so go to PIGPROMPT
OUT ; write char in R0 to console
STR R0,R4,#0 ; store typed character into memory location
ADD R4,R4,#1 ; increment memory location so you write next character to the next location
BRnzp INPUT ; break no matter what to the INPUT step to receive next typed character
PIGPROMPT LEA R0,PIG ; loads starting address of pig latin prompt
PUTS ; displays pig latin prompt on screen
LEA R0,ENGLWORD
PUTS
BRnzp REPEAT
LD R1,SAVER1 ; restore R1 to original value
LD R2,SAVER2 ; restore R2 to original value
LD R3,SAVER3 ; restore R3 to original value
HALT
SAVER1 .BLKW 1 ; allocates 1 memory location for SAVER1
SAVER2 .BLKW 1 ; allocates 1 memory location for SAVER2
SAVER3 .BLKW 1 ; allocates 1 memory location for SAVER3
ENGLWORD .BLKW #20
ENTER .FILL xFFF6 ; the negative value of the ASCII code for the enter key
NEWLINE .FILL x000A
PROMPT .STRINGZ "\nEnglish Word: " ; initializes a sequence of stringLength+1 memory locations to hold string
PIG .STRINGZ "\nPig-Latin Word: "
DSR .FILL xFE04
DDR .FILL xFE06
KBSR .FILL xFE00
KBDR .FILL xFE02
.END
尝试的解决方案
我在想，问题出在整个程序中，R4 保存着第一个用户输入的字符串。因此，对于一个解决方案，我考虑在显示后清除 R4，以便它准备好接受下一个用户输入。有谁知道我会怎么做？
这里的关键是 PUTS 的工作原理——它打印从 R0 中的地址开始的所有字符，直到它到达 0（'\0' 而不是 '0'）。
第一次运行它，内存将包含['A','P','P','L','E' ]，如果您在加载程序时没有随机化内存内容，则后跟零。这意味着 PUTS 调用将 return "APPLE"。当您输入新单词时，它不会清除内存，因此输入 "at" 将导致 ['A'、'T'、'P'、'L' ,'E']，您的打印例程将打印 "ATPLE".
为了正确完成单词，您需要在要打印的最后一个字符之后的元素中添加一个'\0' (a.k.a. 0)。换句话说，如果您的内存包含 ['A'、'T'、'\0'、'L'、'E']，您的打印例程将打印 "AT"。
Aqua 说得对，PUTs 命令正在寻找一个零以停止将字符打印到屏幕上。我在 PIGPROMPT 之后添加了两行代码，它似乎按预期工作。
修订：
.ORIG x3000
START ST R1,SAVER1
ST R2,SAVER2
ST R3,SAVER3
LD R5,ENTER
REPEAT LEA R0,PROMPT ; loading the starting address of prompt
PUTS ; displays PROMPT on screen
LEA R4,ENGLWORD ; sets aside memory locations for typed characters
INPUT GETC ; now that user has typed, read char into R0
ADD R6,R5,R0 ; adds the negative value of the ASCII enter keycode to the input character
BRz PIGPROMPT ; if the sum of the ASCII codes from step before is 0, that means user pressed enter so go to PIGPROMPT
OUT ; write char in R0 to console
STR R0,R4,#0 ; store typed character into memory location
ADD R4,R4,#1 ; increment memory location so you write next character to the next location
BRnzp INPUT ; break no matter what to the INPUT step to receive next typed character
PIGPROMPT AND R0, R0, #0 ; clear R0
STR R0,R4,#0 ; store typed character into memory location
LEA R0,PIG ; loads starting address of pig latin prompt
PUTS ; displays pig latin prompt on screen
LEA R0,ENGLWORD
PUTS
BRnzp REPEAT
LD R1,SAVER1 ; restore R1 to original value
LD R2,SAVER2 ; restore R2 to original value
LD R3,SAVER3 ; restore R3 to original value
HALT
SAVER1 .BLKW 1 ; allocates 1 memory location for SAVER1
SAVER2 .BLKW 1 ; allocates 1 memory location for SAVER2
SAVER3 .BLKW 1 ; allocates 1 memory location for SAVER3
ENGLWORD .BLKW #20
ENTER .FILL xFFF6 ; the negative value of the ASCII code for the enter key
NEWLINE .FILL x000A
PROMPT .STRINGZ "\nEnglish Word: " ; initializes a sequence of stringLength+1 memory locations to hold string
PIG .STRINGZ "\nPig-Latin Word: "
DSR .FILL xFE04
DDR .FILL xFE06
KBSR .FILL xFE00
KBDR .FILL xFE02
.END
我所做的只是在用户字符串的末尾存储一个“0”值，这样当调用 PUTs 时它将停在零值处。