按索引选择 MultiIndex 数据框中的行而不丢失任何级别
Selecting rows in a MultiIndex dataframe by index without losing any levels
我想 select 一个名为 'Mid' 的行,而不丢失它的索引 'Site'
以下代码显示数据框:
m.commodity
price max maxperstep
Site Commodity Type
Mid Biomass Stock 6.0 inf inf
CO2 Env 0.0 inf inf
Coal Stock 7.0 inf inf
Elec Demand NaN NaN NaN
Gas Stock 27.0 inf inf
Hydro SupIm NaN NaN NaN
Lignite Stock 4.0 inf inf
Slack Stock 999.0 inf inf
Solar SupIm NaN NaN NaN
Wind SupIm NaN NaN NaN
North Biomass Stock 6.0 inf inf
CO2 Env 0.0 inf inf
Coal Stock 7.0 inf inf
Elec Demand NaN NaN NaN
Gas Stock 27.0 inf inf
Hydro SupIm NaN NaN NaN
Lignite Stock 4.0 inf inf
Slack Stock 999.0 inf inf
Solar SupIm NaN NaN NaN
Wind SupIm NaN NaN NaN
South Biomass Stock 6.0 inf inf
CO2 Env 0.0 inf inf
Coal Stock 7.0 inf inf
Elec Demand NaN NaN NaN
Gas Stock 27.0 inf inf
Hydro SupIm NaN NaN NaN
Lignite Stock 4.0 inf inf
Slack Stock 999.0 inf inf
Solar SupIm NaN NaN NaN
Wind SupIm NaN NaN NaN
期望的结果如下:
price max maxperstep
Site Commodity Type
Mid Biomass Stock 6.0 inf inf
CO2 Env 0.0 inf inf
Coal Stock 7.0 inf inf
Elec Demand NaN NaN NaN
Gas Stock 27.0 inf inf
Hydro SupIm NaN NaN NaN
Lignite Stock 4.0 inf inf
Slack Stock 999.0 inf inf
Solar SupIm NaN NaN NaN
Wind SupIm NaN NaN NaN
以下答案给出了预期的结果:
m.commodity.xs('Mid', drop_level=False)
m.commodity.loc[['Mid']]
m.commodity.loc['Mid', :, :]
ty MaxU、COLDSPEED 和 jezrael 的答案:)
我相信你需要xs
:
df = m.commodity.xs('Mid', drop_level=False)
print (df)
b price max maxperstep
Site Commodity Type
Mid Biomass Stock 6.0 inf inf
CO2 Env 0.0 inf inf
Coal Stock 7.0 inf inf
Elec Demand NaN NaN NaN
Gas Stock 27.0 inf inf
Hydro SupIm NaN NaN NaN
Lignite Stock 4.0 inf inf
Slack Stock 999.0 inf inf
Solar SupIm NaN NaN NaN
Wind SupIm NaN NaN NaN
对于你来说,另一个问题最好检查 or 。
In [59]: df.loc['Mid', :, :]
Out[59]:
price max maxperstep
Site Commodity Type
Mid Biomass Stock 6.0 inf inf
CO2 Env 0.0 inf inf
Coal Stock 7.0 inf inf
Elec Demand NaN NaN NaN
Gas Stock 27.0 inf inf
Hydro SupIm NaN NaN NaN
Lignite Stock 4.0 inf inf
Slack Stock 999.0 inf inf
Solar SupIm NaN NaN NaN
Wind SupIm NaN NaN NaN
您也可以使用带双大括号的 loc
。
df.loc[['Mid']]
price max maxperstep
Site Commodity Type
Mid Biomass Stock 6.0 inf inf
CO2 Env 0.0 inf inf
Coal Stock 7.0 inf inf
Elec Demand NaN NaN NaN
Gas Stock 27.0 inf inf
Hydro SupIm NaN NaN NaN
Lignite Stock 4.0 inf inf
Slack Stock 999.0 inf inf
Solar SupIm NaN NaN NaN
Wind SupIm NaN NaN NaN
在你的情况下,我想应该是 m.commodity.loc[['Mid']]
。
当谈论 loc
与 ix
时,后者已被弃用,请使用 loc
/iloc
/iat
/xs
用于索引。
ix
对传递的内容做出假设,并接受标签或位置。 loc
纯粹基于标签,而 iloc
纯粹是索引(基于位置)
我想 select 一个名为 'Mid' 的行,而不丢失它的索引 'Site'
以下代码显示数据框:
m.commodity
price max maxperstep
Site Commodity Type
Mid Biomass Stock 6.0 inf inf
CO2 Env 0.0 inf inf
Coal Stock 7.0 inf inf
Elec Demand NaN NaN NaN
Gas Stock 27.0 inf inf
Hydro SupIm NaN NaN NaN
Lignite Stock 4.0 inf inf
Slack Stock 999.0 inf inf
Solar SupIm NaN NaN NaN
Wind SupIm NaN NaN NaN
North Biomass Stock 6.0 inf inf
CO2 Env 0.0 inf inf
Coal Stock 7.0 inf inf
Elec Demand NaN NaN NaN
Gas Stock 27.0 inf inf
Hydro SupIm NaN NaN NaN
Lignite Stock 4.0 inf inf
Slack Stock 999.0 inf inf
Solar SupIm NaN NaN NaN
Wind SupIm NaN NaN NaN
South Biomass Stock 6.0 inf inf
CO2 Env 0.0 inf inf
Coal Stock 7.0 inf inf
Elec Demand NaN NaN NaN
Gas Stock 27.0 inf inf
Hydro SupIm NaN NaN NaN
Lignite Stock 4.0 inf inf
Slack Stock 999.0 inf inf
Solar SupIm NaN NaN NaN
Wind SupIm NaN NaN NaN
期望的结果如下:
price max maxperstep
Site Commodity Type
Mid Biomass Stock 6.0 inf inf
CO2 Env 0.0 inf inf
Coal Stock 7.0 inf inf
Elec Demand NaN NaN NaN
Gas Stock 27.0 inf inf
Hydro SupIm NaN NaN NaN
Lignite Stock 4.0 inf inf
Slack Stock 999.0 inf inf
Solar SupIm NaN NaN NaN
Wind SupIm NaN NaN NaN
以下答案给出了预期的结果:
m.commodity.xs('Mid', drop_level=False)
m.commodity.loc[['Mid']]
m.commodity.loc['Mid', :, :]
ty MaxU、COLDSPEED 和 jezrael 的答案:)
我相信你需要xs
:
df = m.commodity.xs('Mid', drop_level=False)
print (df)
b price max maxperstep
Site Commodity Type
Mid Biomass Stock 6.0 inf inf
CO2 Env 0.0 inf inf
Coal Stock 7.0 inf inf
Elec Demand NaN NaN NaN
Gas Stock 27.0 inf inf
Hydro SupIm NaN NaN NaN
Lignite Stock 4.0 inf inf
Slack Stock 999.0 inf inf
Solar SupIm NaN NaN NaN
Wind SupIm NaN NaN NaN
对于你来说,另一个问题最好检查
In [59]: df.loc['Mid', :, :]
Out[59]:
price max maxperstep
Site Commodity Type
Mid Biomass Stock 6.0 inf inf
CO2 Env 0.0 inf inf
Coal Stock 7.0 inf inf
Elec Demand NaN NaN NaN
Gas Stock 27.0 inf inf
Hydro SupIm NaN NaN NaN
Lignite Stock 4.0 inf inf
Slack Stock 999.0 inf inf
Solar SupIm NaN NaN NaN
Wind SupIm NaN NaN NaN
您也可以使用带双大括号的 loc
。
df.loc[['Mid']]
price max maxperstep
Site Commodity Type
Mid Biomass Stock 6.0 inf inf
CO2 Env 0.0 inf inf
Coal Stock 7.0 inf inf
Elec Demand NaN NaN NaN
Gas Stock 27.0 inf inf
Hydro SupIm NaN NaN NaN
Lignite Stock 4.0 inf inf
Slack Stock 999.0 inf inf
Solar SupIm NaN NaN NaN
Wind SupIm NaN NaN NaN
在你的情况下,我想应该是 m.commodity.loc[['Mid']]
。
当谈论 loc
与 ix
时,后者已被弃用,请使用 loc
/iloc
/iat
/xs
用于索引。
ix
对传递的内容做出假设,并接受标签或位置。 loc
纯粹基于标签,而 iloc
纯粹是索引(基于位置)