需要匹配此示例中的所有单词变体

Question

这将标记单词 betting、gambling、xxx，但不会标记 Betting、Gambling、XXX .

我希望它能标记这些词的所有变体（即 Betting、BEttinG、BETTING 等）。显然，我可以单独列出它们，但我想以某种方式匹配它们，以便标记这些词的所有变体。

$original  = $_POST['message'];

$spamw = array('betting', 'gambling', 'xxx');

foreach ($spamw as $num) {
    if (( $pos = strpos( $original, $num )) !== false) { 
        $err = 'Something went wrong. Please, try again.';
    }
}

已解决

$spamw = array('betting', 'gambling', 'xxx');
$original = $_POST['message'];

foreach ($spamw as $spamwords) {
  if (preg_match("/\b$spamwords\b/i", $original)) {
$err = 'Something went wrong. Please, try again.';
  }
}

Answer 1

好的，我用我脑海中所有变化的 0.1% 更新了解决方案：

<?php
function tospam($dictswrd){
    global $word;
    print('the imput is <span style="color:red">'.$word.'</span> compare to <span style="color:blue">'.$dictswrd.'</span> from Dictionary<br>');
    $pattern = '/(?<!\p{L})'.strtolower($word).'*/iu';
    return preg_match($pattern,$dictswrd ) >0;
}




$dictionary = array('betting', 'gambling', 'xxx'); //a small internal database loaded from a internal file maybe file?
/*
 eg:
$dictionary =file('spam_dictionary.txt');
internal you can drop a file 
spam_dictionary.txt :
---------------
betting
gambling
xxx
---------------
or you can fill the array of dictionary from a kind of database=any kind
*/

if(isset($_POST['message'])){
    print('<h1>FORM`s POST method 1</h1>');

    $word=$_POST['message'];//let's say that's coming from input from post
    $result_spam_or_not=array_filter($dictionary,'tospam' );
    print_r($result_spam_or_not);print('<hr>');

    $word=$_POST['message'];//let's say that's coming from input from post
    $result_spam_or_not=array_filter($dictionary,'tospam' );
    print_r($result_spam_or_not);print('<hr>');


    $word=$_POST['message'];//let's say that's coming from input from post
    $result_spam_or_not=array_filter($dictionary,'tospam' );
    print_r($result_spam_or_not);print('<hr>');

//or
print('<h1>FORM`s POST method 2</h1>');

$word=$_POST['message'];//let's say that's coming from input from post
$result_spam_or_not=array_filter($dictionary,'tospam' );
print(!empty($result_spam_or_not)? 'SPAM':'ok!');print('<hr>');



$word=$_POST['message'];//let's say that's coming from input from post
$result_spam_or_not=array_filter($dictionary,'tospam' );
print(!empty($result_spam_or_not)? 'SPAM':'ok!');print('<hr>');


$word=$_POST['message'];//let's say that's coming from input from post
$result_spam_or_not=array_filter($dictionary,'tospam' );
print(!empty($result_spam_or_not)? 'SPAM':'ok!');print('<hr>');


//or
print('<h1>FORM`s POST method 3</h1>');

$word=$_POST['message'];//let's say that's coming from input from post
$result_spam_or_not=array_filter($dictionary,'tospam' );
if(!empty($result_spam_or_not))print('spam');else print('not a spam');print('<hr>');



$word=$_POST['message'];//let's say that's coming from input from post
$result_spam_or_not=array_filter($dictionary,'tospam' );
if(!empty($result_spam_or_not))print('spam');else print('not a spam');print('<hr>');


$word=$_POST['message'];//let's say that's coming from input from post
$result_spam_or_not=array_filter($dictionary,'tospam' );
if(!empty($result_spam_or_not))print('spam');else print('not a spam');print('<hr>');

}


print('<h1>method 1</h1>');

$word='Gambling';//$word=$_POST['message'];//let's say that's coming from input from post
$result_spam_or_not=array_filter($dictionary,'tospam' );
print_r($result_spam_or_not);print('<hr>');

$word='gambling';//$word=$_POST['message'];//let's say that's coming from input from post
$result_spam_or_not=array_filter($dictionary,'tospam' );
print_r($result_spam_or_not);print('<hr>');


$word='blablabla';//$word=$_POST['message'];//let's say that's coming from input from post
$result_spam_or_not=array_filter($dictionary,'tospam' );
print_r($result_spam_or_not);print('<hr>');


//or
print('<h1>method 2</h1>');

$word='Gambling';//$word=$_POST['message'];//let's say that's coming from input from post
$result_spam_or_not=array_filter($dictionary,'tospam' );
print(!empty($result_spam_or_not)? 'SPAM':'ok!');print('<hr>');



$word='gambling';//$word=$_POST['message'];//let's say that's coming from input from post
$result_spam_or_not=array_filter($dictionary,'tospam' );
print(!empty($result_spam_or_not)? 'SPAM':'ok!');print('<hr>');


$word='blablabla';//$word=$_POST['message'];//let's say that's coming from input from post
$result_spam_or_not=array_filter($dictionary,'tospam' );
print(!empty($result_spam_or_not)? 'SPAM':'ok!');print('<hr>');


//or
print('<h1>method 3</h1>');

$word='Gambling';//$word=$_POST['message'];//let's say that's coming from input from post
$result_spam_or_not=array_filter($dictionary,'tospam' );
if(!empty($result_spam_or_not))print('spam');else print('not a spam');print('<hr>');



$word='gambling';//$word=$_POST['message'];//let's say that's coming from input from post
$result_spam_or_not=array_filter($dictionary,'tospam' );
if(!empty($result_spam_or_not))print('spam');else print('not a spam');print('<hr>');


$word='blablabla';//$word=$_POST['message'];//let's say that's coming from input from post
$result_spam_or_not=array_filter($dictionary,'tospam' );
if(!empty($result_spam_or_not))print('spam');else print('not a spam');print('<hr>');


?><form method="post" action="">
    spam!<input type="text" name="message" value="Gambling"><input type="submit">
</form>
<form method="post" action="">
    spam!<input type="text" name="message" value="gambling"><input type="submit">
</form>
<form method="post" action="">
    not a spam!<input type="text" name="message" value="blablabla"><input type="submit">
</form>

Answer 2

一种方法是将 $spamw 数组中的所有单词存储为小写，就像您现在所做的那样，然后使用 PHP strtolower() 函数将任何用户输入转换为小写字符。然后，您的 PHP 脚本可以将用户输入与存储在 $spamw 数组中的值进行比较，检查是否有任何单词恰好匹配。

Answer 3

简单地使用stripos函数，它找到不区分大小写的子字符串第一次出现的位置，而不是strpos。

需要匹配此示例中的所有单词变体

Need to match all word variations in this example

php

arrays

preg-match