从函数返回 PSCustomObject 属性

Returning PSCustomObject Properties From a Function

我正在制作一个提示选择的函数,并且在 select 选择该选项后,它通过 PSCustomObject 为 returned 变量的 属性 分配了一个值。

function Select-ChoiceFunction {
    # This generates a simple choice menu #
    $Title = "Title"
    $Info = "Info"
    $choice = echo @("Choice &1", "Choice &2", "Choice &3", "&Cancel")
    [int]$defaultchoice = 3
    $selection = $host.UI.PromptForChoice($title, $info, $choice, $defaultchoice)

    # Switch assigns two pieces of data to two variables #
    switch ($selection) {
        0 {
            $var1 = "Data 1"
            $var2 = "Data 2"
            Write-Host "`Choice 1`n"; break
        }
        1 {
            $var1 = "Data 3"
            $var2 = "Data 4"
            Write-Host "`Choice 2`n"; break
        }
        2 {
            $var1 = "Data 5"
            $var2 = "Data 6"
            Write-Host "`Choice 3`n"; break
        }
        default {
            $WarningPreference = "Stop"
            Write-Warning "`nNo Choice Made.`n"
        }
    }

    # Creating PSObject to return Properties from selection outside the Function #
    $Results = [PSCustomObject]@{
        var1 = $var1
        var2 = $var2
    }

    return $Results
}

因此,如果我 运行 独立执行脚本命令,它会按我想要的方式运行。我 select 上面的选项 1 并检查变量显示:

$Results.var1 = "Data 1"
$Results.var2 = "Data 2"

依此类推,相互选择。但是,当我将它包装在一个函数中并在其他地方调用它时,它 return 是两个变量,如下所示:

$Choices = Select-ChoiceFunction

Select 选择 1

$Results.var1 = "Data 1" "Data 2"
$Results.var2 = "Data 1" "Data 2"

我也试过管道 Select-Object 像这样:

$Choices = Select-ChoiceFunction | Select-Object $Results.var1

Select 选择 1 returns 与:

"Data 1" "Data 2"

和上面一样,我想调用函数并独立获取变量属性。我认为该功能制作不正确,但不清楚我需要添加什么才能单独 return 属性。

更新:Ansgar/TheMadTechnician 回答。我应该这样调用属性:

$Choices = Select-ChoiceFunction

Select 选择 1

$Choices.var1 = "Data 1" "Data 2"
$Choices.var2 = "Data 1" "Data 2"

"You are referencing $Results.var1 and $Results.var2 outside of your function, but you should be looking at $Choices.var1 and $Choices.var2." – TheMadTechnician