二进制序列化、静态和单例

Question

在我的 class 通过二进制序列化后，任何对另一个 class 静态实例的引用中断。这个例子应该能更好地解释我的意思：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

using System.IO;
using System.Runtime.Serialization.Formatters.Binary;

namespace staticorsingletontest
{
    [System.Serializable]
    public class weapon 
    {
        public string name;
        public weapon (string name)
            { this.name = name; }
    }
    class Program
    {
        public static weapon sword =  new weapon("Sword");
        public static weapon axe = new weapon("Axe");
        static void Main(string[] args)
        {

            byte[] b;
            Dictionary<weapon, int> WarriorSkills = new Dictionary<weapon,int>();
            Dictionary<weapon, int> Des = new Dictionary<weapon,int>();

            WarriorSkills.Add(sword, 10);
            using (MemoryStream ms = new MemoryStream())
            {
                //Serialize
                new BinaryFormatter().Serialize(ms, WarriorSkills);
                b = ms.ToArray();
                //Deserialize
                ms.Flush();
                ms.Write(b, 0, b.Length);
                ms.Seek(0, SeekOrigin.Begin);

                Des = (Dictionary<weapon, int>)new BinaryFormatter().Deserialize(ms);
            }

            Console.WriteLine(WarriorSkills.Keys.ToArray()[0].name + " is a " + Des.Keys.ToArray()[0].name + ", but are they equal? " + (WarriorSkills.Keys.ToArray()[0] == Des.Keys.ToArray()[0]).ToString());

            Console.ReadLine();

            Console.WriteLine("Warrior's Skill with Sword is ", Des[sword]); //wonderful "KeyNotFoundException" error

            Console.ReadLine();
        }
    }    
}

程序抛出错误，因为反序列化的 "sword" 与 "sword" 不同（它的 static，这是怎么发生的？）

将 weapon class 变成 singleton 是行不通的，因为那样剑和斧头就是一回事了。

有没有办法指出这两把剑是同一回事，或者我没有得到staticclasses的一些核心逻辑？

Answer 1

也许最好的解决方法是完全避免序列化武器。

您可以改为序列化一个武器密钥，并拥有一个类型安全的枚举，您可以从中查找您的武器。

但是，在使用 .net 二进制序列化作为持久性机制之前，您应该考虑所有其他选项 - 它的性能非常差，并且有大量陷阱可能会真正伤害你 - 特别是如果你正在尝试保持版本向后兼容性。

[Serializable]
public sealed class Warrior
{
    private readonly Dictionary<int, int> weaponSkills = new Dictionary<int, int>();

    public void SetWeaponSkill(Weapon weapon, int skill)
    {
        weaponSkills[weapon.Key] = skill;
    }

    public int GetWeaponSkill(Weapon weapon)
    {
        int skill;
        if (!weaponSkills.TryGetValue(weapon.Key, out skill))
        {
            throw new ArgumentException("Warrior doesn't have weapon");
        }
        return skill;
    }
}

public static class Weapons
{
    public static readonly Weapon Sword = new Weapon(1, "Sword");

    public static readonly Weapon Dagger = new Weapon(2, "Dagger");
}

public sealed class Weapon
{
    public Weapon(int key, string text)
    {
        Key = key;
        Text = text;
    }

    public int Key { get; }
    public string Text { get; }
}

Answer 2

如果您反序列化一个（最初是单例的）对象，它将是一个新实例，除非您指定反序列化应该 return 一个 "well known" 实例。但是你可以通过一些定制来做到这一点：

using System;
using System.IO;
using System.Runtime.Serialization;
using System.Runtime.Serialization.Formatters.Binary;

public class Example
{
    [Serializable]
    public class Weapon: IObjectReference // here is the trick, see GetRealObject method
    {
        // unless you want to allow to create any kind of weapon I suggest to use an enum for the predefined types
        private enum WeaponKind { Sword, Axe }

        public static Weapon Sword { get; } = new Weapon(WeaponKind.Sword);
        public static Weapon Axe { get; } = new Weapon(WeaponKind.Axe);

        // this is the only instance field so this will be stored on serialization
        private readonly WeaponKind kind;

        public string Name => kind.ToString();

        // make the constructor private so no one can create further weapons
        private Weapon(WeaponKind kind)
        {
            this.kind = kind;
        }

        // on deserialization ALWAYS a new instance will be created
        // but if you implement IObjectReference, this method will be called before returning the deserialized object
        public object GetRealObject(StreamingContext context)
        {
            // map the temporarily created new deserialized instance to the well-known static member:
            switch (kind)
            {
                case WeaponKind.Sword:
                    return Sword;
                case WeaponKind.Axe:
                    return Axe;
                default:
                    throw new InvalidOperationException("Unknown weapon type");
            }
        }
    }
}

还有一些测试：

public static void Main()
{
    var axe = Weapon.Axe;
    var savedContent = new MemoryStream();
    var formatter = new BinaryFormatter();
    formatter.Serialize(savedContent, axe);
    savedContent.Position = 0;
    var deserializedAxe = (Weapon)formatter.Deserialize(savedContent);
    Console.WriteLine(ReferenceEquals(axe, deserializedAxe)); // prints True
}

更新：

如果你所有的武器属性都是不变的（如果有更多的实例应该被认为是相等的，这不是问题），那么只需覆盖 Equals:

public override bool Equals(object obj)
{
    var other = obj as Weapon;
    if (other == null)
        return base.Equals(obj);
    return other.kind == this.kind;
}

如果覆盖Equals，则必须同时覆盖GetHashCode，否则，您将无法在字典中找到同一对象的不同实例：

public override int GetHashCode()
{
    return kind.GetHashCode();
}

请注意，== 运算符仍将 return 引用相等性。如果你想覆盖它，你需要重载 == 和 != 运算符：

public static bool operator ==(Weapon w1, Weapon w2)
{
    return Equals(w1, w2);
}

public static bool operator !=(Weapon w1, Weapon w2)
{
    return !Equals(w1, w2);
}

二进制序列化、静态和单例

BinarySerialization, Static and Singleton

c#

singleton

serialization

static

binary-serialization