php 替换文本中的多个占位符 returns 1 个元素而不是 2 个

Question

我有一个字符串，我想 return 数组中的 2 个占位符，我该如何实现？

$text = 'is simply dummy text of the printing and [[file::aaa]] typesetting industry. Lorem Ipsum has been the [[file::bbb]] standard dummy text ever since the 1500s.';

if (preg_match("/\[\[.*\]\]/", $text, $matches)) {
    print_r($matches);
}

Answer 1

您可以尝试这样的操作：

if (preg_match_all("/\[\[(.*?)\]\]/", $text, $matches)) {
    print_r($matches);
}

输出：

Array
(
    [0] => Array
        (
            [0] => [[file::aaa]]
            [1] => [[file::bbb]]
        )

    [1] => Array
        (
            [0] => file::aaa
            [1] => file::bbb
        )

)

php 替换文本中的多个占位符 returns 1 个元素而不是 2 个

php replace multiple placeholders in text returns 1 element instead 2

php

preg-match