未定义对基础 Class 构造函数的引用
Undefined Reference to Base Class Constructor
这是我实现双重 linked 列表的代码,它从单个 linked 列表继承了以前的代码,我目前在使用 linker 时遇到问题错误并在过去的一个小时内上网寻找我的问题的答案,但到目前为止没有找到任何可以帮助我的东西。这是我最后的办法了,有人能帮忙吗?
具体来说,当我尝试使用 g++ 处理 link 我的 .o 文件时出现的错误是:
DoublyList.o:DoublyList.cpp:(.text+0xf): undefined reference to
`LinkedList::LinkedList()'
collect2.exe: error: ld returned 1 exit status
我发现了非常相似的问题,但 none 的答案对我有帮助,或者至少我不知道如何在我的代码中具体实现它们,我们将不胜感激。
我的链表class
#ifndef LINKEDLIST_H
#define LINKEDLIST_H
using namespace std;
struct node
{
float value;
node *next;
};
class LinkedList
{
private:
node *first;
public:
LinkedList();
virtual void insert(float val);
virtual void del(float val);
virtual void read();
virtual int search(float val);
};
#endif
我的链表class定义
#include <iostream>
#include "LinkedList.h"
using namespace std;
LinkedList::LinkedList()
{
this->first = NULL;
}
void LinkedList::insert(float val)
{
if(this->first==NULL or this->first->value >= val)
{
node* a_node = new node();
a_node->value = val;
this->first = a_node;
return;
}
node* n = new node();
n = this->first;
node* new_node = new node();
new_node->value = val;
while(n->next != NULL and n->next->value < new_node->value)
{
n = n->next;
}
new_node->next = n->next;
n->next = new_node;
}
void LinkedList::del(float val)
{
node* n = this->first;
node* prev = new node();
prev = n;//in case if it is the first value
int i = this->search(val);
if(this->first->value == val)
{
this->first = this->first->next;
return;
}
if(i != -1)
{
for(int j = 0; j < i; j++)
{
prev = n;
n = n->next;
}
}
//one last check
if(n->value == val)
{
prev->next = n->next;
}
}
void LinkedList::read()
{
node* n = this->first;
int i = 1;
while(n != NULL)
{
cout << i << ". " << n->value << endl;
n = n->next;
i++;
}
}
int LinkedList::search(float val)
{
int i = 0;
node* n = this->first;
while(n != NULL)
{
if(n->value == val)
return i;
else
{
n = n->next;
i++;
}
}
return -1;
}
我的双重名单class
#ifndef DOUBLYLIST_H
#define DOUBLYLIST_H
#include "LinkedList.h"
class DoublyList: public LinkedList
{
public:
struct node
{
float value;
node * next;
node * prev;
};
node * first;
DoublyList();
void insert(float val);
void del(float val);
void read();
int search(float val);
};
#endif
我的双重列表定义
#include <cstddef>
#include "DoublyList.h"
#include "LinkedList.h"
using namespace std;
//constructor
DoublyList::DoublyList()
{
first = NULL;
}
//Insert a node into the correct position in the doubly linked list
void DoublyList::insert(float val)
{
//if linked list is empty or val <= the first node
if(this->first == NULL or this->first->value >= val)
{
node * a_node = new node();
a_node->value = val;//set node's value
//begin replacing and assigning pointers
a_node->next = this->first;
a_node->prev = NULL;
this->first = a_node;
return;
}
node * n = new node();
n = this->first;
node * new_node = new node();
new_node->value = val;
node * prev_node = new node();
while(n->next != NULL and n->next->value < new_node->value)
{
prev_node = n;
n = n->next;
}
prev_node->next = new_node;
new_node->next = n->next;
new_node->prev = prev_node;
n->next = new_node;
}
void DoublyList::del(float val)
{
node * n = this->first;
int i = this->search(val);
//if first node
if(this->first->value == val)
{
this->first = this->first->next;
this->first->prev = NULL;
return;
}
//if value found
if(i != -1)
{
for(int j = 0; j < i; j++)
{
n = n->next;
}
//if a middle node
if(n->value == val and n->next != NULL)
{
n->prev->next = n->next;
return;
}
//if last node
if(n->prev != NULL)
{
n->prev->next = n->next;
}
}
return;//value not found so return
}
void DoublyList::read() { }
int DoublyList::search(float val) { }
编辑:忘记提及此错误具体发生在 DoublyList.cpp 的第 8 行,这是从以前的试验到 link .o 文件。
我用来调用 linker 的命令是
g++ -g main2.cpp DoublyList.o
其中 main2.cpp 是包含我测试代码的主要功能的代码。
感谢 xskxzr,解决方案也是 link LinkedList.o 以及所有其他 .o 文件。如果有人遇到同样的问题,这就是答案。
这是我实现双重 linked 列表的代码,它从单个 linked 列表继承了以前的代码,我目前在使用 linker 时遇到问题错误并在过去的一个小时内上网寻找我的问题的答案,但到目前为止没有找到任何可以帮助我的东西。这是我最后的办法了,有人能帮忙吗?
具体来说,当我尝试使用 g++ 处理 link 我的 .o 文件时出现的错误是:
DoublyList.o:DoublyList.cpp:(.text+0xf): undefined reference to
`LinkedList::LinkedList()'
collect2.exe: error: ld returned 1 exit status
我发现了非常相似的问题,但 none 的答案对我有帮助,或者至少我不知道如何在我的代码中具体实现它们,我们将不胜感激。
我的链表class
#ifndef LINKEDLIST_H
#define LINKEDLIST_H
using namespace std;
struct node
{
float value;
node *next;
};
class LinkedList
{
private:
node *first;
public:
LinkedList();
virtual void insert(float val);
virtual void del(float val);
virtual void read();
virtual int search(float val);
};
#endif
我的链表class定义
#include <iostream>
#include "LinkedList.h"
using namespace std;
LinkedList::LinkedList()
{
this->first = NULL;
}
void LinkedList::insert(float val)
{
if(this->first==NULL or this->first->value >= val)
{
node* a_node = new node();
a_node->value = val;
this->first = a_node;
return;
}
node* n = new node();
n = this->first;
node* new_node = new node();
new_node->value = val;
while(n->next != NULL and n->next->value < new_node->value)
{
n = n->next;
}
new_node->next = n->next;
n->next = new_node;
}
void LinkedList::del(float val)
{
node* n = this->first;
node* prev = new node();
prev = n;//in case if it is the first value
int i = this->search(val);
if(this->first->value == val)
{
this->first = this->first->next;
return;
}
if(i != -1)
{
for(int j = 0; j < i; j++)
{
prev = n;
n = n->next;
}
}
//one last check
if(n->value == val)
{
prev->next = n->next;
}
}
void LinkedList::read()
{
node* n = this->first;
int i = 1;
while(n != NULL)
{
cout << i << ". " << n->value << endl;
n = n->next;
i++;
}
}
int LinkedList::search(float val)
{
int i = 0;
node* n = this->first;
while(n != NULL)
{
if(n->value == val)
return i;
else
{
n = n->next;
i++;
}
}
return -1;
}
我的双重名单class
#ifndef DOUBLYLIST_H
#define DOUBLYLIST_H
#include "LinkedList.h"
class DoublyList: public LinkedList
{
public:
struct node
{
float value;
node * next;
node * prev;
};
node * first;
DoublyList();
void insert(float val);
void del(float val);
void read();
int search(float val);
};
#endif
我的双重列表定义
#include <cstddef>
#include "DoublyList.h"
#include "LinkedList.h"
using namespace std;
//constructor
DoublyList::DoublyList()
{
first = NULL;
}
//Insert a node into the correct position in the doubly linked list
void DoublyList::insert(float val)
{
//if linked list is empty or val <= the first node
if(this->first == NULL or this->first->value >= val)
{
node * a_node = new node();
a_node->value = val;//set node's value
//begin replacing and assigning pointers
a_node->next = this->first;
a_node->prev = NULL;
this->first = a_node;
return;
}
node * n = new node();
n = this->first;
node * new_node = new node();
new_node->value = val;
node * prev_node = new node();
while(n->next != NULL and n->next->value < new_node->value)
{
prev_node = n;
n = n->next;
}
prev_node->next = new_node;
new_node->next = n->next;
new_node->prev = prev_node;
n->next = new_node;
}
void DoublyList::del(float val)
{
node * n = this->first;
int i = this->search(val);
//if first node
if(this->first->value == val)
{
this->first = this->first->next;
this->first->prev = NULL;
return;
}
//if value found
if(i != -1)
{
for(int j = 0; j < i; j++)
{
n = n->next;
}
//if a middle node
if(n->value == val and n->next != NULL)
{
n->prev->next = n->next;
return;
}
//if last node
if(n->prev != NULL)
{
n->prev->next = n->next;
}
}
return;//value not found so return
}
void DoublyList::read() { }
int DoublyList::search(float val) { }
编辑:忘记提及此错误具体发生在 DoublyList.cpp 的第 8 行,这是从以前的试验到 link .o 文件。 我用来调用 linker 的命令是
g++ -g main2.cpp DoublyList.o
其中 main2.cpp 是包含我测试代码的主要功能的代码。
感谢 xskxzr,解决方案也是 link LinkedList.o 以及所有其他 .o 文件。如果有人遇到同样的问题,这就是答案。