python socket error: AF_INET address must be tuple, not str

Question

我有这个小程序：

import sys
import socket

target = "google.co.uk"
port = 443
print(target)

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect(target)
print("successfull connection to: " + target)

当我运行代码时，我得到：

    s.connect(target)
TypeError: getsockaddrarg: AF_INET address must be tuple, not str

当我尝试将行更改为：s.connect(target,443) 我也遇到了一个错误：

    s.connect(target,443)
TypeError: connect() takes exactly one argument (2 given)

问题是什么？

Answer 1

函数接收的参数是一个元组，因此应该给一个元组作为参数。意思是 f(a,b) 用 f((a,b))

调用函数

因此，我们像这样修复您的代码：

import sys
import socket

target = "google.co.uk"
port = 443
print(target)

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((target, port))
print("successfull connection to: " + target)

Answer 2

我遇到了同样的错误。在 PyMySQL 的 connections.py 文件中，有一个名为 connect() 的函数与

行

sock = socket.socket(socket.AF_UNIX, socket.SOCK_STREAM)
sock.settimeout(self.connect_timeout)
sock.connect(self.unix_socket)

一个Windows用户将得到

AttributeError: module 'socket' has no attribute 'AF_UNIX'

到fix it应该把第一行改成

sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

这将得到

File "C:\Users\tiago\Desktop\dev\venv\lib\site-packages\pymysql\connections.py", line 609, in connect
    sock.connect(self.windows_socket)
TypeError: connect(): AF_INET address must be tuple, not str

在的基础上，只需要将第三行改为

sock.connect((self.unix_socket))

所以你应该

sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
sock.settimeout(self.connect_timeout)
sock.connect((self.unix_socket))

python socket error: AF_INET address must be tuple, not str

python socket error: AF_INET address must be tuple, not str

python

sockets

networking

network-programming

socket.io