Room Kotlin 找不到 setter 字段

Question

您好，我正在尝试在基于 MVP 的项目中将 Room 与 Kotlin 一起使用。

我的问题是，当我创建一个数据 class 和相关的 DAO 时，所有 classes 都会成功生成，但是当我创建第二个数据 class 和它是 DAO Error:Cannot find setter for field. 在 android studio

中的重建命令中抛出的

@Entity(tableName = "TB_CLASSES")
class TbClass(
@ColumnInfo(name = "ID")
@PrimaryKey(autoGenerate = true)  var id: Int =-1,
@ColumnInfo(name = "NAME") var name: String="",
@ColumnInfo(name = "CAPTION") var caption: String="",
@ColumnInfo(name = "TYPE") var type: String="")

@Entity(tableName = "TB_FEATURE_DISA")
class TbFeatureDisa(
@ColumnInfo(name = "ID")
@PrimaryKey(autoGenerate = true) var id: Int=-1,
@ColumnInfo(name = "FEATURE_ID") var featureId: Int=-1,
@ColumnInfo(name = "DISA_ID") var disaId: Int=-1,
@ColumnInfo(name = "IS_SOLVED") var isSolved: Int=-1,
@ColumnInfo(name = "DISA_LEVEL") var disaLevel: Double=-0.1,
@ColumnInfo(name = "RESOLVER_USER_NAME") var resolverUserName: String="",
@ColumnInfo(name = "RESOLVE_TIME") var resolveTime: Date? =null,
@ColumnInfo(name = "REPORT_VIST_ID") var reportVisitId: Int=-1,
@ColumnInfo(name = "REPORT_FAULT_ID") var reportFaultId: Int=-1,
@ColumnInfo(name = "SOLVE_VIST_ID") var solveVisitId: Int=-1,
@ColumnInfo(name = "SOLVE_SERVICE_ID") var solveServiceId: Int=-1,
@ColumnInfo(name = "SOLVE_FUALT_ID") var solveFaultId: Int=-1)

我也检查过这个 and this 但其中 none 对我有用

Answer 1

创建一个 data class，它将为

中的属性提供 setters 和 getters

@Entity(tableName = "TB_CLASSES")
data class TbClass( //< add data prior to class
@ColumnInfo(name = "ID")
@PrimaryKey(autoGenerate = true)  var id: Int =-1,
@ColumnInfo(name = "NAME") var name: String="",
@ColumnInfo(name = "CAPTION") var caption: String="",
@ColumnInfo(name = "TYPE") var type: String="")

TbFeatureDisa

    @Entity(tableName = "TB_FEATURE_DISA")
    data class TbFeatureDisa(
    @ColumnInfo(name = "ID")
    @PrimaryKey(autoGenerate = true) var id: Int=-1,
    @ColumnInfo(name = "FEATURE_ID") var featureId: Int=-1,
    @ColumnInfo(name = "DISA_ID") var disaId: Int=-1,
    @ColumnInfo(name = "IS_SOLVED") var isSolved: Int=-1,
    @ColumnInfo(name = "DISA_LEVEL") var disaLevel: Double=-0.1,
    @ColumnInfo(name = "RESOLVER_USER_NAME") var resolverUserName: String="",
    @ColumnInfo(name = "RESOLVE_TIME") var resolveTime: Date? =null,
    @ColumnInfo(name = "REPORT_VIST_ID") var reportVisitId: Int=-1,
    @ColumnInfo(name = "REPORT_FAULT_ID") var reportFaultId: Int=-1,
    @ColumnInfo(name = "SOLVE_VIST_ID") var solveVisitId: Int=-1,
    @ColumnInfo(name = "SOLVE_SERVICE_ID") var solveServiceId: Int=-1,
    @ColumnInfo(name = "SOLVE_FUALT_ID") var solveFaultId: Int=-1)

Answer 2

我终于找到了解决办法。问题与属性命名有关。

编译时出现以下错误：

 @ColumnInfo(name = "IS_SOLVED") var isSolved

但是当我把上面的改成下面的时候，错误就解决了：

 @ColumnInfo(name = "IS_SOLVED") var solved

我们不能使用 SQLite 保留关键字 line 来命名字段。我使用的是 Room 版本 1.0.0 和 kotlin 版本 1.1.51。

Answer 3

对于像我这样缺乏关注并通过 Google 偶然发现的人，使用 val 而不是 var 会给出相同的错误消息。

Room Kotlin 找不到 setter 字段

Room Kotlin Cannot find setter for field

android

kotlin

android-room