bash 函数非零退出代码

Question

在下面的函数"handleExit"中，exitCode为零，即“0”。我希望它是“1”。我的函数名为 "exit 1"。我需要做什么才能检测到函数 "writeToErr" 具有非零状态。

#!/bin/bash

set -euo pipefail

logError() {
  awk " BEGIN { print \"$@\" > \"/dev/fd/2\" }"
}

function writeToErr ()  {
    echo "standard out"
    logError "standard err"
    exit 1
}

function wrapper () {
    writeToErr >>output.log 2>&1
}

function handleExit () {
    echo "handle exit"
    exitCode=$?
    if [ $exitCode -eq "0" ]
     then
        echo "No problem"
     else
        echo "[=11=] exited unexpectedly with status:$exitCode"
        exit 1
     fi
}

trap wrapper EXIT
handleExit >>output.log 2>&1

这里是"output.log"的内容：

handle exit
No problem
standard out
standard err

Answer 1

有两个问题：

你运行handleExit在你运行wrapper之前，所以还没有失败
handleExit 检查 echo

没有说明您要做什么，我猜您想要：

#!/bin/bash

set -euo pipefail

logError() {
    # A better way to write to stderr
    echo "$*" >&2
}

function writeToErr ()  {
    echo "standard out"
    logError "standard err"
    exit 1
}

function wrapper () {
    writeToErr >>output.log 2>&1
}

function handleExit () {
    # Get exit code of the previous command, instead of echo
    exitCode=$?
    echo "handle exit"
    if [ $exitCode -eq "0" ]
     then
        echo "No problem"
     else
        echo "[=10=] exited unexpectedly with status:$exitCode"
        exit 1
     fi
}

# Call handler on exit, so it has something to handle
trap handleExit EXIT
wrapper

bash 函数非零退出代码

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