Delphi SysUtils.Supports 没想到 returns 真
Delphi SysUtils.Supports unexpectedly returns true
我正在根据 Spring4d 的文档示例制作一个 eventPublisher
区别在于订阅者必须明确订阅事件。
我想根据他们是否触发他们的处理程序
实现 IEventHandler<TEventType>
接口。
发布传入事件时,我使用事件的 class 名称和 Spring4d 的 TType.FindType('IEventHandler<TEvent1>')
找到 IEventHandler<TEventType>
类型引用
然后我遍历我的订阅者(实现 IEventHandler 接口的对象)并检查它是否支持 IEventHandler 类型。
问题是 Supports 方法 returns 正确
即使订阅者没有实现接口。
此外,我尝试列出 say TMyEventHandler2
类型的接口。
它包含 IEventHandler<TEvent2>
??
我认为这是由于 IEventHandler<TEvent2>
的限制所致
和 IEventHandler<TEvent1>
共享相同的 GUID
有解决办法吗?
使用这些 classes 和接口:
TEvent1 = class(TObject)
end;
TEvent2 = class(TObject)
end;
IEventHandler = interface(IInvokable)
[guid]
procedure Handle(aEvent : TObject);
end;
IEventHandler<T : class> = interface(IEventHandler)
[guid]
procedure Handle(aEvent : T);
end;
TMyEventHandler1 = class(TObject, IEventHandler, IEventHandler<TEvent1>)
public
procedure Handle(AEvent : TObject); overload;
procedure Handle(AEvent : TEvent1); overload;
end;
TMyEventHandler2 = class(TObject, IEventHandler, IEventHandler<TEvent2>)
public
procedure Handle(AEvent : TObject); overload;
procedure Handle(AEvent : TEvent2); overload;
end;
TEventPublisher = class(TObject)
public
fSubscribers : IList<TValue>;
procedure Subscribe(aSubscriber : TValue); // Simply adds the subscriber to the list of subscribers
procedure Publish(aEvent : TObject); // Publishes an event to the subscribers
end;
procedure TEventPublisher.Publish(const event: TObject; ownsObject: Boolean = True);
const
IEventSubscriberName = 'IEventSubscriber<*>';
var
consumerTypeName: string;
consumerType : TRttiType;
intfType : TRttiInterfaceType;
subscriber : TValue;
subscribed : IInterface;
lEventSubscriber: IEventSubscriber;
lIntfs : IReadOnlyList<TRttiInterfaceType>;
begin
consumerTypeName := StringReplace(IEventSubscriberName, '*', GetQualifiedClassName(event), []);
consumerType := TType.FindType(consumerTypeName);
intfType := consumerType as TRttiInterfaceType;
for subscriber in fSubscribers do
begin
lIntfs := TType.GetType(subscriber.AsObject.ClassInfo).GetInterfaces();
// lIntfs for TMyEventHandler2 containts IEventHandler<TEvent1> ???
if Supports(subscriber.AsObject, intfType.GUID, subscribed) then
if Supports(subscriber.AsObject, IEventSubscriber, lEventSubscriber) then
begin
intfType.GetMethod('Handle').Invoke(TValue.From(@subscribed, intfType.Handle), [event])
end;
end;
if ownsObject then
event.Free;
end;
lEventPublisher := TEventPublisher.Create;
lEventPublisher.Subscribe(TMyEventHandler1.Create);
lEventPublisher.Subscribe(TMyEventHandler2.Create);
lEventPublisher.Publish(TEvent1.Create); // Will both trigger TMyEventHandler1.Handle and TMyEventHandler2.Handle. Why ??
发生这种情况是因为如果您将 guid 放在通用接口上,则该接口的每个特化都将具有相同的 guid,而不管其通用类型参数。
我通常通过在界面中提供有关该信息的方法来解决这个问题(比如 Spring.Collections.IEnumerable
有一个 ElementType
属性 来获取 [=13 的实际类型=]).
所以实现看起来像这样:
program GenericEventPublisher;
{$APPTYPE CONSOLE}
uses
Spring,
Spring.Collections,
System.SysUtils;
type
IEventHandler = interface
['{2E4BD8F4-4EB8-4B33-84F4-B70F42EF9208}']
procedure Handle(const event: TObject);
end;
IEventHandler<T: class> = interface
['{82B7521E-D719-4051-BE2C-2EC449A92B22}']
procedure Handle(const event: T);
function GetHandledClass: TClass;
end;
IEventPublisher = interface
['{2A460EF0-AE27-480F-ACEA-1B897F2DE056}']
procedure Subscribe(const subscriber: IEventHandler);
procedure Publish(const event: TObject; ownsObject: Boolean = True);
end;
TEventHandlerBase<T: class> = class(TInterfacedObject, IEventHandler, IEventHandler<T>)
private
function GetHandledClass: TClass;
procedure Handle(const event: TObject); overload;
public
procedure Handle(const event: T); overload; virtual; abstract;
end;
TEvent1 = class
end;
TEvent2 = class
end;
TMyEventHandler1 = class(TEventHandlerBase<TEvent1>)
public
procedure Handle(const event: TEvent1); override;
end;
TMyEventHandler2 = class(TEventHandlerBase<TEvent2>)
public
procedure Handle(const event: TEvent2); override;
end;
TEventPublisher = class(TInterfacedObject, IEventPublisher)
private
fSubscribers: IList<IEventHandler>;
public
constructor Create;
procedure Subscribe(const subscriber: IEventHandler);
procedure Publish(const event: TObject; ownsObject: Boolean = True);
end;
{ TEventPublisher }
constructor TEventPublisher.Create;
begin
fSubscribers := TCollections.CreateList<IEventHandler>;
end;
procedure TEventPublisher.Publish(const event: TObject; ownsObject: Boolean);
var
subscriber: IEventHandler;
eventSubscriber: IEventHandler<TObject>;
begin
for subscriber in fSubscribers do
if Supports(subscriber, IEventHandler<TObject>, eventSubscriber)
and (eventSubscriber.GetHandledClass = event.ClassType) then
eventSubscriber.Handle(event);
if ownsObject then
event.Free;
end;
procedure TEventPublisher.Subscribe(const subscriber: IEventHandler);
begin
fSubscribers.Add(subscriber)
end;
{ TEventHandlerBase<T> }
function TEventHandlerBase<T>.GetHandledClass: TClass;
begin
Result := T;
end;
procedure TEventHandlerBase<T>.Handle(const event: TObject);
begin
Assert(event is T);
Handle(T(event));
end;
{ TMyEventHandler1 }
procedure TMyEventHandler1.Handle(const event: TEvent1);
begin
Writeln(event.ClassName, ' handled by ', ClassName);
end;
{ TMyEventHandler2 }
procedure TMyEventHandler2.Handle(const event: TEvent2);
begin
Writeln(event.ClassName, ' handled by ', ClassName);
end;
var
eventPublisher: IEventPublisher;
begin
eventPublisher := TEventPublisher.Create;
eventPublisher.Subscribe(TMyEventHandler1.Create);
eventPublisher.Subscribe(TMyEventHandler2.Create);
eventPublisher.Publish(TEvent1.Create);
eventPublisher.Publish(TEvent2.Create);
end.
由于接口上有 class 约束,我们可以确定接口是二进制兼容的,无论 T 的类型如何(因为它们只能是对象)。还为通用事件处理程序使用基类型减少了要编写的额外代码。它只是将非通用 Handle
方法重定向到必须在具体实现中实现的通用方法。
此外,由于基础 class 实现了这两个接口,我们不需要将处理程序存储在 TValue
列表中,但可以使用非通用接口类型并轻松访问它们而无需RTTI.
现在 Publish
方法使用了一个小技巧,用 IEventHandler<TObject>
调用 Support
- 因为 eventSubscriber
是那种类型,我们可以传递 event
参数添加到它的 Handle
方法中,这恰好是正确的 - 这是因为我之前解释过的二进制兼容性,因为我们只是处理不同的 classes 作为 T 的类型 - 故事将是完整的如果我们没有 class 约束,则不同。
我正在根据 Spring4d 的文档示例制作一个 eventPublisher
区别在于订阅者必须明确订阅事件。
我想根据他们是否触发他们的处理程序
实现 IEventHandler<TEventType>
接口。
发布传入事件时,我使用事件的 class 名称和 Spring4d 的 TType.FindType('IEventHandler<TEvent1>')
IEventHandler<TEventType>
类型引用
然后我遍历我的订阅者(实现 IEventHandler 接口的对象)并检查它是否支持 IEventHandler 类型。
问题是 Supports 方法 returns 正确 即使订阅者没有实现接口。
此外,我尝试列出 say TMyEventHandler2
类型的接口。
它包含 IEventHandler<TEvent2>
??
我认为这是由于 IEventHandler<TEvent2>
的限制所致
和 IEventHandler<TEvent1>
共享相同的 GUID
有解决办法吗?
使用这些 classes 和接口:
TEvent1 = class(TObject)
end;
TEvent2 = class(TObject)
end;
IEventHandler = interface(IInvokable)
[guid]
procedure Handle(aEvent : TObject);
end;
IEventHandler<T : class> = interface(IEventHandler)
[guid]
procedure Handle(aEvent : T);
end;
TMyEventHandler1 = class(TObject, IEventHandler, IEventHandler<TEvent1>)
public
procedure Handle(AEvent : TObject); overload;
procedure Handle(AEvent : TEvent1); overload;
end;
TMyEventHandler2 = class(TObject, IEventHandler, IEventHandler<TEvent2>)
public
procedure Handle(AEvent : TObject); overload;
procedure Handle(AEvent : TEvent2); overload;
end;
TEventPublisher = class(TObject)
public
fSubscribers : IList<TValue>;
procedure Subscribe(aSubscriber : TValue); // Simply adds the subscriber to the list of subscribers
procedure Publish(aEvent : TObject); // Publishes an event to the subscribers
end;
procedure TEventPublisher.Publish(const event: TObject; ownsObject: Boolean = True);
const
IEventSubscriberName = 'IEventSubscriber<*>';
var
consumerTypeName: string;
consumerType : TRttiType;
intfType : TRttiInterfaceType;
subscriber : TValue;
subscribed : IInterface;
lEventSubscriber: IEventSubscriber;
lIntfs : IReadOnlyList<TRttiInterfaceType>;
begin
consumerTypeName := StringReplace(IEventSubscriberName, '*', GetQualifiedClassName(event), []);
consumerType := TType.FindType(consumerTypeName);
intfType := consumerType as TRttiInterfaceType;
for subscriber in fSubscribers do
begin
lIntfs := TType.GetType(subscriber.AsObject.ClassInfo).GetInterfaces();
// lIntfs for TMyEventHandler2 containts IEventHandler<TEvent1> ???
if Supports(subscriber.AsObject, intfType.GUID, subscribed) then
if Supports(subscriber.AsObject, IEventSubscriber, lEventSubscriber) then
begin
intfType.GetMethod('Handle').Invoke(TValue.From(@subscribed, intfType.Handle), [event])
end;
end;
if ownsObject then
event.Free;
end;
lEventPublisher := TEventPublisher.Create;
lEventPublisher.Subscribe(TMyEventHandler1.Create);
lEventPublisher.Subscribe(TMyEventHandler2.Create);
lEventPublisher.Publish(TEvent1.Create); // Will both trigger TMyEventHandler1.Handle and TMyEventHandler2.Handle. Why ??
发生这种情况是因为如果您将 guid 放在通用接口上,则该接口的每个特化都将具有相同的 guid,而不管其通用类型参数。
我通常通过在界面中提供有关该信息的方法来解决这个问题(比如 Spring.Collections.IEnumerable
有一个 ElementType
属性 来获取 [=13 的实际类型=]).
所以实现看起来像这样:
program GenericEventPublisher;
{$APPTYPE CONSOLE}
uses
Spring,
Spring.Collections,
System.SysUtils;
type
IEventHandler = interface
['{2E4BD8F4-4EB8-4B33-84F4-B70F42EF9208}']
procedure Handle(const event: TObject);
end;
IEventHandler<T: class> = interface
['{82B7521E-D719-4051-BE2C-2EC449A92B22}']
procedure Handle(const event: T);
function GetHandledClass: TClass;
end;
IEventPublisher = interface
['{2A460EF0-AE27-480F-ACEA-1B897F2DE056}']
procedure Subscribe(const subscriber: IEventHandler);
procedure Publish(const event: TObject; ownsObject: Boolean = True);
end;
TEventHandlerBase<T: class> = class(TInterfacedObject, IEventHandler, IEventHandler<T>)
private
function GetHandledClass: TClass;
procedure Handle(const event: TObject); overload;
public
procedure Handle(const event: T); overload; virtual; abstract;
end;
TEvent1 = class
end;
TEvent2 = class
end;
TMyEventHandler1 = class(TEventHandlerBase<TEvent1>)
public
procedure Handle(const event: TEvent1); override;
end;
TMyEventHandler2 = class(TEventHandlerBase<TEvent2>)
public
procedure Handle(const event: TEvent2); override;
end;
TEventPublisher = class(TInterfacedObject, IEventPublisher)
private
fSubscribers: IList<IEventHandler>;
public
constructor Create;
procedure Subscribe(const subscriber: IEventHandler);
procedure Publish(const event: TObject; ownsObject: Boolean = True);
end;
{ TEventPublisher }
constructor TEventPublisher.Create;
begin
fSubscribers := TCollections.CreateList<IEventHandler>;
end;
procedure TEventPublisher.Publish(const event: TObject; ownsObject: Boolean);
var
subscriber: IEventHandler;
eventSubscriber: IEventHandler<TObject>;
begin
for subscriber in fSubscribers do
if Supports(subscriber, IEventHandler<TObject>, eventSubscriber)
and (eventSubscriber.GetHandledClass = event.ClassType) then
eventSubscriber.Handle(event);
if ownsObject then
event.Free;
end;
procedure TEventPublisher.Subscribe(const subscriber: IEventHandler);
begin
fSubscribers.Add(subscriber)
end;
{ TEventHandlerBase<T> }
function TEventHandlerBase<T>.GetHandledClass: TClass;
begin
Result := T;
end;
procedure TEventHandlerBase<T>.Handle(const event: TObject);
begin
Assert(event is T);
Handle(T(event));
end;
{ TMyEventHandler1 }
procedure TMyEventHandler1.Handle(const event: TEvent1);
begin
Writeln(event.ClassName, ' handled by ', ClassName);
end;
{ TMyEventHandler2 }
procedure TMyEventHandler2.Handle(const event: TEvent2);
begin
Writeln(event.ClassName, ' handled by ', ClassName);
end;
var
eventPublisher: IEventPublisher;
begin
eventPublisher := TEventPublisher.Create;
eventPublisher.Subscribe(TMyEventHandler1.Create);
eventPublisher.Subscribe(TMyEventHandler2.Create);
eventPublisher.Publish(TEvent1.Create);
eventPublisher.Publish(TEvent2.Create);
end.
由于接口上有 class 约束,我们可以确定接口是二进制兼容的,无论 T 的类型如何(因为它们只能是对象)。还为通用事件处理程序使用基类型减少了要编写的额外代码。它只是将非通用 Handle
方法重定向到必须在具体实现中实现的通用方法。
此外,由于基础 class 实现了这两个接口,我们不需要将处理程序存储在 TValue
列表中,但可以使用非通用接口类型并轻松访问它们而无需RTTI.
现在 Publish
方法使用了一个小技巧,用 IEventHandler<TObject>
调用 Support
- 因为 eventSubscriber
是那种类型,我们可以传递 event
参数添加到它的 Handle
方法中,这恰好是正确的 - 这是因为我之前解释过的二进制兼容性,因为我们只是处理不同的 classes 作为 T 的类型 - 故事将是完整的如果我们没有 class 约束,则不同。