连接 Python 列表中的不完整序列

Question

我有一个包含完整和不完整句子的列表。完整的句子以 .、? 或 ! 结束。如何遍历列表中的元素并加入不完整的句子？例如，

输入：

myList = ['My first','sentence is incomplete.','Hold on.','Is the second complete?','The third','might not be!','Thanks.','Really appreciate.']

期望的输出：

myList = ['My first sentence is incomplete.','Hold on.','Is the second complete?','The third might not be!','Thanks','Really appreciate.']

Answer 1

这是一个 brute-force 使用 collections.defaultdict 的方法。

from collections import defaultdict

myList = ['My first','sentence is incomplete.','Hold on.','Is the second complete?',
          'The third','might not be!','Thanks.','Really appreciate.']

d = defaultdict(list)

idx = 0
for j in myList:
    d[idx].append(j)
    if any(j.endswith(k) for k in ('.', '!', '?')):
        idx += 1

sentences = [' '.join(v) for _, v in sorted(d.items())]

结果：

['My first sentence is incomplete.',
 'Hold on.',
 'Is the second complete?',
 'The third might not be!',
 'Thanks.',
 'Really appreciate.']

Answer 2

不完整句子的拼接是比较容易的部分，用“+”符号拼接句子例如用myList[0]+myList[1]得到'My first sentence is incomplete.' You should erase列表中使用的元素以后不会有任何问题。要验证要添加哪些，您应该使用这样的 while 循环：

while (myList!=[]):
    index=0
    if myList[index][-1]=="." or myList[index][-1]=="?" or myList[index][-1]=="!" : #checks if the last element of the string is a . ? or !
        #make a function to concatenate the list elements from myList[0] to myList[index],and delete said elements from the original list, remember to reset index to 0 and repeaat process

连接 Python 列表中的不完整序列

Concatenating incomplete setences from lists in Python

python

list

concatenation

string-concatenation

输入：

期望的输出：