使用 DC.js 和交叉过滤器的复合图(条形图和线形图),当条形值 = 0 时线消失

Composite graph (bar & line) using DC.js and crossfilter, line disappears when bar value = 0

当度量的最后一个值为零时,该线在复合图中消失。我有 code pen here

这是我的示例数据:

    var data = [
        { "ID": 1, "TxDate": "2017/12/30", "InstCode": "Loc1", "NTS": 7, "NTS2": 1 },
        { "ID": 2, "TxDate": "2017/12/31", "InstCode": "Loc1", "NTS": 14, "NTS2": 6 },
        { "ID": 3, "TxDate": "2017/12/31", "InstCode": "Loc1", "NTS": 1, "NTS2": 1 },
        { "ID": 4, "TxDate": "2017/12/30", "InstCode": "Loc2", "NTS": 1, "NTS2": 1 },
        { "ID": 5, "TxDate": "2018/01/02", "InstCode": "Loc2", "NTS": 2, "NTS2": 1 },
        { "ID": 6, "TxDate": "2018/01/02", "InstCode": "Loc2", "NTS": 1, "NTS2": 1 },
        { "ID": 7, "TxDate": "2018/01/03", "InstCode": "Loc1", "NTS": 3, "NTS2": 4 },
        { "ID": 8, "TxDate": "2018/01/03", "InstCode": "Loc1", "NTS": 1, "NTS2": 1 },
        { "ID": 9, "TxDate": "2018/01/04", "InstCode": "Loc1", "NTS": 1, "NTS2": 1 },
        { "ID": 10, "TxDate": "2018/01/02", "InstCode": "Loc2", "NTS": 4, "NTS2": 1 },
        { "ID": 11, "TxDate": "2018/01/03", "InstCode": "Loc1", "NTS": 22, "NTS2": 14 },
        { "ID": 12, "TxDate": "2018/01/02", "InstCode": "Loc1", "NTS": 2, "NTS2": 0 },
        { "ID": 13, "TxDate": "2018/01/04", "InstCode": "Loc2", "NTS": 0, "NTS2": 0 },
        { "ID": 14, "TxDate": "2018/01/04", "InstCode": "Loc2", "NTS": 0, "NTS2": 0 },
        { "ID": 15, "TxDate": "2018/02/04", "InstCode": "Loc2", "NTS": 0, "NTS2": 3 }
    ];

var yearPieChart = dc.pieChart("#year-pie-chart");
var monthBarChart = dc.barChart("#month-bar-chart");
var composite = dc.compositeChart('#compo-bar-line-chart');

问题是"NTS"的最后一个值:1的那一刻,合成图出现了。如果我更改下面的行

{ "ID": 15, "TxDate": "2018/02/04", "InstCode": "Loc2", "NTS": 0, "NTS2": 3 }

{ "ID": 15, "TxDate": "2018/02/04", "InstCode": "Loc2", "NTS": 1, "NTS2": 3 }

合成图出现。有没有什么方法可以在值 "NTS": 0 时显示图表 非常感谢您的帮助。

复合条码:

composite
                    .width(1200).height(450)
                    .margins({ top: 20, bottom: 90, right: 10, left: 70 })
                    .x(d3.scale.ordinal().domain(nonEmptytxNTSGroup))
                    .xUnits(dc.units.ordinal)
                    //.xAxisLabel('Date')
                    .yAxisLabel("NTS")
                    .elasticX(true)
                    .elasticY(true)
                    //.rightYAxisLabel('Final Treatments')
                    .group(nonEmptytxNTSGroup)
                    .renderLabel(true)
                    ._rangeBandPadding(1)
                    .compose(
                    [
                        dc.barChart(composite)
                            .gap(1)
                            .centerBar(true)
                            .group(nonEmptytxNTSGroup)
                            .elasticX(true)
                            .elasticY(true)
                            .renderLabel(true),

                        dc.lineChart(composite)
                            .group(nonEmptytxFinalTxGroup)
                            .useRightYAxis(false)
                            .colors('red')
                            .elasticX(true)
                            .elasticY(true)
                            .renderDataPoints({
                                radius: 10,
                                fillOpacity: 5.5,
                                strokeOpacity: 5.8
                            })
                            .renderLabel(true)
                    ]
                    );


composite.renderlet(function (composite) {
                        composite.selectAll("g.x text")
                            .attr('dx', '-35')
                            //.select("g.axis.y")
                            //.attr("transform", "rotate(-45)");
                            .attr('transform', "translate(-10,0) rotate(-65)");
                    });

在复合图表中,所有子图表将共享相同的 X 比例尺。这是由给予父(复合)图表的组决定的。

在您的示例中,您使用条形图组作为复合图表组。如果折线图组有任何不在条形图组中的键,则拒绝绘制。 (具体来说,它在行中以一些 NaN 结束,对于比例中不存在的 X 值,然后完整性检查将其重置为空行。)

解决此问题的最简单方法是不使用 remove_empty_bins。然后域将始终匹配两个图表。

更复杂但可以说更可靠的方法是使用通常用于堆叠图表的解决方案,其中所有堆叠还必须在其 X 域中匹配。

The FAQ contains combine_groups:

function combine_groups() { // (groups...)
    var groups = Array.prototype.slice.call(arguments);
    return {
        all: function() {
            var alls = groups.map(function(g) { return g.all(); });
            var gm = {};
            alls.forEach(function(a, i) {
                a.forEach(function(b) {
                    if(!gm[b.key]) {
                        gm[b.key] = new Array(groups.length);
                        for(var j=0; j<groups.length; ++j)
                            gm[b.key][j] = 0;
                    }
                    gm[b.key][i] = b.value;
                });
            });
            var ret = [];
            for(var k in gm)
                ret.push({key: k, value: gm[k]});
            return ret;
        }
    };
}

从非空组中生成一个组合组,如下所示:

var combined = combine_groups(nonEmptytxNTSGroup, nonEmptytxFinalTxGroup);

给复合图表设置公共域:

                composite
                    // ...
                    .group(combined)

告诉每个子图表从组合值之一中提取其值:

                    .compose(
                    [
                        dc.barChart(composite)
                            // ...
                            .group(combined, "1", function(kv) { return kv.value[0]; })
                            // ...
                        dc.lineChart(composite)
                            .group(combined, "2", function(kv) { return kv.value[1]; })
                            // ...
                    ]

现在您有一个复合图表,它将使用两个非空组的域的 并集。请注意,这也会强制子图表具有相同的域:任何跳过的值现在都将设置为 0:

此处最后一个柱为零,但仍绘制其 0 标签,因为折线图在那里具有非零值。

Fork of your codepen.