我如何聚合引用另一个 table 的 2 列的数据，并获得过去 3 个月的每月总计？

Question

使用以下数据：

如何根据listofincidents[=33=中的两列（crime_incidentid、similar_incidentid）得到每个事件的成本总和]?

另外，如何获取过去 3 个月（1 月、2 月和 3 月）的总和？

create table crimeincidents (
  id int not null,
  name varchar(20),
  primary key (id)
);

create table listofincidents (
  id int not null,
  incidentdate datetime not null,
  crime_incidentid int not null,
  similar_incidentid int not null,
  cost_to_city decimal(8,2),
  primary key (id),
  FOREIGN KEY (crime_incidentid) REFERENCES crimeincidents(id),
  FOREIGN KEY (similar_incidentid) REFERENCES crimeincidents(id)
); 

insert into crimeincidents  (id,name) values 
  (1,'Burglary'),
  (2,'Theft'),
  (3,'Grand theft auto');

insert into listofincidents (id, incidentdate, crime_incidentid,
  similar_incidentid, cost_to_city) 
 values
  (1, "2018-01-10 18:48:00", 1, 2, 900),
  (2, "2018-02-15 14:48:00", 2, 3, 800),
  (3, "2018-02-20 18:10:00", 3, 1, 1500.10), 
  (4, "2018-03-20 18:48:00", 1, 3, 800.23),
  (5, "2018-03-25 18:24:00", 1, 3, 200.00),
  (6, "2018-04-15 10:12:00", 1, 2, 400.00);

生成没有每月日期的结果的查询是：

select c.id, c.name, sm.similarIncidentCost, cr.crimeIncidentCost 
  from crimeincidents c
  inner join (
    select c.id, sum(s.cost_to_city) similarIncidentCost 
    from crimeincidents c inner join listofincidents s 
                          on s.similar_incidentid = c.id
    group by c.id
  ) sm on sm.id = c.id
  inner join (
     select c.id, sum(cr.cost_to_city) crimeIncidentCost 
       from crimeincidents c inner join listofincidents cr 
                             on cr.crime_incidentid = c.id
       group by c.id
  ) cr on cr.id = c.id;

我想使用过去 3 个月的数据生成成本。最终结果应如下所示：

1. January   | 1500.1   |   1900.23
2. February  | 900      |   800
3. March     | 1800.23  |   1500.1

Answer 1

我认为这就是您的要求：

SELECT DATE_FORMAT(li.incidentdate, '%Y-%m') as date,
ci.name,
SUM(
li.cost_to_city
) as totalCost
FROM crimeincidents ci
JOIN listofincidents li ON ci.id = li.crime_incidentid OR ci.id = li.similar_incidentid
GROUP BY date, ci.id
ORDER BY date

你可以选择：

SELECT CONCAT(YEAR(li.incidentdate), ' ', MONTHNAME(li.incidentdate)) as month,
ci.name,
SUM(
li.cost_to_city
) as totalCost
FROM crimeincidents ci
JOIN listofincidents li ON ci.id = li.crime_incidentid OR ci.id = li.similar_incidentid
GROUP BY month, ci.id
ORDER BY month

为了更好地满足您的要求。

一开始没注意到您要将 "incident" 和 "similar incident" 的和分开。虽然我觉得很奇怪（因为类似的事件他自己也有类似的事件）我做了查询：

SELECT CONCAT(YEAR(li.incidentdate), ' ', MONTHNAME(li.incidentdate)) as month,
ci.name,
SUM(
IF(ci.id = li.id, li.cost_to_city,0)
) as totalCostIncident,
SUM(
IF(ci.id = li.similar_incidentid, li.cost_to_city,0)
) as totalCostSimilarIncident
FROM crimeincidents ci
JOIN listofincidents li ON ci.id = li.crime_incidentid OR ci.id = li.similar_incidentid
GROUP BY month, ci.id
ORDER BY month

我如何聚合引用另一个 table 的 2 列的数据，并获得过去 3 个月的每月总计？

How do i aggregate data from 2 columns referencing another table and also get the monthly totals for the past 3 months?

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