如何使用 Akka HTTP 表示表单数据请求?

How to represent a form-data request using Akka HTTP?

我想使用 Akka HTTP 创建一个到 Facebook API 的表单数据 http 请求。在 curl 中,请求示例如下所示:

curl \
 -X POST \
 "https://graph-video.facebook.com/v2.3/1533641336884006/videos"  \
 -F "access_token=XXXXXXX" \
 -F "upload_phase=transfer" \
 -F "start_offset=0" \
 -F "upload_session_id=1564747013773438" \
 -F "video_file_chunk=@chunk1.mp4"

所以我为请求负载表示创建了以下模型:

case class FBSingleChunkUpload(accessToken: String, 
    sessionId: String,
    from: Long, 
    to: Long, 
    file: File) //file is always ~1Mb

那我要用:

Http().cachedHostConnectionPoolHttps[String]("graph-video.facebook.com")

但我不知道如何将 FBSingleChunkUpload 转换为正确的 HttpRequest :(

你能给我一个提示吗,如何使用 Akka HTTP 表示此类请求?

有一个 FormData Entity 类型

 val fBSingleChunkUpload = ???
 HttpRequest(method = HttpMethods.POST,
              entity = FormData(("accessToken", fBSingleChunkUpload.accessToken), ...).toEntity)

此外,对于文件,您可以检查它是否适用于 Multipart.FormData

 val fileFormPart = Multipart.FormData
    .BodyPart("name", HttpEntity(MediaTypes.`application/octet-stream`, file.length(), FileIO.fromPath(file.toPath)))

  val otherPart = Multipart.FormData.BodyPart.Strict("accessToken", "the token")

  val entity =
    Multipart.FormData(otherPart, fileFormPart).toEntity

在 curl 中,-F 选项规定 POST 使用 "multipart/form-data" 内容类型。要在 Akka HTTP 中创建这样的请求,请使用 Multipart.FormData (defaultEntity below is borrowed from Akka HTTP's MultipartSpec):

val chunkUpload = FBSingleChunkUpload(...)

def defaultEntity(content: String) =
  HttpEntity.Default(ContentTypes.`text/plain(UTF-8)`, content.length, Source(ByteString(content) :: Nil))

val streamed = Multipart.FormData(Source(
  Multipart.FormData.BodyPart("access_token", defaultEntity(chunkUpload.accessToken)) ::
  Multipart.FormData.BodyPart("upload_phase", defaultEntity("transfer")) ::
  Multipart.FormData.BodyPart("start_offset", defaultEntity(chunkUpload.from.toString)) ::
  Multipart.FormData.BodyPart("upload_session_id", defaultEntity(chunkUpload.sessionId)) ::
  Multipart.FormData.BodyPart.fromFile(
    "video_file_chunk", ContentType.Binary(MediaTypes.`video/mp4`), chunkUpload.file
  ) :: Nil))

val request =
  HttpRequest(method = HttpMethods.POST, uri = /** your URI */, entity = streamed.toEntity)