我如何在 Kotlin 的 List<E> 的构造函数参数中设置值

Question

我创建了一个 Account 的 pojo class，其中有一个 Address class 的数组。我想从我的主要片段中设置 address 的参数值。我该如何设置？请看我的Account模型代码，Address模型代码和我设置账户模型数据的主要片段。

账户模型 (POJO)

class Account(
          var OrganizationName: String?,
          var Addresses: List<Address>?,) : Serializable {

constructor() : this(null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null)}

地址模型 (POJO)

class Address(
var Id: Int?,

var Name: String?,
var AddressLine1: String?,
var AddressLine2: String?,
var City: String?,
var Locality: String?,
var State: String?,
var ZipCode: Int?,
):Serializable

主要片段 class 我在其中设置帐户和地址 class 参数的详细信息。

  class AccountDetailsFragment constructor
  (onCheckChanged: OnCheckChanged, changeTabs: ChangeTabs) : BaseFragment() {override fun onCreateView(inflater: LayoutInflater, container: ViewGroup?, savedInstanceState: Bundle?): View? {
    val view = inflater.inflate(R.layout.fragment_account_details, container, false)


    return view
}

 fun getFilledData(account: Account): Account {

    account.OrganizationName = "name"

    // How do i insert the value for address's parameters here.

    return account


}


}

Answer 1

首先，您使用了错误的变量命名约定。 Read more here.

fun getFilledData(account: Account): Account {

    account.OrganizationName = "name"

    val addresses = ArrayList<Address>()
    for(i in 0..10){

        //create and  insert your multiple addresses here
        val address  = Address(i,"name $i","line1 $i","line2 $i ","city $i","locality $i","state $i ", i)

        addresses.add(address)
    }
    //assign list to account
    account.Addresses = addresses

    return account
}

我如何在 Kotlin 的 List<E> 的构造函数参数中设置值

How do i set the value in List<E>'s constructor parameters in kotlin

java

android

pojo

kotlin

retrofit