django 序列化程序 is_valid() return false

Question

使用 Django 2.0.2 Python3.4

MySerializers.py

class MySerializer(BaseSerializer):
    UserUID = serializers.CharField()
    DeviceUID = serializers.CharField()
    SessionId = serializers.CharField()

MyView.py

class MyVeiw(BaseViewSet):
    serializer_class = MySerializer

    def create(self, request, *args, **kwargs):
        serializer_class = MySerializer(data=request.data.dict())
        if serializer_class.is_valid():
            print(serializer_class.errors)
            return Response(0)
        else:
            return Response(1)

输入数据

{'SessionId': '222a282f-c3f8-46d2-8476-8d4ec627a477', 'UserUID': '62', 'DeviceUI
D': '25'}

serializer_class

 return MySerializer(data={'SessionId': '7c5d0530-8e54-42aa-91a0-ce8776c82490', 'Us
erUID': '64', 'DeviceUID': '27'}):
    UserUID = CharField()
    DeviceUID = CharField()
    SessionId = CharField()

serializer_class.initial_data

return {'UserUID': '65', 'DeviceUID': '28', 'SessionId': 'aecef14f-
       7f9d-4f01-bc1d-89514  8ab0c05'}

serializer_class.errors

return {}

但 is_valid() 总是 false

为什么错误 return empty list

我尝试更改 SessionId UUIDField() 但没有用

和 UserUID , DeviceUID 更改 IntegerField() 但不起作用

我认为这个序列化程序是有效的，为什么 return false

Answer 1

将 class MySerializer(BaseSerializer): 更改为 class MySerializer(Serializer):。

正如 Bear Brown 提到的；如果您从 BaseSerialzier 继承，您应该自己定义 to_internal_value。

默认情况下，BaseSerializer 引发 NotImplementedError:

def to_internal_value(self, data):
    raise NotImplementedError('`to_internal_value()` must be implemented.')

django 序列化程序 is_valid() return false

django serializer is_valid() return false

python

django

django-serializer

django-rest-framework