当其中一个结果未通过测试时如何删除与分组 ID 相关的所有结果

how to remove all results relating to a grouped ID when one of the results fails a test

所以我要做的是从按 KEYVADD(ID) 分组的 CKDBAUDDP 中检索所有订单。然后我想做的只是 return 如果状态在特定日期范围内的订单。使用我目前拥有的代码,添加另一个 "and" 与 STMPADD 比较只会从已完成的查询中删除这些结果。这并不是我真正想要发生的事情,因为那时结果变得不那么清楚了。

exec('  select KEYVADD
    ,min(case when VALUADD=0 then STMPADD else null end) as "Status 0"
    ,min(case when VALUADD=2 then STMPADD else null end) as "Status 2"
    ,min(case when VALUADD=4 then STMPADD else null end) as "Status 4"
    ,min(case when VALUADD=5 then STMPADD else null end) as "Status 5"
    ,min(case when VALUADD=7 then STMPADD else null end) as "Status 7"
    ,min(case when VALUADD=8 then STMPADD else null end) as "Status 8"
    ,min(case when VALUADD=9 then STMPADD else null end) as "Status 9"
    ,min(nmdoh) as "Customer"
    ,min(c.scscn) as "Container"
    ,min(whsoh) as "Warehouse"
    ,min(preoh) as "Preorder"
from CKDBAUDDP a
left outer join mvpscohp h on left(a.KEYVADD,7) = h.ONHOH
left outer join mvpscnhp c on h.onhoh = c.onhcn
where whsoh in (700,711,721,731) 
    and IMGTADD = ''A''
    and KEYVADD IN (786398200,786417600)                                                                                                     
group by KEYVADD

') at nordic

下面是从上面的查询中检索到的一些测试数据。

KEYVADD    |            Status 0            |           Status 2            |           Status 4            |   Status 5  | Status 7  |             Status 8         |  Status 9  |     Customer  | Container  |    Warehouse | Preorder
786398200  |  2018-04-30 13:07:53.8780000   |   2018-04-30 10:21:41.9330000 |  2018-04-30 13:08:18.8560000  |   NULL      | NULL      | 2018-04-30 16:33:11.8850000  |  NULL      |  test name    |  27739742  |      721     |  N
786417600  |  2018-04-30 13:07:53.9080000   |   2018-04-30 11:21:15.7810000 |  2018-04-30 13:08:18.8930000  |   NULL      | NULL      | 2018-04-30 18:13:07.7940000  |  NULL      |  test name 2  |  27739744  |      721     |  N

如果我不希望第二个显示,因为状态 2 是在上午 11 点之后,我将其放在 And 语句中,那么问题就出在这个例子中,它只会删除时间并放置一个 Null结果不是我想要的。我怎样才能让它一起删除那个 ID?

抱歉,信息太多了,但希望它能清楚地说明我想要表达的意思。谢谢!

我想你会使用 having:

having datepart(hour, min(case when VALUADD = 2 then STMPADD end)) >= 11