在 python 中将字符串附加到 .txt 文件的每一行?

Append String to each line of .txt file in python?

我想在文件的每一行中附加一些文本

这是我的代码

filepath = 'hole.txt'
with open(filepath) as fp:
    line = fp.readline()
    cnt = 1
    while line:
        #..........
        #want to append text "#" in every line by reading line by line 
        text from .txt file
        line = fp.readline()
        cnt += 1

您可以阅读这些行并将它们放入列表中。然后你用写入模式打开同一个文件,并在每一行中写入你想要追加的字符串。

filepath = "hole.txt"
with open(filepath) as fp:
    lines = fp.read().splitlines()
with open(filepath, "w") as fp:
    for line in lines:
        print(line + "#", file=fp)

假设您可以将全文加载到内存中,您可以打开文件,按行拆分并为每一行附加“#”。然后保存 :-) :

with open(filepath, 'r') as f:     # load file
    lines = f.read().splitlines()  # read lines

with open('new_file.txt', 'w') as f: 
    f.write('\n'.join([line + '#' for line in lines]))  # write lines with '#' appended

我假设文件足够小,可以在内存中保留两个副本:

filepath = 'hole.txt'
with open(filepath, 'r') as f:
    original_lines = f.readlines()

new_lines = [line.strip() + "#\n" for line in original_lines]

with open(filepath, 'w') as f:
    f.writelines(new_lines)

首先,我们打开文件并将所有行读入列表。然后,通过 strip() 每行的行终止符生成一个新列表,在它之后添加一些额外的文本和一个新的行终止符。

然后,最后一行用修改后的新行覆盖文件。

这有帮助吗?

inputFile = "path-to-input-file/a.txt"
outputFile = "path-to-output-file/b.txt"
stringToAPpend = "#"

with open(inputFile, 'r') as inFile, open(outputFile, 'w') as outFile:
    for line in inFile:
        outFile.write(stringToAPpend+line)