如何从列表中删除引号？

Question

我正在为我的一个朋友制作一个 discord.py 机器人。我想这样做，以便您可以将愚蠢的引号添加到列表中，然后随机选择它们。就这么多，我做到了。

但是，我也希望能够删除不相关的、拼写错误的引号等。我想知道如何才能做到这一点。

这是我目前得到的：

import discord
from discord.ext.commands import Bot
from discord.ext import commands
import random
import pickle
import os

Client = discord.Client()
bot_prefix = "."
bot = commands.Bot(command_prefix=bot_prefix)

@bot.event
async def on_ready():
    print("Bot Online!")
    print("Name: {}".format(bot.user.name))
    print("ID: {}".format(bot.user.id))

class Main_Commands():
    def __init__(self, bot):
     self.bot = bot

# .addquote
@bot.command(pass_context = True)
async def addquote(ctx, *answer):
    answer=" ".join(answer)
    if not os.path.isfile("quote_file.pk1"):
        quote_list = []
    else:
        with open("quote_file.pk1", "rb") as quote_file:
            quote_list = pickle.load(quote_file)
    quote_list.append(answer)
    with open("quote_file.pk1", "wb") as quote_file:
        pickle.dump(quote_list, quote_file)
    await bot.say('Quote: "{}" added!'.format(answer))

# .quote
@bot.command(pass_context = True)
async def quote(ctx):
    with open("quote_file.pk1", "rb") as quote_file:
        quote_list = pickle.load(quote_file)
    await bot.say(random.choice(quote_list))

bot.run("TOKEN")

基本上，我想添加另一个功能，.removequote() 可以删除特定引号，同时保持其他引号不变。

Answer 1

删除引号与添加引号非常相似，只有一行需要替换。代替 .append，使用列表 comp 来过滤掉不需要的引用。其他一切都可以保持不变。

# .removequote
@bot.command(pass_context = True)
async def removequote(ctx, *answer):
    answer=" ".join(answer)
    if not os.path.isfile("quote_file.pk1"):
        quote_list = []
    else:
        with open("quote_file.pk1", "rb") as quote_file:
            quote_list = pickle.load(quote_file)

    # This line:
    quote_list = [quote for quote in quote_list if quote != answer]

    with open("quote_file.pk1", "wb") as quote_file:
        pickle.dump(quote_list, quote_file)
    await bot.say('Quote: "{}" deleted!'.format(answer))

每个服务器 pickling，你可以为每个服务器使用不同的文件名，或者为你的 pickle 使用字典（我个人认为存储在一个单独的文件中更有效，因为你不必加载其他服务器的引号):

# .removequote
@bot.command(pass_context = True)
async def removequote(ctx, *answer):
    answer=" ".join(answer)
    filename = "quote_file_{}.pkl".format(ctx.message.server.id)
    if not os.path.isfile(filename):
        quote_list = []
    else:
        with open(filename, "rb") as quote_file:
            quote_list = pickle.load(quote_file)

    quote_list = [quote for quote in quote_list if quote != answer]

    with open(filename, "wb") as quote_file:
        pickle.dump(quote_list, quote_file)
    await bot.say('Quote: "{}" deleted!'.format(answer))

如何从列表中删除引号？

How can you remove a quote from a list?

python

bots

discord

discord.py