在postgres中查找系列的长度

Finding the length of a series in postgres

postgres 的棘手查询。想象一下,我有一组行,其中有一个名为(例如)成功的布尔列。像这样:

id | success  
9  | false  
8  | false  
7  | true  
6  | true  
5  | true  
4  | false  
3  | false  
2  | true  
1  | false  

而且我需要计算最新(不)成功系列的长度。例如在这种情况下,“3”表示成功,“2”表示不成功。或者使用 window 函数,然后像这样:

id | success | length  
9  | false   | 2  
8  | false   | 2  
7  | true    | 3  
6  | true    | 3  
5  | true    | 3  
4  | false   | 1  
3  | true    | 2  
2  | true    | 2  
1  | false   | 1  

(请注意,我通常只需要最新系列的长度,而不是全部)

到目前为止我找到的最接近的答案是这篇文章: https://jaxenter.com/10-sql-tricks-that-you-didnt-think-were-possible-125934.html (参见#5)

但是,postgres 不支持 "IGNORE NULLS" 选项,因此查询无效。没有 "IGNORE NULLS" 它只是 returns 我在长度列中为空。

这是我能得到的最接近的:

WITH
  trx1(id, success, rn) AS (
    SELECT id, success, row_number() OVER (ORDER BY id desc) 
    FROM results
  ),
  trx2(id, success, rn, lo, hi) AS (
    SELECT trx1.*,
    CASE WHEN coalesce(lag(success) OVER (ORDER BY id DESC), FALSE) != success THEN rn END,
    CASE WHEN coalesce(lead(success) OVER (ORDER BY id DESC), FALSE) != success THEN rn END
    FROM trx1
  )
SELECT trx2.*, 1
- last_value (lo) IGNORE nulls OVER (ORDER BY id DESC ROWS BETWEEN
UNBOUNDED PRECEDING AND CURRENT ROW)
+ first_value(hi) OVER (ORDER BY id DESC ROWS BETWEEN CURRENT ROW
AND UNBOUNDED FOLLOWING)
AS length FROM trx2;

您对这样的查询有什么想法吗?

可以使用window函数row_number()指定系列:

select max(id) as max_id, success, count(*) as length
from (
    select *, row_number() over wa - row_number() over wp as grp
    from my_table
    window
        wp as (partition by success order by id desc),
        wa as (order by id desc)
    ) s
group by success, grp
order by 1 desc

 max_id | success | length 
--------+---------+--------
      9 | f       |      2
      7 | t       |      3
      4 | f       |      2
      2 | t       |      1
      1 | f       |      1
(5 rows)

DbFiddle.

尽管 Klin 的回答完全正确,但我想 post 我朋友建议的另一个解决方案:

with last_success as (
  select max(id) id from my_table where success
)
select count(mt.id) last_fails_count
from my_table mt, last_success lt
where mt.id > lt.id;

--------------------
| last_fails_count |
--------------------
| 2                |
--------------------

DbFiddle

如果我只需要获取最后一个失败或成功的系列,它会快两倍。