在其他列上有条件地从 hive table 获取最新的列值
get latest column value from hive table conditionally on other columns
我有一个 Hive table 'Orders' 有四列(id 字符串、名称字符串、顺序字符串、ts 字符串)。 table的样本数据如下。
-------------------------------------------
id name order ts
-------------------------------------------
1 abc completed 2018-04-12 08:15:26
2 def received 2018-04-15 06:20:17
3 ghi processed 2018-04-16 11:36:56
4 jkl received 2018-04-05 12:23:34
3 ghi received 2018-03-23 16:43:46
1 abc processed 2018-03-17 18:39:22
1 abc received 2018-02-25 20:07:56
Order 列有三个状态 received -> processed -> completed。单个名称有很多订单,每个订单都有这三个阶段。我需要给定 'id' 和 'name' 的最新订单值。这对你来说似乎是一个新手问题,但我坚持这个。
我尝试编写如下查询,但它们不起作用,而且我无法直接在 'ts' 列上使用 max 函数,因为它是字符串格式。请建议一个最好的方法。
提前致谢。
我试过的查询
SELECT
ORDER
FROM Orders
WHERE id = '1'
AND name = 'ghi'
AND ts = (
SELECT max(unix_timestamp(ts, 'yyyy-MM-dd HH:mm:SS'))
FROM Orders
)
Error while compiling statement: FAILED: ParseException line 2:0 cannot recognize input near 'select' 'max' '(' in expression specification
SELECT
ORDER
FROM Orders
WHERE id = '1'
AND name = 'ghi'
AND max(unix_timestamp(ts, 'yyyy-MM-dd HH:mm:SS'))
Error while compiling statement: FAILED: SemanticException [Error 10128]: Line 1:93 Not yet supported place for UDAF 'max'
select o.order from Orders o
inner join (
select id, name, order, max(ts) as ts
from Orders
group by id, name, order
) ord on d.id = ord.id and o.name = ord.name and o.ts = ord.ts where o.id = '1' and o.name = 'abc'
执行了此查询,但输出的不是单个最新订单阶段,而是每个订单阶段都有对应的最新时间戳。
请帮忙。
您可以使用 RANK 分析功能来解决您的问题,如下所示:
select id,name,order,ts
from (select id,name,order,ts,rank() over(partition by id,name order by ts) r from orders)k
where r = 1
and id = '1'
and name = 'ghi'
如果您想获取所有 ID 和姓名的最新记录,则无需传递 "ID" 和 "NAME" 的值,您将轻松获得所需的结果。
祝一切顺利!!!
对于给定的订单,您需要一行。因此,您可以使用 order by
和 limit
:
SELECT o.*
FROM Orders o
WHERE id = 1 AND -- presumably id is a number
name = 'ghi'
ORDER BY ts DESC
LIMIT 1;
这个应该也是性能最好的
我有一个 Hive table 'Orders' 有四列(id 字符串、名称字符串、顺序字符串、ts 字符串)。 table的样本数据如下。
-------------------------------------------
id name order ts
-------------------------------------------
1 abc completed 2018-04-12 08:15:26
2 def received 2018-04-15 06:20:17
3 ghi processed 2018-04-16 11:36:56
4 jkl received 2018-04-05 12:23:34
3 ghi received 2018-03-23 16:43:46
1 abc processed 2018-03-17 18:39:22
1 abc received 2018-02-25 20:07:56
Order 列有三个状态 received -> processed -> completed。单个名称有很多订单,每个订单都有这三个阶段。我需要给定 'id' 和 'name' 的最新订单值。这对你来说似乎是一个新手问题,但我坚持这个。
我尝试编写如下查询,但它们不起作用,而且我无法直接在 'ts' 列上使用 max 函数,因为它是字符串格式。请建议一个最好的方法。 提前致谢。
我试过的查询
SELECT
ORDER
FROM Orders
WHERE id = '1'
AND name = 'ghi'
AND ts = (
SELECT max(unix_timestamp(ts, 'yyyy-MM-dd HH:mm:SS'))
FROM Orders
)
Error while compiling statement: FAILED: ParseException line 2:0 cannot recognize input near 'select' 'max' '(' in expression specification
SELECT
ORDER
FROM Orders
WHERE id = '1'
AND name = 'ghi'
AND max(unix_timestamp(ts, 'yyyy-MM-dd HH:mm:SS'))
Error while compiling statement: FAILED: SemanticException [Error 10128]: Line 1:93 Not yet supported place for UDAF 'max'
select o.order from Orders o
inner join (
select id, name, order, max(ts) as ts
from Orders
group by id, name, order
) ord on d.id = ord.id and o.name = ord.name and o.ts = ord.ts where o.id = '1' and o.name = 'abc'
执行了此查询,但输出的不是单个最新订单阶段,而是每个订单阶段都有对应的最新时间戳。
请帮忙。
您可以使用 RANK 分析功能来解决您的问题,如下所示:
select id,name,order,ts
from (select id,name,order,ts,rank() over(partition by id,name order by ts) r from orders)k
where r = 1
and id = '1'
and name = 'ghi'
如果您想获取所有 ID 和姓名的最新记录,则无需传递 "ID" 和 "NAME" 的值,您将轻松获得所需的结果。
祝一切顺利!!!
对于给定的订单,您需要一行。因此,您可以使用 order by
和 limit
:
SELECT o.*
FROM Orders o
WHERE id = 1 AND -- presumably id is a number
name = 'ghi'
ORDER BY ts DESC
LIMIT 1;
这个应该也是性能最好的