PARTITION BY 表达式引用既未分组也未聚合的列 sku

Question

我正在尝试执行此查询

select
rank() over (partition by substr(upper(sku),1,19) order by round(avg(inpf.amount),2) desc) as ranking from erp.input_factor  inpf

我一直收到错误消息： PARTITION BY 表达式引用在 [5:40]

既未分组也未聚合的列 SKU

当然，我不希望将 sku 添加到 group by 这就是它在 over 子句中的原因。这里有什么问题吗？

实际查询：

select sq.fab_id , sq.sku as sku
from
(
select upper(inpf.fab_id) as fab_id, substr(upper(sku),1,19) as sku ,round(avg(inpf.amount),2) as amount,
  rank() over (partition by substr(upper(sku),1,19) order by round(avg(inpf.amount),2) desc) as ranking ,
fi.main_construction as construct from erp.input_factor  inpf
left join
erp.fabric_information fi
on upper(inpf.fab_id) = upper(fi.fab_id)

where length(inpf.fab_id) > 3
group by inpf.fab_id , substr(upper(sku),1,19) , fi.main_construction
) sq
where (sq.construct = 1)

Answer 1

这是 BigQuery 的特点。一个简单的解决方案是子查询：

select sq.fab_id , sq.sku as sku
from (select upper(inpf.fab_id) as fab_id, sku19 as sku, 
             round(avg(inpf.amount),2) as amount,
             rank() over (partition by sku19 order by inpf.amount desc) as ranking,
            fi.main_construction as construct
      from erp.input_factor inpf left join
           (select fi.*, substr(upper(sku), 1, 19) as sku19
            from erp.fabric_information fi
           ) fi
           on upper(inpf.fab_id) = upper(fi.fab_id)
      where length(inpf.fab_id) > 3
      group by inpf.fab_id, sku19 , fi.main_construction
     ) sq
where sq.construct = 1;

注意：您没有注意到 sku 的来源，所以我只是猜测。

PARTITION BY 表达式引用既未分组也未聚合的列 sku

PARTITION BY expression references column sku which is neither grouped nor aggregated

sql

window-functions

google-bigquery