序列号添加不同步
serial number add not synchronized
我不知道放在哪里我能想象"synchronized",但它仍然是线程不安全,帮助,非常感谢!多线程竞争添加一个序列号'a'。应该线程Demo的运行方法可以同步吗?不管怎样,我把它加到"public void run()"一个synchronized,它仍然显示一个不安全的消息。
package Whosebug;
import java.util.ArrayList;
import java.util.List;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
public class NumberEx {
public static void main(String[] args) {
// TODO Auto-generated method stub
ExecutorService service=Executors.newCachedThreadPool();
for(int i=0;i<10;i++) {
service.execute(new ThreadDemo());
}
service.shutdown();
}
}
package Whosebug;
import java.io.FileNotFoundException;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.Iterator;
import java.util.List;
import java.util.concurrent.atomic.AtomicInteger;
public class ThreadDemo implements Runnable {
private static volatile int a = 0;
private static volatile List<Integer> list=new ArrayList<Integer>();
static PrintWriter writer;
static {
try {
writer=new PrintWriter("./src/out.txt");
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
@Override
public void run() {
while (a< 1000) {
//critical section
a= increment(a);
//end
}
writer.close();
}
private static synchronized int increment(int a) {
writer.print("<<<<============"+Thread.currentThread().getName()+"======================== ");
a=a+1;
Integer temp=new Integer(a);
writer.print(" Thread["+Thread.currentThread().getName()+"]" + ":"+ a);
writer.print(" ============="+Thread.currentThread().getName()+"=======================>>>>> ");
if(list.contains(temp)) {
System.out.println("repeat number"+temp);
Iterator<Integer> iter=list.iterator();
while(iter.hasNext()) {
System.out.print(iter.next()+" ");
}
System.exit(0);
}else {
list.add(temp);
}
writer.println(" "+temp+"\n");
return a;
}
}
我可能是错的,但我认为你需要包围
//critical section
a= increment(a);
//end
使用同步块并像这样引入锁对象:
private static final Object LOCK = new Object();
@Override
public void run() {
while (true) {
synchronized (LOCK) {
if(a<1000){
//critical section
a = increment(a);
//end
}else{
break;
}
}
}
}
你还需要检查同步块内部的条件,否则你会得到大于 1000 的数字。
编辑。之前的回答不正确。
不好意思这个愚蠢的问题,我最近学习了对象监视器,最后通过对象上的同步解决了ti
我不知道放在哪里我能想象"synchronized",但它仍然是线程不安全,帮助,非常感谢!多线程竞争添加一个序列号'a'。应该线程Demo的运行方法可以同步吗?不管怎样,我把它加到"public void run()"一个synchronized,它仍然显示一个不安全的消息。
package Whosebug;
import java.util.ArrayList;
import java.util.List;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
public class NumberEx {
public static void main(String[] args) {
// TODO Auto-generated method stub
ExecutorService service=Executors.newCachedThreadPool();
for(int i=0;i<10;i++) {
service.execute(new ThreadDemo());
}
service.shutdown();
}
}
package Whosebug;
import java.io.FileNotFoundException;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.Iterator;
import java.util.List;
import java.util.concurrent.atomic.AtomicInteger;
public class ThreadDemo implements Runnable {
private static volatile int a = 0;
private static volatile List<Integer> list=new ArrayList<Integer>();
static PrintWriter writer;
static {
try {
writer=new PrintWriter("./src/out.txt");
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
@Override
public void run() {
while (a< 1000) {
//critical section
a= increment(a);
//end
}
writer.close();
}
private static synchronized int increment(int a) {
writer.print("<<<<============"+Thread.currentThread().getName()+"======================== ");
a=a+1;
Integer temp=new Integer(a);
writer.print(" Thread["+Thread.currentThread().getName()+"]" + ":"+ a);
writer.print(" ============="+Thread.currentThread().getName()+"=======================>>>>> ");
if(list.contains(temp)) {
System.out.println("repeat number"+temp);
Iterator<Integer> iter=list.iterator();
while(iter.hasNext()) {
System.out.print(iter.next()+" ");
}
System.exit(0);
}else {
list.add(temp);
}
writer.println(" "+temp+"\n");
return a;
}
}
我可能是错的,但我认为你需要包围
//critical section
a= increment(a);
//end
使用同步块并像这样引入锁对象:
private static final Object LOCK = new Object();
@Override
public void run() {
while (true) {
synchronized (LOCK) {
if(a<1000){
//critical section
a = increment(a);
//end
}else{
break;
}
}
}
}
你还需要检查同步块内部的条件,否则你会得到大于 1000 的数字。
编辑。之前的回答不正确。
不好意思这个愚蠢的问题,我最近学习了对象监视器,最后通过对象上的同步解决了ti