序列号添加不同步

serial number add not synchronized

我不知道放在哪里我能想象"synchronized",但它仍然是线程不安全,帮助,非常感谢!多线程竞争添加一个序列号'a'。应该线程Demo的运行方法可以同步吗?不管怎样,我把它加到"public void run()"一个synchronized,它仍然显示一个不安全的消息。

package Whosebug;

import java.util.ArrayList;
import java.util.List;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;

public class NumberEx {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        ExecutorService service=Executors.newCachedThreadPool();
        for(int i=0;i<10;i++) {
            service.execute(new ThreadDemo());
        }
        service.shutdown();

    }
}


package Whosebug;

import java.io.FileNotFoundException;
import java.io.PrintWriter;
import java.util.ArrayList;
import java.util.Iterator;
import java.util.List;
import java.util.concurrent.atomic.AtomicInteger;

public class ThreadDemo implements Runnable  {
    private static volatile int a = 0;
    private static volatile List<Integer> list=new ArrayList<Integer>();
    static PrintWriter writer;
    static {
        try {
            writer=new PrintWriter("./src/out.txt");
        } catch (FileNotFoundException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }

    @Override
    public void run()  {

         while (a< 1000) {
                //critical section
                a= increment(a);
                //end
         }
            writer.close();

    }

    private static synchronized int increment(int a)  {

        writer.print("<<<<============"+Thread.currentThread().getName()+"========================     ");

        a=a+1;
        Integer temp=new Integer(a);

       writer.print(" Thread["+Thread.currentThread().getName()+"]" + ":"+ a);
       writer.print("      ============="+Thread.currentThread().getName()+"=======================>>>>>    "); 
        if(list.contains(temp)) {
            System.out.println("repeat number"+temp);
            Iterator<Integer> iter=list.iterator();
            while(iter.hasNext()) {
                System.out.print(iter.next()+" ");
            }
            System.exit(0);
        }else {
            list.add(temp);
        }
       writer.println(" "+temp+"\n");

        return a;
    } 

}

我可能是错的,但我认为你需要包围

//critical section
a= increment(a);
 //end

使用同步块并像这样引入锁对象:

private static final Object LOCK = new Object();

@Override
public void run() {

    while (true) {
        synchronized (LOCK) {
            if(a<1000){
                //critical section
                a = increment(a);
                //end
            }else{
                break;
            }
        }
    }
}

你还需要检查同步块内部的条件,否则你会得到大于 1000 的数字。

编辑。之前的回答不正确。

不好意思这个愚蠢的问题,我最近学习了对象监视器,最后通过对象上的同步解决了ti