如何通过 peewee 中的 ForeignKeyField 从 child 调用 parent 方法?
How to call a parent method from a child via ForeignKeyField in peewee?
我有两个类:
class A(Base_Model):
def ping(self):
print("Ping!")
class B(Base_Model):
__A_reference = peewee.ForeignKeyField(A, null=True)
def test_ping(self):
self.__A_reference.ping()
我初始化数据库,创建两个表并尝试 运行 B.test_ping()
,但无济于事。
曾尝试将我指定外键的方式更改为 self-referencing __A_reference = peewee.ForeignKeyField("self", null=True, backref="Bs")
,但还是没有用。
尝试查看一堆代码示例,但似乎从来没有拥有外键的 (child) object 实际上使用它从parent object.
我不明白为什么这令人困惑...访问 B.__A_reference 将 return 相关的 A 实例:
In [1]: from peewee import *
In [2]: db = SqliteDatabase(':memory:')
In [3]: class A(Model):
...: def ping(self):
...: print('ping')
...: class Meta:
...: database = db
...:
In [4]: class B(Model):
...: a = ForeignKeyField(A)
...: class Meta:
...: database = db
...:
In [5]: db.create_tables([A, B])
In [6]: a = A.create()
In [7]: b = B.create(a=a)
In [8]: b.a.ping()
ping
我有两个类:
class A(Base_Model):
def ping(self):
print("Ping!")
class B(Base_Model):
__A_reference = peewee.ForeignKeyField(A, null=True)
def test_ping(self):
self.__A_reference.ping()
我初始化数据库,创建两个表并尝试 运行 B.test_ping()
,但无济于事。
曾尝试将我指定外键的方式更改为 self-referencing __A_reference = peewee.ForeignKeyField("self", null=True, backref="Bs")
,但还是没有用。
尝试查看一堆代码示例,但似乎从来没有拥有外键的 (child) object 实际上使用它从parent object.
我不明白为什么这令人困惑...访问 B.__A_reference 将 return 相关的 A 实例:
In [1]: from peewee import *
In [2]: db = SqliteDatabase(':memory:')
In [3]: class A(Model):
...: def ping(self):
...: print('ping')
...: class Meta:
...: database = db
...:
In [4]: class B(Model):
...: a = ForeignKeyField(A)
...: class Meta:
...: database = db
...:
In [5]: db.create_tables([A, B])
In [6]: a = A.create()
In [7]: b = B.create(a=a)
In [8]: b.a.ping()
ping