PyQt5 QThread 不工作，gui 仍然冻结
PyQt5 QThread not working, gui still freezing
我有这个代码（如果你有pyqt5，你应该可以运行自己）：
import sys
import time
from PyQt5.QtWidgets import QApplication, QPushButton, QVBoxLayout, QWidget
from PyQt5.QtCore import QObject, QThread, pyqtSignal, pyqtSlot
class Worker(QObject):
def __init__(self):
super().__init__()
self.thread = None
class Tab(QObject):
def __init__(self, _main):
super().__init__()
self._main = _main
class WorkerOne(Worker):
finished = pyqtSignal()
def __init__(self):
super().__init__()
@pyqtSlot(str)
def print_name(self, name):
for _ in range(100):
print("Hello there, {0}!".format(name))
time.sleep(1)
self.finished.emit()
self.thread.quit()
class SomeTabController(Tab):
def __init__(self, _main):
super().__init__(_main)
self.threads = {}
self._main.button_start_thread.clicked.connect(self.start_thread)
# Workers
self.worker1 = WorkerOne()
#self.worker2 = WorkerTwo()
#self.worker3 = WorkerThree()
#self.worker4 = WorkerFour()
def _threaded_call(self, worker, fn, *args, signals=None, slots=None):
thread = QThread()
thread.setObjectName('thread_' + worker.__class__.__name__)
# store because garbage collection
self.threads[worker] = thread
# give worker thread so it can be quit()
worker.thread = thread
# objects stay on threads after thread.quit()
# need to move back to main thread to recycle the same Worker.
# Error is thrown about Worker having thread (0x0) if you don't do this
worker.moveToThread(QThread.currentThread())
# move to newly created thread
worker.moveToThread(thread)
# Can now apply cross-thread signals/slots
#worker.signals.connect(self.slots)
if signals:
for signal, slot in signals.items():
try:
signal.disconnect()
except TypeError: # Signal has no slots to disconnect
pass
signal.connect(slot)
#self.signals.connect(worker.slots)
if slots:
for slot, signal in slots.items():
try:
signal.disconnect()
except TypeError: # Signal has no slots to disconnect
pass
signal.connect(slot)
thread.started.connect(lambda: fn(*args)) # fn needs to be slot
thread.start()
@pyqtSlot()
def _receive_signal(self):
print("Signal received.")
@pyqtSlot(bool)
def start_thread(self):
name = "Bob"
signals = {self.worker1.finished: self._receive_signal}
self._threaded_call(self.worker1, self.worker1.print_name, name,
signals=signals)
class MainWindow(QWidget):
def __init__(self):
super().__init__()
self.setWindowTitle("Thread Example")
form_layout = QVBoxLayout()
self.setLayout(form_layout)
self.resize(400, 400)
self.button_start_thread = QPushButton()
self.button_start_thread.setText("Start thread.")
form_layout.addWidget(self.button_start_thread)
self.controller = SomeTabController(self)
if __name__ == '__main__':
app = QApplication(sys.argv)
_main = MainWindow()
_main.show()
sys.exit(app.exec_())
但是 WorkerOne 仍然阻塞我的 GUI 线程，并且当 WorkerOne.print_name 为 运行ning 时 window 没有响应。
我最近对 QThreads 进行了大量研究，但根据我所做的研究，我不确定为什么它不起作用。
什么给了？
问题是由与 lambda 方法的连接引起的，因为此 lambda 不是 Worker 的一部分，因此它不会 运行 在新线程上。解决方案是使用 functools.partial:
from functools import partial
...
thread.started.connect(partial(fn, *args))
完整代码：
import sys
import time
from functools import partial
from PyQt5.QtWidgets import QApplication, QPushButton, QVBoxLayout, QWidget
from PyQt5.QtCore import QObject, QThread, pyqtSignal, pyqtSlot
class Worker(QObject):
def __init__(self):
super().__init__()
self.thread = None
class Tab(QObject):
def __init__(self, _main):
super().__init__()
self._main = _main
class WorkerOne(Worker):
finished = pyqtSignal()
def __init__(self):
super().__init__()
@pyqtSlot(str)
def print_name(self, name):
for _ in range(100):
print("Hello there, {0}!".format(name))
time.sleep(1)
self.finished.emit()
self.thread.quit()
class SomeTabController(Tab):
def __init__(self, _main):
super().__init__(_main)
self.threads = {}
self._main.button_start_thread.clicked.connect(self.start_thread)
# Workers
self.worker1 = WorkerOne()
#self.worker2 = WorkerTwo()
#self.worker3 = WorkerThree()
#self.worker4 = WorkerFour()
def _threaded_call(self, worker, fn, *args, signals=None, slots=None):
thread = QThread()
thread.setObjectName('thread_' + worker.__class__.__name__)
# store because garbage collection
self.threads[worker] = thread
# give worker thread so it can be quit()
worker.thread = thread
# objects stay on threads after thread.quit()
# need to move back to main thread to recycle the same Worker.
# Error is thrown about Worker having thread (0x0) if you don't do this
worker.moveToThread(QThread.currentThread())
# move to newly created thread
worker.moveToThread(thread)
# Can now apply cross-thread signals/slots
#worker.signals.connect(self.slots)
if signals:
for signal, slot in signals.items():
try:
signal.disconnect()
except TypeError: # Signal has no slots to disconnect
pass
signal.connect(slot)
#self.signals.connect(worker.slots)
if slots:
for slot, signal in slots.items():
try:
signal.disconnect()
except TypeError: # Signal has no slots to disconnect
pass
signal.connect(slot)
thread.started.connect(partial(fn, *args)) # fn needs to be slot
thread.start()
@pyqtSlot()
def _receive_signal(self):
print("Signal received.")
@pyqtSlot(bool)
def start_thread(self):
name = "Bob"
signals = {self.worker1.finished: self._receive_signal}
self._threaded_call(self.worker1, self.worker1.print_name, name,
signals=signals)
class MainWindow(QWidget):
def __init__(self):
super().__init__()
self.setWindowTitle("Thread Example")
form_layout = QVBoxLayout()
self.setLayout(form_layout)
self.resize(400, 400)
self.button_start_thread = QPushButton()
self.button_start_thread.setText("Start thread.")
form_layout.addWidget(self.button_start_thread)
self.controller = SomeTabController(self)
if __name__ == '__main__':
app = QApplication(sys.argv)
_main = MainWindow()
_main.show()
sys.exit(app.exec_())
为了避免阻塞显示图像的幻灯片功能的 gui 运行 以下内容
简单的代码。
一个后台线程Class等待一秒，然后向gui发出等待完成的信号。
class Waiter(QThread):
result = pyqtSignal(object)
def __init__(self):
QtCore.QThread.__init__(self)
def run(self):
while self.isRunning:
self.sleep(1)
self.result.emit("waited for 1s")
然后在 main window 中将幻灯片开始和停止按钮连接到主应用程序的启动和停止方法，并将 nextImage 函数连接到 Waiter Thread 发出的信号。
self.actionstopSlideShow.triggered.connect(self.stopSlideShow)
self.actionslideShowStart.triggered.connect(self.startSlideShow)
self.waitthread = Waiter()
self.waitthread.result.connect(self.nextImage)
然后主应用程序的两个方法允许启动和停止计时器
def startSlideShow(self):
"""Start background thread that waits one second,
on wait result trigger next image
use thread otherwise gui freezes and stop button cannot be pressed
"""
self.waitthread.start()
def stopSlideShow(self):
self.waitthread.terminate()
self.waitthread.wait()
到目前为止，我在 pyqt5 中从 QThread 子类化没有问题，gui 更改都在主 (gui) 线程内处理。
我有这个代码（如果你有pyqt5，你应该可以运行自己）：
import sys
import time
from PyQt5.QtWidgets import QApplication, QPushButton, QVBoxLayout, QWidget
from PyQt5.QtCore import QObject, QThread, pyqtSignal, pyqtSlot
class Worker(QObject):
def __init__(self):
super().__init__()
self.thread = None
class Tab(QObject):
def __init__(self, _main):
super().__init__()
self._main = _main
class WorkerOne(Worker):
finished = pyqtSignal()
def __init__(self):
super().__init__()
@pyqtSlot(str)
def print_name(self, name):
for _ in range(100):
print("Hello there, {0}!".format(name))
time.sleep(1)
self.finished.emit()
self.thread.quit()
class SomeTabController(Tab):
def __init__(self, _main):
super().__init__(_main)
self.threads = {}
self._main.button_start_thread.clicked.connect(self.start_thread)
# Workers
self.worker1 = WorkerOne()
#self.worker2 = WorkerTwo()
#self.worker3 = WorkerThree()
#self.worker4 = WorkerFour()
def _threaded_call(self, worker, fn, *args, signals=None, slots=None):
thread = QThread()
thread.setObjectName('thread_' + worker.__class__.__name__)
# store because garbage collection
self.threads[worker] = thread
# give worker thread so it can be quit()
worker.thread = thread
# objects stay on threads after thread.quit()
# need to move back to main thread to recycle the same Worker.
# Error is thrown about Worker having thread (0x0) if you don't do this
worker.moveToThread(QThread.currentThread())
# move to newly created thread
worker.moveToThread(thread)
# Can now apply cross-thread signals/slots
#worker.signals.connect(self.slots)
if signals:
for signal, slot in signals.items():
try:
signal.disconnect()
except TypeError: # Signal has no slots to disconnect
pass
signal.connect(slot)
#self.signals.connect(worker.slots)
if slots:
for slot, signal in slots.items():
try:
signal.disconnect()
except TypeError: # Signal has no slots to disconnect
pass
signal.connect(slot)
thread.started.connect(lambda: fn(*args)) # fn needs to be slot
thread.start()
@pyqtSlot()
def _receive_signal(self):
print("Signal received.")
@pyqtSlot(bool)
def start_thread(self):
name = "Bob"
signals = {self.worker1.finished: self._receive_signal}
self._threaded_call(self.worker1, self.worker1.print_name, name,
signals=signals)
class MainWindow(QWidget):
def __init__(self):
super().__init__()
self.setWindowTitle("Thread Example")
form_layout = QVBoxLayout()
self.setLayout(form_layout)
self.resize(400, 400)
self.button_start_thread = QPushButton()
self.button_start_thread.setText("Start thread.")
form_layout.addWidget(self.button_start_thread)
self.controller = SomeTabController(self)
if __name__ == '__main__':
app = QApplication(sys.argv)
_main = MainWindow()
_main.show()
sys.exit(app.exec_())
但是 WorkerOne 仍然阻塞我的 GUI 线程，并且当 WorkerOne.print_name 为 运行ning 时 window 没有响应。
我最近对 QThreads 进行了大量研究，但根据我所做的研究，我不确定为什么它不起作用。
什么给了？
问题是由与 lambda 方法的连接引起的，因为此 lambda 不是 Worker 的一部分，因此它不会 运行 在新线程上。解决方案是使用 functools.partial:
from functools import partial
...
thread.started.connect(partial(fn, *args))
完整代码：
import sys
import time
from functools import partial
from PyQt5.QtWidgets import QApplication, QPushButton, QVBoxLayout, QWidget
from PyQt5.QtCore import QObject, QThread, pyqtSignal, pyqtSlot
class Worker(QObject):
def __init__(self):
super().__init__()
self.thread = None
class Tab(QObject):
def __init__(self, _main):
super().__init__()
self._main = _main
class WorkerOne(Worker):
finished = pyqtSignal()
def __init__(self):
super().__init__()
@pyqtSlot(str)
def print_name(self, name):
for _ in range(100):
print("Hello there, {0}!".format(name))
time.sleep(1)
self.finished.emit()
self.thread.quit()
class SomeTabController(Tab):
def __init__(self, _main):
super().__init__(_main)
self.threads = {}
self._main.button_start_thread.clicked.connect(self.start_thread)
# Workers
self.worker1 = WorkerOne()
#self.worker2 = WorkerTwo()
#self.worker3 = WorkerThree()
#self.worker4 = WorkerFour()
def _threaded_call(self, worker, fn, *args, signals=None, slots=None):
thread = QThread()
thread.setObjectName('thread_' + worker.__class__.__name__)
# store because garbage collection
self.threads[worker] = thread
# give worker thread so it can be quit()
worker.thread = thread
# objects stay on threads after thread.quit()
# need to move back to main thread to recycle the same Worker.
# Error is thrown about Worker having thread (0x0) if you don't do this
worker.moveToThread(QThread.currentThread())
# move to newly created thread
worker.moveToThread(thread)
# Can now apply cross-thread signals/slots
#worker.signals.connect(self.slots)
if signals:
for signal, slot in signals.items():
try:
signal.disconnect()
except TypeError: # Signal has no slots to disconnect
pass
signal.connect(slot)
#self.signals.connect(worker.slots)
if slots:
for slot, signal in slots.items():
try:
signal.disconnect()
except TypeError: # Signal has no slots to disconnect
pass
signal.connect(slot)
thread.started.connect(partial(fn, *args)) # fn needs to be slot
thread.start()
@pyqtSlot()
def _receive_signal(self):
print("Signal received.")
@pyqtSlot(bool)
def start_thread(self):
name = "Bob"
signals = {self.worker1.finished: self._receive_signal}
self._threaded_call(self.worker1, self.worker1.print_name, name,
signals=signals)
class MainWindow(QWidget):
def __init__(self):
super().__init__()
self.setWindowTitle("Thread Example")
form_layout = QVBoxLayout()
self.setLayout(form_layout)
self.resize(400, 400)
self.button_start_thread = QPushButton()
self.button_start_thread.setText("Start thread.")
form_layout.addWidget(self.button_start_thread)
self.controller = SomeTabController(self)
if __name__ == '__main__':
app = QApplication(sys.argv)
_main = MainWindow()
_main.show()
sys.exit(app.exec_())
为了避免阻塞显示图像的幻灯片功能的 gui 运行 以下内容 简单的代码。
一个后台线程Class等待一秒，然后向gui发出等待完成的信号。
class Waiter(QThread):
result = pyqtSignal(object)
def __init__(self):
QtCore.QThread.__init__(self)
def run(self):
while self.isRunning:
self.sleep(1)
self.result.emit("waited for 1s")
然后在 main window 中将幻灯片开始和停止按钮连接到主应用程序的启动和停止方法，并将 nextImage 函数连接到 Waiter Thread 发出的信号。
self.actionstopSlideShow.triggered.connect(self.stopSlideShow)
self.actionslideShowStart.triggered.connect(self.startSlideShow)
self.waitthread = Waiter()
self.waitthread.result.connect(self.nextImage)
然后主应用程序的两个方法允许启动和停止计时器
def startSlideShow(self):
"""Start background thread that waits one second,
on wait result trigger next image
use thread otherwise gui freezes and stop button cannot be pressed
"""
self.waitthread.start()
def stopSlideShow(self):
self.waitthread.terminate()
self.waitthread.wait()
到目前为止，我在 pyqt5 中从 QThread 子类化没有问题，gui 更改都在主 (gui) 线程内处理。