从 string/Json url 获取数据

Question

所以我想在这个 URL 中获取纬度和经度（lat 和 lgn），它看起来就像一个 Json 文件但是每当我尝试使用 JsonConvert.DeserializeObject 我得到一个错误...

这是我的代码：

using (WebClient webClient = new System.Net.WebClient())
{
    Console.WriteLine("Boucle");
    WebClient n = new WebClient();
    var json = n.DownloadString(url);
    string valueOriginal = Convert.ToString(json);
    dynamic GPS = JsonConvert.DeserializeObject<Geocoding>(json);
    Console.WriteLine($"{GPS.results}");
}

这是我的 class：

public class Geocoding
{
    public class Rootobject
    {
        public Result[] results { get; set; }
        public string status { get; set; }
    }

    public class Result
    {
        public Address_Components[] address_components { get; set; }
        public string formatted_address { get; set; }
        public Geometry geometry { get; set; }
        public string place_id { get; set; }
        public string[] types { get; set; }
    }

    public class Geometry
    {
        public Location location { get; set; }
        public string location_type { get; set; }
        public Viewport viewport { get; set; }
    }

    public class Location
    {
        public double lat { get; set; }
        public double lng { get; set; }
    }

    public class Viewport
    {
        public Northeast northeast { get; set; }
        public Southwest southwest { get; set; }
    }

    public class Northeast
    {
        public double lat { get; set; }
        public double lng { get; set; }
    }

    public class Southwest
    {
        public double lat { get; set; }
        public  double lng { get; set; }
    }

    public class Address_Components
    {
        public string long_name { get; set; }
        public string short_name { get; set; }
        public string[] types { get; set; }
    }

}

Json 文件 URL 如下所示：

{
    "results" : [
      {
         "address_components" : [
            {
               "long_name" : "41",
               "short_name" : "41",
               "types" : [ "street_number" ]
            },
            {
               "long_name" : "Boulevard Vauban",
               "short_name" : "Boulevard Vauban",
               "types" : [ "route" ]
            },
            {
               "long_name" : "Lille",
               "short_name" : "Lille",
               "types" : [ "locality", "political" ]
            },
            {
               "long_name" : "Nord",
               "short_name" : "Nord",
               "types" : [ "administrative_area_level_2", "political" ]
            },
            {
               "long_name" : "Hauts-de-France",
               "short_name" : "Hauts-de-France",
               "types" : [ "administrative_area_level_1", "political" ]
            },
            {
               "long_name" : "France",
               "short_name" : "FR",
               "types" : [ "country", "political" ]
            },
            {
               "long_name" : "59800",
               "short_name" : "59800",
               "types" : [ "postal_code" ]
            }
         ],
         "formatted_address" : "41 Boulevard Vauban, 59800 Lille, France",
         "geometry" : {
            "location" : {
               "lat" : 50.6341809,
               "lng" : 3.0487116
            },
            "location_type" : "ROOFTOP",
            "viewport" : {
               "northeast" : {
                  "lat" : 50.63552988029151,
                  "lng" : 3.050060580291502
               },
               "southwest" : {
                  "lat" : 50.63283191970851,
                  "lng" : 3.047362619708498
               }
            }
         },
         "place_id" : "ChIJfZ8S2njVwkcRmcb0tz_XNNE",
         "types" : [ "establishment", "point_of_interest", "university" ]
      }
   ],
   "status" : "OK"
}

我收到错误："Microsoft.CSharp.RuntimeBinder.RuntimeBinderException : ''GeocodingApi.Geocoding' doesn't have definition for 'results''"。我尝试了从删除 <Geocoding> 到保留它的所有方法...

Answer 1

删除 RootObject class 定义并将其成员折叠到地理编码中。您的 class 结构与 JSON 文件不匹配。或者，您可以将字符串反序列化为 "RootObject" 而不是 "Geocoding"

Answer 2

您正在尝试反序列化为嵌套 class。您可以删除外部 class 并直接使用 Rootobject class 或使用完整命名空间进行反序列化：

Geocoding.Rootobject GPS = JsonConvert.DeserializeObject<Geocoding.Rootobject>(json);

注意变量是同一类型而不是 dynamic，很少有不使用正确类型的好用例。

从 string/Json url 获取数据

Get data from a string/Json url

c#

json

geocoding