条件语句语法
Conditional Statement Syntax
我现在正在写一个网络爬虫,我的 Python 已经生锈了,所以我只是想知道是否有更短的语法来完成以下...
def parse(self, response):
prc_path = '//span[@class="result-meta"]/span[@class="result-price"]/text()'
sqf_path = '//span[@class="result-meta"]/span[@class="housing"]/text()'
loc_path = '//span[@class="result-meta"]/span[@class="result-hood"]/text()'
prc_resp = response.xpath(prc_path).extract_first()
sqf_resp = response.xpath(sqf_path).extract_first()
loc_resp = response.xpath(loc_path).extract_first()
if sqf_resp and loc_resp:
yield {
'prc': response.xpath(prc_path).extract_first(),
'sqf': response.xpath(sqf_path).extract_first(),
'loc': response.xpath(loc_path).extract_first()
}
elif sqf_resp:
yield {
'prc': response.xpath(prc_path).extract_first(),
'sqf': response.xpath(sqf_path).extract_first()
}
else:
yield {
'prc': response.xpath(prc_path).extract_first(),
'loc': response.xpath(loc_path).extract_first()
}
如您所见,有相当多的重复,我希望尽可能保持干燥。
您可以创建字典,然后向其中添加适当的条目。
result = { 'prc': response.xpath(prc_path).extract_first() }
if sqf_path:
result['sqf'] = response.xpath(sqf_path).extract_first()
if loc_path:
result['loc'] = response.xpath(loc_path).extract_first()
yield result
您还可以通过字典理解分解出 extract_path
位。
result = { 'prc': prc_path, 'sqf': sqf_path, 'loc': loc_path }
yield { key : response.xpath(value).extract_first()
for (key, value) in result.items() if value }
在 Python 的早期版本中,这将是:
result = { 'prc': prc_path, 'sqf': sqf_path, 'loc': loc_path }
yield dict((key, response.xpath(value).extract_first())
for (key, value) in result.items() if value)
我会使用查找地图:
def parse(self, response):
# initialize your prc_path/sqf_path/loc_path here
lookup_map = {"prc": prc_path, "sqf": sqf_path, "loc": loc_path} # add as many as needed
return {k: response.xpath(v).extract_first() for k, v in lookup_map.items() if v}
我现在正在写一个网络爬虫,我的 Python 已经生锈了,所以我只是想知道是否有更短的语法来完成以下...
def parse(self, response):
prc_path = '//span[@class="result-meta"]/span[@class="result-price"]/text()'
sqf_path = '//span[@class="result-meta"]/span[@class="housing"]/text()'
loc_path = '//span[@class="result-meta"]/span[@class="result-hood"]/text()'
prc_resp = response.xpath(prc_path).extract_first()
sqf_resp = response.xpath(sqf_path).extract_first()
loc_resp = response.xpath(loc_path).extract_first()
if sqf_resp and loc_resp:
yield {
'prc': response.xpath(prc_path).extract_first(),
'sqf': response.xpath(sqf_path).extract_first(),
'loc': response.xpath(loc_path).extract_first()
}
elif sqf_resp:
yield {
'prc': response.xpath(prc_path).extract_first(),
'sqf': response.xpath(sqf_path).extract_first()
}
else:
yield {
'prc': response.xpath(prc_path).extract_first(),
'loc': response.xpath(loc_path).extract_first()
}
如您所见,有相当多的重复,我希望尽可能保持干燥。
您可以创建字典,然后向其中添加适当的条目。
result = { 'prc': response.xpath(prc_path).extract_first() }
if sqf_path:
result['sqf'] = response.xpath(sqf_path).extract_first()
if loc_path:
result['loc'] = response.xpath(loc_path).extract_first()
yield result
您还可以通过字典理解分解出 extract_path
位。
result = { 'prc': prc_path, 'sqf': sqf_path, 'loc': loc_path }
yield { key : response.xpath(value).extract_first()
for (key, value) in result.items() if value }
在 Python 的早期版本中,这将是:
result = { 'prc': prc_path, 'sqf': sqf_path, 'loc': loc_path }
yield dict((key, response.xpath(value).extract_first())
for (key, value) in result.items() if value)
我会使用查找地图:
def parse(self, response):
# initialize your prc_path/sqf_path/loc_path here
lookup_map = {"prc": prc_path, "sqf": sqf_path, "loc": loc_path} # add as many as needed
return {k: response.xpath(v).extract_first() for k, v in lookup_map.items() if v}