如何在空手道中用键传递 SOAP header

Question

我想用空手道调用以下请求：

http://testsample.com/test?request=<REQUESTS>
<REQUEST TYPE="createClientAccount" REF_NUM="A1">
<CRM_ID>ABC_123</CRM_ID>
<CRM_SYSTEM_ID>abc</CRM_SYSTEM_ID>       
<AUTO_APPROVE>TRUE</AUTO_APPROVE>
</REQUEST>
</REQUESTS>

我尝试了以下选项，但没有用，有人可以告诉我这里有什么问题吗？

Given url 'http://testsample.com/test'
And request
"""
<REQUESTS>
<REQUEST TYPE="createClientAccount" REF_NUM="A1">
<CRM_ID>ABC_123</CRM_ID>
<CRM_SYSTEM_ID>abc</CRM_SYSTEM_ID>       
<AUTO_APPROVE>TRUE</AUTO_APPROVE>
</REQUEST>
</REQUESTS>
"""
And header Content-Type = 'application/soap+xml'
When method post
Then status 200

Answer 1

糟糕，这看起来设计得很糟糕 API。您确定要将 XML 作为 URL 的一部分发送吗？然后这样做：

* string xml = <REQUESTS><REQUEST TYPE="createClientAccount" REF_NUM="A1"><CRM_ID>ABC_123</CRM_ID><CRM_SYSTEM_ID>abc</CRM_SYSTEM_ID><AUTO_APPROVE>TRUE</AUTO_APPROVE></REQUEST></REQUESTS> 
Given url 'http://testsample.com/test'
And param request = xml
And request ''
When method post

如果您不熟悉 HTTP 和 REST，请寻求他人的帮助。

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