CLion 建议使用 'strtol' 而不是 'scanf'

CLion recommends to use 'strtol' instead of 'scanf'

#include <stdio.h>

int main(int argc, char** argv) {
    int num = 0;

    printf("Input: ");
    scanf("%d", &num); <<<

    printf("%d\n", num);

    return 0;
}

scanf("%d", &num);

Clang-Tidy:'scanf'用于将字符串转换为整数值,但函数不会报转换错误;考虑使用 'strtol' 而不是


我用 CLion 写了一个非常简单的代码,它推荐我 'strtol' 而不是 'scanf'。

但我只使用整数变量,没有字符串。想不通为什么会弹出检查信息

如何修改此代码?

How do I modify this code?

#include <stdio.h>
#include <stdlib.h>
#include <errno.h>
#include <limits.h>

enum { INPUT_SIZE = 30 };

int main () {
    char *ptr;
    long ret;
    char str[INPUT_SIZE];

    fgets(str, INPUT_SIZE, stdin);    
    ret = strtol(str, &ptr, 10);

    if( ret == LONG_MAX || ret == LONG_MIN ) {
        perror("!! Problem is -> ");
    }
    else if (ret) {
        printf("The number is %ld\n", ret);
    }
    else {
        printf("No number found input is -> %s\n", ptr);
    }

    return(0);
}

If successful, strtol() returns the converted long int value.

If unsuccessful, strtol() returns 0 if no conversion could be performed. If the correct value is outside the range of representable values, strtol() returns LONG_MAX or LONG_MIN, according to the sign of the value. If the value of base is not supported, strtol() returns 0.

If unsuccessful strtol() sets errno to one of the following values:

Error Codes:

EINVAL The value of base is not supported.

ERANGE The conversion caused an overflow. Source : IBM

你可以使用 scanf() 来检查溢出吗?

Input:  1234 Whosebug
Output: The number is 1234

Input:  123nowhitespace
Output: The number is 123

Input:  number is 123
Output: No number found input is -> number is 123

Input:  between123between
Output: No number found input is -> between23between

Input:  9999999999999999999
Output: !! Problem is -> : Result too large

可能跑题了,但是,Jonathan Leffler 在他的评论(在另一个主题中)中说 像处理错误一样处理警告。