以分钟为单位的两个 DateTime 对象之间的差异

Question

===========================================================
Date_Time_from          | Date_Time_to
===========================================================
2018-06-16 02:00:00     |2018-06-18 02:00:00
2018-06-16 03:00:00     |2018-06-18 03:00:00
2018-06-16 04:00:00     |2018-06-18 04:00:00
2018-06-16 05:00:00     |2018-06-18 05:00:00
2018-06-16 06:00:00     |2018-06-18 06:00:00
==========================================================

我正在使用 LocalDateTime，但它没有得到 2 DateTime 的差值，而是只计算了时间。没有算天数。

代码如下：

LocalDateTime fromdate = LocalDateTime.of(orderYear,orderMonth,orderDay,orderHour,orderMinute,orderSeconds);
LocalDateTime todate = LocalDateTime.of(deliverYear, deliverMonth, deliverDay,deliverHour,deliverMinute,deliverSeconds);
int a = fromdate.get(ChronoField.MINUTE_OF_DAY)-todate.get(ChronoField.MINUTE_OF_DAY);

以上代码的输出为零，因为 date_time_from 中的 2 小时相当于 date_time_to 中的 120 分钟减去 2 小时。

是否有其他方法获取总分钟数并计算日期？

Answer 1

LocalDateTime fromdate = LocalDateTime.of(orderYear,orderMonth,orderDay,orderHour,orderMinute,orderSeconds);
LocalDateTime todate = LocalDateTime.of(deliverYear, deliverMonth, deliverDay,deliverHour,deliverMinute,deliverSeconds);
Duration difference = Duration.between(fromdate, todate);

然后您可以使用类似于...

的格式对其进行格式化

long hours = difference.toHours();
long mins = difference.minusHours(hours).toMinutes();

// Or if you're lucky enough to be using Java 9+
//String formatted = String.format("%dhrs %02dmins", duration.toHours(), duration.toMinutesPart());
String formatted = String.format("%dhrs %02dmins", hours, mins);

只是为了证明这一点...

import java.time.Duration;
import java.time.LocalDateTime;
import java.time.format.DateTimeFormatter;
import java.util.ArrayList;
import java.util.List;
import java.util.Locale;

public class Test {

    public static void main(String[] args) {
        DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss", Locale.ENGLISH);
        List<LocalDateTime> from = new ArrayList<>(5);
        List<LocalDateTime> to = new ArrayList<>(5);

        from.add(LocalDateTime.parse("2018-06-16 02:00:00", formatter));
        from.add(LocalDateTime.parse("2018-06-16 03:00:00", formatter));
        from.add(LocalDateTime.parse("2018-06-16 04:00:00", formatter));
        from.add(LocalDateTime.parse("2018-06-16 05:00:00", formatter));
        from.add(LocalDateTime.parse("2018-06-16 06:00:00", formatter));

        to.add(LocalDateTime.parse("2018-06-18 02:00:00", formatter));
        to.add(LocalDateTime.parse("2018-06-18 03:00:00", formatter));
        to.add(LocalDateTime.parse("2018-06-18 04:00:00", formatter));
        to.add(LocalDateTime.parse("2018-06-18 05:00:00", formatter));
        to.add(LocalDateTime.parse("2018-06-18 06:00:00", formatter));

        for (int index = 0; index < from.size(); index++) {
            LocalDateTime fromDate = from.get(index);
            LocalDateTime toDate = to.get(index);
            String difference = formatDurationBetween(fromDate, toDate);
            System.out.println(fromDate.format(formatter) + " - " + toDate.format(formatter) + " = " + difference);
        }
    }

    public static String formatDurationBetween(LocalDateTime from, LocalDateTime to) {
        Duration difference = Duration.between(from, to);

        long days = difference.toDays();
        difference = difference.minusDays(days);
        long hours = difference.toHours();
        long mins = difference.minusHours(hours).toMinutes();

        return String.format("%dd %dh %02dm", days, hours, mins);
    }

}

输出...

2018-06-16 02:00:00 - 2018-06-18 02:00:00 = 2d 0h 00m
2018-06-16 03:00:00 - 2018-06-18 03:00:00 = 2d 0h 00m
2018-06-16 04:00:00 - 2018-06-18 04:00:00 = 2d 0h 00m
2018-06-16 05:00:00 - 2018-06-18 05:00:00 = 2d 0h 00m
2018-06-16 06:00:00 - 2018-06-18 06:00:00 = 2d 0h 00m

你当然可以根据自己的需要制定自己的格式化算法

Answer 2

这是你要的吗，

LocalDateTime fromDate = LocalDateTime.of(2018, 6, 16, 2, 0, 0);
LocalDateTime toDate = LocalDateTime.of(2018, 6, 18, 2, 0, 0);
long minutes = Duration.between(fromDate, toDate).toMinutes();

更新

根据以下评论，删除了前导零，因为它们容易出错。

Answer 3

I need the output to be in mins only. Thanks

已经有两个很好的答案，所以这只是补充一点，虽然 Duration class 是表示两个日期时间之间差异的最通用和最灵活的方法，但还有一个更简单的方法选项，ChronoUnit.MINUTES:

    LocalDateTime fromdate = LocalDateTime.of(2018, Month.JUNE, 16, 2, 0, 0);
    LocalDateTime todate = LocalDateTime.of(2018, Month.JUNE, 18, 2, 0, 0);
    long diffInMinutes = ChronoUnit.MINUTES.between(fromdate, todate);
    System.out.println(diffInMinutes);

输出是

2880

以分钟为单位的两个 DateTime 对象之间的差异

Difference between two DateTime objects in minutes

java

datetime

localdate