将 JSON 数据解析为 C# 对象

Question

我有 JSON 个包含多个对象数组的文件：

{
    "projects":[{
        "issuetypes":[{
            "fields":{
                "priority":{
                "allowedValues":[{
                    "self":"",
                    "iconUrl":"",
                    "name":"",
                    "id":"1"
                }]
            },
            "components":{
            "allowedValues":[{
                "self":"",
                "id":"",
                "name":""
            }

我尝试将其解析为 C# class。

Google 只有简化版本的反序列化示例 JSON do C# Object.

我现在创造了什么？

public class RootObject
{
    [JsonProperty(PropertyName = "projects")]
    public List<ProjectObject> Projects { get; set; }
}

public class ProjectObject
{
    [JsonProperty(PropertyName = "issueTypes")]
    public List<IssueObject> Issues { get; set; }
}

public class IssueObject
{
    [JsonProperty(PropertyName = "fields")]
    public FieldObject Field { get; set; }
}

public class FieldObject
{
    [JsonProperty(PropertyName = "components")]
    public ComponentObject Component { get; set; }

    [JsonProperty(PropertyName = "priority")]
    public PriorityObject Priority { get; set; }
}

public class PriorityObject
{
    [JsonProperty(PropertyName = "value")]
    public PriorityAllowedValues PriorityValues { get; set; }
}

public class PriorityAllowedValues
{
    public List<PriorityValues> AllowedValues { get; set; }
}

public class PriorityValues
{
    [JsonProperty(PropertyName = "id")]
    public string Id { get; set; }

    [JsonProperty(PropertyName = "self")]
    public string Self { get; set; }
    [JsonProperty(PropertyName = "iconUrl")]
    public string IconUrl { get; set; }
    [JsonProperty(PropertyName = "name")]
    public string Name { get; set; }
}

public class ComponentObject
{
    [JsonProperty(PropertyName = "value")]
    public ComponentAllowedValues ComponentAllowedValues { get; set; }
}

public class ComponentAllowedValues
{
    public List<SelectObject> AllowedValues { get; set; }
}

public class SelectObject
{
    [JsonProperty(PropertyName = "id")]
    public string Id { get; set; }
    [JsonProperty(PropertyName = "self")]
    public string Self { get; set; }
    [JsonProperty(PropertyName = "name")]
    public string Name { get; set; }
}

当我尝试执行这一行时：

RootObject root = JsonConvert.DeserializeObject<RootObject>(data);

来自 JSON 文件的数据应该正确地传送到 RootObject...

Answer 1

有一些工具可以帮助您从 JSON 生成类，例如https://jsonutils.com/ 此结构适用于提供的 json:

public class AllowedValue
{

    [JsonProperty("self")]
    public string Self { get; set; }

    [JsonProperty("iconUrl")]
    public string IconUrl { get; set; }

    [JsonProperty("name")]
    public string Name { get; set; }

    [JsonProperty("id")]
    public string Id { get; set; }
}

public class Priority
{

    [JsonProperty("allowedValues")]
    public IList<AllowedValue> AllowedValues { get; set; }
}

public class AllowedValue
{

    [JsonProperty("self")]
    public string Self { get; set; }

    [JsonProperty("id")]
    public string Id { get; set; }

    [JsonProperty("name")]
    public string Name { get; set; }
}

public class Components
{

    [JsonProperty("allowedValues")]
    public IList<AllowedValue> AllowedValues { get; set; }
}

public class Fields
{

    [JsonProperty("priority")]
    public Priority Priority { get; set; }

    [JsonProperty("components")]
    public Components Components { get; set; }
}

public class Issuetype
{

    [JsonProperty("fields")]
    public Fields Fields { get; set; }
}

public class Project
{

    [JsonProperty("issuetypes")]
    public IList<Issuetype> Issuetypes { get; set; }
}

public class RootObject
{

    [JsonProperty("projects")]
    public IList<Project> Projects { get; set; }
}

将 JSON 数据解析为 C# 对象

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