编码和解码跳过字符

Question

我正在尝试使用它们的编码格式将一些字符串存储到数据库中。但是当取回字符串时，它的格式是错误的。

这是我的代码示例，您可以轻松地看到传递给编码的字符串与解码后的字符串不同。为什么会这样？

有没有其他库可以帮我编解码？对此的任何建议都会有所帮助。

var Base64 = {
 _keyStr : "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=",
 encode : function(e) {
  var t = "";
  var n, r, i, s, o, u, a;
  var f = 0;
  e = Base64._utf8_encode(e);
  while (f < e.length) {
   n = e.charCodeAt(f++);
   r = e.charCodeAt(f++);
   i = e.charCodeAt(f++);
   s = n >> 2;
   o = (n & 3) << 4 | r >> 4;
   u = (r & 15) << 2 | i >> 6;
   a = i & 63;
   if (isNaN(r)) {
    u = a = 64
   } else if (isNaN(i)) {
    a = 64
   }
   t = t + this._keyStr.charAt(s) + this._keyStr.charAt(o)
     + this._keyStr.charAt(u) + this._keyStr.charAt(a)
  }
  return t
 },
 decode : function(e) {
  var t = "";
  var n, r, i;
  var s, o, u, a;
  var f = 0;
  e = e.replace(/[^A-Za-z0-9+/=]/g, "");
  while (f < e.length) {
   s = this._keyStr.indexOf(e.charAt(f++));
   o = this._keyStr.indexOf(e.charAt(f++));
   u = this._keyStr.indexOf(e.charAt(f++));
   a = this._keyStr.indexOf(e.charAt(f++));
   n = s << 2 | o >> 4;
   r = (o & 15) << 4 | u >> 2;
   i = (u & 3) << 6 | a;
   t = t + String.fromCharCode(n);
   if (u != 64) {
    t = t + String.fromCharCode(r)
   }
   if (a != 64) {
    t = t + String.fromCharCode(i)
   }
  }
  t = Base64._utf8_decode(t);
  return t
 },
 _utf8_encode : function(e) {
  e = e.replace(/rn/g, "n");
  var t = "";
  for (var n = 0; n < e.length; n++) {
   var r = e.charCodeAt(n);
   if (r < 128) {
    t += String.fromCharCode(r)
   } else if (r > 127 && r < 2048) {
    t += String.fromCharCode(r >> 6 | 192);
    t += String.fromCharCode(r & 63 | 128)
   } else {
    t += String.fromCharCode(r >> 12 | 224);
    t += String.fromCharCode(r >> 6 & 63 | 128);
    t += String.fromCharCode(r & 63 | 128)
   }
  }
  return t
 },
 _utf8_decode : function(e) {
  var t = "";
  var n = 0;
  var r = c1 = c2 = 0;
  while (n < e.length) {
   r = e.charCodeAt(n);
   if (r < 128) {
    t += String.fromCharCode(r);
    n++
   } else if (r > 191 && r < 224) {
    c2 = e.charCodeAt(n + 1);
    t += String.fromCharCode((r & 31) << 6 | c2 & 63);
    n += 2
   } else {
    c2 = e.charCodeAt(n + 1);
    c3 = e.charCodeAt(n + 2);
    t += String.fromCharCode((r & 15) << 12 | (c2 & 63) << 6 | c3
      & 63);
    n += 3
   }
  }
  return t
 }
}


var str = "background:url(/drona-courses/player_assets/skin_0/DRONA_default_skinRightCorner.png) ;"

var encoded = Base64.encode(str);
//console.log(encoded);

var decoded = Base64.decode(encoded);
console.log(str,"......Input");
console.log(decoded,".....Output");

Answer 1

Base64 Encoding in common browsers

In JavaScript there are two functions respectively for decoding and encoding base64 strings:

atob()

btoa()

The atob() function decodes a string of data which has been encoded using base-64 encoding. Conversely, the btoa() function creates a base-64 encoded ASCII string from a "string" of binary data.

Answer 2

使用atob和btoa。

const foo = "bar"

const encodedFoo = btoa(foo)
const decodedFoo = atob(encodedFoo)

console.log(encodedFoo)
console.log(decodedFoo)

您可以阅读更多相关信息here.

编码和解码跳过字符

Encode and decode skipping the characters

html

javascript

base64

encode

decode