SQL 连续天数 - 甲骨文

Question

[数据]

[Emp] [Emp_group] [Date_purchase]
1      001         12-jan-2016
1      001         13-jan-2016
1      001         19-jan-2016
1      003         14-jan-2016
2      004         21-feb-2016
2      004         22-feb-2016
2      004         23-feb-2016
3      005         01-apr-2016

需要 SQL 来查找连续的购买日期。 emp组(001)的emp(1)已于1月12日及13日连续进货。必须考虑Emp和Emp组划分。

Answer 1

只需使用lag()/lead():

select t.*
from (select t.*,
             lag(date_purchase) over (partition by emp, emp_group order by date_purchase) as prev_dp,
             lead(date_purchase) over (partition by emp, emp_group order by date_purchase) as next_dp
      from t
     ) t
where date_purchase in (prev_dp, next_dp);