我如何在 python 子进程中使用睡眠功能

Question

executor.py

from time import sleep
if __name__ == "__main__"
for i in range(10):
    print(i)
    sleep(1)

starter.py

from subprocess import Popen, PIPE

if __name__ == "__main__"
    process = Popen(['python', 'executor.py'], stdout=PIPE, universal_newlines=True)
    while process.poll() is None:
        output = process.stdout.readline()
        print(output)
    process.wait()

在Shell

python starter.py

命令执行后结果如下 #after 10秒后.... 0 1个 2个 3个 4个 5个 6个 7 8个 9
我要打印每一个 second 我该如何解决这个问题？

Answer 1

缓冲标准输出。您应该在每个 print:

之后刷新缓冲区

from time import sleep
import sys
if __name__ == "__main__":
    for i in range(10):
        print(i)
        sys.stdout.flush()
        sleep(1)