Select满足输入条件的第n行-Oracle数据库-Sqldbx

Question

我对 Oracle 完全陌生。我有一个 table 存储了工作日。我想从满足输入条件的地方获得第 5 个工作日（第 5 行）。例如，请考虑以下 table

 BUSINESS DAY
8/06/2004 12:00:00 AM
8/07/2004 12:00:00 AM
8/08/2004 12:00:00 AM
8/09/2004 12:00:00 AM
8/10/2004 12:00:00 AM
8/13/2004 12:00:00 AM
8/14/2004 12:00:00 AM
8/15/2004 12:00:00 AM
8/16/2004 12:00:00 AM

这里我的输入日期是 8/08/2004 12:00:00 AM 我的输出应该是 8/15/2004 12:00:00 AM。请帮助为此构建查询。请注意，根据要求，我可能还需要过去的日期。

我也提到了其他堆栈流问题和答案。但似乎 none 符合我的问题。

Answer 1

这里有一个选项：排序业务日期（使用 ROW_NUMBER 分析函数），然后对其应用简单的算术（即加 5 天，或减去一些天数）：

SQL> with test (busday) as
  2    (select date '2004-08-06' from dual union
  3     select date '2004-08-07' from dual union
  4     select date '2004-08-08' from dual union
  5     select date '2004-08-09' from dual union
  6     select date '2004-08-10' from dual union
  7     select date '2004-08-13' from dual union
  8     select date '2004-08-14' from dual union
  9     select date '2004-08-15' from dual union
 10     select date '2004-08-16' from dual
 11    ),
 12  inter as
 13    (select busday, row_number() over (order by busday) rn
 14     from test
 15    )
 16  select i.busday
 17  from inter i
 18  where i.rn = (select i1.rn + 5 from inter i1
 19                where i1.busday = date '&par_busday'
 20               );
Enter value for par_busday: 2004-08-08

BUSDAY
----------
2004-08-15

SQL>

Answer 2

演示 table:

create table business_days (busday) as
    select date '2004-08-06' from dual union
    select date '2004-08-07' from dual union
    select date '2004-08-08' from dual union
    select date '2004-08-09' from dual union
    select date '2004-08-10' from dual union
    select date '2004-08-13' from dual union
    select date '2004-08-14' from dual union
    select date '2004-08-15' from dual union
    select date '2004-08-16' from dual;

一种方法：

select busday, t_plus_5
from   ( select busday
              , lead(busday,5) over (order by busday) as t_plus_5
         from   business_days
         where  busday >= date '2004-08-08' )
where   busday = date '2004-08-08';

或者这个（需要 Oracle 12.1 或更高版本）：

select busday
     , ( select d5.busday from business_days d5
         where  d5.busday >= d1.busday
         order by busday
         offset 5 rows fetch first row only ) as t_plus_5
from   business_days d1
where  busday = date '2004-08-08';

Select满足输入条件的第n行-Oracle数据库-Sqldbx

Select nth row from where the input condition is satisfied - Oracle database- Sqldbx

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