group by on union all result SQL 服务器

Question

我是 SQL 服务器的新手。我有一个 SQL 查询，我在其中执行了一个 union all，这 2 个单独的查询有分组依据。

select top 5  
    Starttime, convert(date,row_date) as Date,
    sum(acdcalls + abncalls) [Offered],
    sum(acdcalls) [Handled],
    sum(abncalls) [Abandoned],
    sum(acdcalls1 + acdcalls2 + acdcalls3 + acdcalls4 + acdcalls5) [Answered within SLA],
    case 
        when sum(acdcalls) != 0 
          then cast((sum(acdcalls1 + acdcalls2 + acdcalls3 + acdcalls4 + acdcalls5)) * 1.0 / sum((acdcalls)) * 1.0 * 100 as decimal(10, 2)) 
          else 0 
    end as [SLA in %]
from 
    db1
where 
    row_date = getdate()
group by 
    Starttime, row_Date

union all

select top 5 
    Starttime, convert(date,row_date) as Date,
    sum(acdcalls + abncalls) [Offered],
    sum(acdcalls) [Handled],
    sum(abncalls) [Abandoned],
    sum(acdcalls1 + acdcalls2 + acdcalls3 + acdcalls4 + acdcalls5) [Answered within SLA],
    case 
       when sum(acdcalls) != 0 
         then cast((sum(acdcalls1 + acdcalls2 + acdcalls3 + acdcalls4 + acdcalls5)) * 1.0 / sum((acdcalls)) * 1.0 * 100 as decimal(10, 2)) 
         else 0 
    end as [SLA in %]
from 
    db2
where 
    row_date = getdate()
group by 
    Starttime, row_Date

Starttime 列具有共同的值。我想对结果进行 Starttime 分组。我怎样才能做到这一点？任何帮助将不胜感激

Answer 1

你需要先做并集，再做聚合。以下示例使用子查询，但如果您愿意，可以使用临时 table 代替：

Select StartTime, Row_Date, sum(acdcalls+abncalls)...[other sums here]
  From (
    select * from db1 
    union all
    select * from db2
  ) a
group by StartTime, RowDate

如有必要，您仍然可以在子查询中使用您的 where 子句和您的特定列（上面的示例仅在 db1 和 db2 具有相同顺序的相同列时才有效 - 否则您将需要指定您的列） .不过，如果您将两个选择限制为 Row_Date = GetDate()，我不确定为什么要按 Row_Date 分组。

group by on union all result SQL 服务器

group by on union all result SQL Server

sql

sql-server

group-by

union-all