XML 通过 c# 不接受日期时间值

Question

无法将 datetime.now 值传递给节点 'createddatetime'。输出 xml 文件丢弃节点。我使用了以下代码，

   string PATH = "C:\Samplex.xml";
    CreateEmptyFile(PATH);

    var data = new AutoCount();
    data.Product = "AutoCount Accounting";
    data.Version = "1.5";
    data.CreatedApplication = "BApp";
    data.CreatedBy = "Business Solutions";
    data.CreatedDateTime = DateTime.Now;   /* this line*/
    var serializer = new XmlSerializer(typeof(AutoCount));
    using (var stream = new StreamWriter(PATH))
    serializer.Serialize(stream, data);

输出是：

     <?xml version="1.0" encoding="utf-8"?>
     <AutoCount xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="http://schemas.autocountsoft.com/ac_accounting.xsd">
   <Product>AutoCount Accounting</Product>
    <Version>1.5</Version>
      <CreatedApplication>BApp</CreatedApplication>
       <CreatedBy>Business Solutions</CreatedBy>
    </AutoCount>

而不是：

     <?xml version="1.0" encoding="utf-8"?>
    <AutoCount xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="http://schemas.autocountsoft.com/ac_accounting.xsd">
   <Product>AutoCount Accounting</Product>
    <Version>1.5</Version>
      <CreatedApplication>BApp</CreatedApplication>
       <CreatedBy>Business Solutions</CreatedBy>
       <CreatedDateTime>2015-05-03 18:01:35</CreatedDateTime>
    </AutoCount>

Answer 1

当 xsd.exe 为可选元素（例如带有 minOccurs="0" 的元素）生成 class 定义时，其类型映射到值类型，例如 DateTime，会生成一个额外的属性来表示它的值是否应该被序列化。

在这种情况下 CreatedDateTime 似乎是可选的，因此相关的 CreatedDateTimeSpecified 属性应该设置为 true:

data.CreatedDateTime = DateTime.Now;
data.CreatedDateTimeSpecified = true;

XML 通过 c# 不接受日期时间值

Datetime value not accepted in XML through c#

c#

xml

xsd