SQL ：使用不同的子句 where 两次获取列 table

Question

我尝试使用不同的子句两次在同一 table 中获取同一列：

我的查询：

SELECT 
    * 
FROM
    (SELECT TOP 10 
         CONVERT(DATE, attemptdate) AS Date, 
         Max(currentcount) AS A 
     FROM   
         logintracking 
     INNER JOIN 
         maxuser ON logintracking.loginid = maxuser.loginid 
     INNER JOIN 
         site ON site.siteid = maxuser.defsite 
     WHERE  
         attemptdate BETWEEN @dateDebut AND @dateFin 
         AND logintracking.clientaddr IN ('10.118.254.21', '10.118.254.156') 
     GROUP BY 
         CONVERT(DATE, attemptdate) 
     ORDER BY 
         CONVERT(DATE, attemptdate) ASC
    ) AS T1, 
    (SELECT TOP 10 
         CONVERT(DATE, attemptdate) AS Date, 
         MAX(currentcount) AS B 
     FROM   
         logintracking 
     INNER JOIN 
         maxuser ON logintracking.loginid = maxuser.loginid 
     INNER JOIN 
         site ON site.siteid = maxuser.defsite 
     WHERE  
         attemptdate BETWEEN @dateDebut AND @dateFin 
         AND logintracking.clientaddr = '10.118.254.35' 
     GROUP BY 
         CONVERT(DATE, attemptdate) 
     ORDER BY 
         CONVERT(DATE, attemptdate) ASC) AS T2

结果：

想要的结果：

我的 objective 是两次获取同一列 'max(currentcount)' 并应用不同的 where 子句以便获得名为 (A & B) 的两列，我还需要在中显示日期第一栏，你能帮忙吗？谢谢

Answer 1

由于 A 和 B 之间的唯一区别是 logintracking.clientaddr，您可以将该条件放在 MAX 函数内的 CASE 语句中：

SELECT CONVERT(DATE, attemptdate) AS Date, 
    MAX(CASE WHEN logintracking.clientaddr IN ( '10.118.254.21', '10.118.254.156' ) THEN currentcount END) AS A,
    MAX(CASE WHEN logintracking.clientaddr IN ( '10.118.254.35' ) THEN currentcount END) AS B
FROM logintracking 
    INNER JOIN maxuser 
        ON logintracking.loginid = maxuser.loginid 
    INNER JOIN site 
        ON site.siteid = maxuser.defsite 
WHERE attemptdate BETWEEN @dateDebut AND @dateFin
GROUP BY CONVERT(DATE, attemptdate) 
ORDER BY CONVERT(DATE, attemptdate) ASC

SQL ：使用不同的子句 where 两次获取列 table

SQL : Get Column table twice with differents clause where

sql

tsql

sql-server

where-clause