我如何使用 Doctrine Native Query 通过条件语句的连接计数来排序结果？

Question

我想 select 来自 poll table 的行，并按连接 vote table 的行数或总和对它们进行排序其中 vote.is_current_vote = true.

投票 table 跟踪所有投票，但投票中只计算每个用户的最新投票，标记为 is_current_vote。

我正在努力研究如何使用 Doctrine Query Builder 或 Native Query 来计算投票数 table。

数据库结构如下：

create table if not exists user
(
    id int auto_increment
        primary key,
    username varchar(45) not null,
    slug varchar(45) not null,
    created_at datetime not null,
    updated_at datetime null,
    constraint UNIQ_8D93D649989D9B62
        unique (slug),
    constraint UNIQ_8D93D649F85E0677
        unique (username)
)
collate=utf8_unicode_ci
;

create table if not exists poll
(
    id int auto_increment
        primary key,
    user_id int null,
    question varchar(140) not null,
    slug varchar(140) not null,
    is_active tinyint(1) not null,
    created_at datetime not null,
    updated_at datetime null,
    constraint UNIQ_84BCFA45989D9B62
        unique (slug),
    constraint FK_84BCFA45A76ED395
        foreign key (user_id) references user (id)
)
collate=utf8_unicode_ci
;

create index IDX_84BCFA45A76ED395
    on poll (user_id)
;

create table if not exists vote
(
    id int auto_increment
        primary key,
    poll_id int not null,
    user_id int not null,
    created_at datetime not null,
    is_current_vote tinyint(1) not null,
    constraint FK_5A1085643C947C0F
        foreign key (poll_id) references poll (id),
    constraint FK_5A108564A76ED395
        foreign key (user_id) references user (id),
)
collate=utf8_unicode_ci
;

create index IDX_5A1085643C947C0F
    on vote (poll_id)
;

create index IDX_5A108564A76ED395
    on vote (user_id)
;

我在 MySQL 中使用此查询，它提供了我想要的数据：

select poll.id, poll.slug, poll.question, poll.created_at,
       u.id, u.username, u.slug, u.profile_picture,
       sum(case when v.is_current_vote = true then 1 else 0 end) as total_votes
from poll
       left join user u on poll.user_id = u.id
       left join vote v on poll.id = v.poll_id
group by poll.id
order by total_votes desc

数据应按票数排序，其中 "v.is_current_vote=true"。
示例数据（省略了上面的一些列以便于阅读）：

poll.question, u.username, total_votes  
Is Elvis Alive?, someone, 15  
Is the future bright?, someone_else, 10  
Is this all a dream?, another_user, 5

是否可以在 Symfony/Doctrine QueryBuilder 语句中做类似的事情，或者我是否必须使用 Native SQL？我也不知道该怎么做。如果能提供一些指导，我将不胜感激。

这是我当前的本机 SQL 尝试，我从 poll table 中获取行，但投票和用户都是 null:

/**
 * Class PollRepository
 * @package PollBundle\Repository
 */
class PollRepository extends EntityRepository
{

 /**
     * @return \Doctrine\ORM\NativeQuery
     */
    public function findPopular()
    {
        $rsm = new ResultSetMappingBuilder($this->_em);
        $rsm->addRootEntityFromClassMetadata('PollBundle\Entity\Poll', 'poll');
        $rsm->addJoinedEntityFromClassMetadata('PollBundle\Entity\User', 'u', 'poll', 'user', [
            'id' => 'user_id',
            'slug' => 'user_slug',
            'created_at' => 'user_created_at',
            'updated_at' => 'user_updated_at',
            'is_active' => 'user_is_active',
        ]);
        $rsm->addJoinedEntityFromClassMetadata('PollBundle\Entity\Vote', 'v', 'poll', 'votes', [
            'id' => 'vote_id',
            'user_id' => 'vote_user_id',
            'created_at' => 'vote_created_at',
            'updated_at' => 'vote_updated_at',
        ]);

        $sql = '
            SELECT poll.id, poll.slug, poll.question, poll.created_at,
                   u.id, u.username, u.slug, u.profile_picture,
                   sum(case when v.is_current_vote = true then 1 else 0 end) as total_votes
            from poll
                   left join user u on poll.user_id = u.id
                   left join vote v on poll.id = v.poll_id
            group by poll.id
            order by total_votes desc
        ';

        return $this->_em->createNativeQuery($sql, $rsm)->getResult();
    }
}

Answer 1

您是否尝试过与此查询类似的查询？ Doctrine 几乎可以做 SQL 可以做的所有事情。

$query = $this->createQueryBuilder('p')
   ->select('p.question, u.username, count(v.isCurrentVote) AS votes')
   // joins maybe need change depending on your relations
   ->leftJoin('p.user', 'u')
   ->leftJoin('p.votes', 'v')
   ->groupBy('p.id')
   ->orderBy('votes');
return $query->getQuery()->getResult();

我如何使用 Doctrine Native Query 通过条件语句的连接计数来排序结果？

How can I use Doctrine Native Query to order results by the count of a join with a conditional statement?

mysql

orm

symfony

doctrine-orm

symfony-3.4