如何用clojure读取ByteBuffer中的字节？

Question

(let [buffer (ByteBuffer/allocate 8)
      arr (byte-array 2)]
   (doto buffer
      (.putLong 4)
      (.get arr)))

Answer 1

不是很清楚问题是什么，所以这里有一个阅读和写作的例子来自java.nio.ByteBuffer：

字节数：

user> (let [buf-len 8
            buffer (ByteBuffer/allocate buf-len)
            arr (byte-array 2)]
        (doseq [x (range buf-len)]
          (.put buffer x (byte x)))
        (.get buffer arr 0 (count arr))
        (println "buffer contains"
                 (for [x (range buf-len)]
                   (.get buffer x)))
        (println "arr contains" (vec arr)))
buffer contains (0 1 2 3 4 5 6 7)
arr contains [0 1]
nil

多头：

user> (let [buf-len 8
            buffer (ByteBuffer/allocate buf-len)
            arr (byte-array 2)]
        (.putLong buffer 0 Long/MAX_VALUE)
         (.get buffer arr)
        (println "buffer contains"
                 (for [x (range buf-len)]
                   (.get buffer x)))
        (println "arr contains" (vec arr)))
buffer contains (127 -1 -1 -1 -1 -1 -1 -1)
arr contains [127 -1]
nil

您的原始示例非常接近，它只需要偏移量:

user> (let [buffer (ByteBuffer/allocate 8)
            arr (byte-array 2)]
        (doto buffer
          (.putLong 0 4)
          (.get arr)))
#<HeapByteBuffer java.nio.HeapByteBuffer[pos=2 lim=8 cap=8]>

如何用clojure读取ByteBuffer中的字节？

how to read bytes in ByteBuffer with clojure?

nio

bytebuffer

clojure