[Python][Tkinter] 添加一个标志使标签的前景循环变为红色？
[Python][Tkinter] adding a flag to make the label's foreground turn to red in a loop?
所以我似乎无法弄清楚如何解决我遇到的这个难题。
我有一个简单的脚本，基本上打印出 5 个标签，每个标签打印出 1 个，停顿 2 秒。
我想做的基本上是在 'red' 中突出显示当前 运行 标签，然后当第二个标签打印出来时，第一个标签的前景应该 return 到 'black' 等等。所以基本上最后一个标签应该是红色的，之前的标签应该是黑色的。
基本上，这样做的目的是我有一个用 python 编写的自动化脚本来测试 Android 电视，我想为它制作一个简单的 GUI。我想突出显示当前的测试用例 运行。执行函数（测试用例）后，我希望它变成黑色。
代码如下：
from tkinter import *
from tkinter import ttk
import tkinter.font as tkFont
import time
class SampleTkinterLoop:
def __init__(self, master):
# Initialize master as the Tk() instance
self.master = master
master.title("Loop Tests")
master.geometry("768x480")
# Create main frame as app
self.app = ttk.Frame(root)
self.app.pack(fill="both", expand=True)
# Create a custom font
self.mainFont = tkFont.Font(family="Helvetica", size=12)
# Initialize flags for BG and FG change
self.bgCounter = 0
def test1(self):
x = True # set fgChooser to True to make foreground red
ttk.Label(
self.app, text=f'Test case 1',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont).pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
def test2(self):
x = True # set fgChooser to True to make foreground red
ttk.Label(
self.app, text=f'Test case 2',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont).pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
def test3(self):
x = True # set fgChooser to True to make foreground red
ttk.Label(
self.app, text=f'Test case 3',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont).pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
def test4(self):
x = True # set fgChooser to True to make foreground red
ttk.Label(
self.app, text=f'Test case 4',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont).pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
def test5(self):
x = True # set fgChooser to True to make foreground red
ttk.Label(
self.app, text=f'Test case 5',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont).pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
def repeatIt(self):
for i in range(0, 5):
# self.anotherLoop()
self.test1()
self.test2()
self.test3()
self.test4()
self.test5()
self.reset()
root.update()
time.sleep(1)
print(i)
def bgChooser(self):
# make label background alternate to white and gray for easy reading
if (self.bgCounter % 2) == 0:
return str("#fff")
return str("#ccc")
def fgChooser(self, isActive=False):
# this is where the problem is, can't seem to find a way to make a flag for foreground color of label
if isActive:
return str("#a5120d")
return str("#000")
def reset(self):
'''reset the UI'''
for child in self.app.winfo_children():
child.destroy()
root = Tk()
LoopTest = SampleTkinterLoop(root)
LoopTest.repeatIt()
root.mainloop()
上面的代码使所有标签都变成红色，并没有将之前的标签变成黑色。
您不需要为该任务使用 ttk。这是因为您可以稍后更改标签颜色。
例如：
进口：
from tkinter import * #<-- so you don't have to edit your full code
import tkinter as ttk #<---
import tkinter.font as tkFont
import time
您可以像这样编辑 test1 函数：
x = True
xyz = ttk.Label( #assign to a variable rather than packing <---
self.app, text=f'Test case 1',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont)
xyz.pack() #pack later <---
self.bgCounter += 1
x = False
root.update()
time.sleep(2)
xyz.config(fg="black") #change color after 2 sec <---
这是一个示例代码：
from tkinter import *
import tkinter as ttk
import tkinter.font as tkFont
import time
class SampleTkinterLoop:
def __init__(self, master):
# Initialize master as the Tk() instance
self.master = master
master.title("Loop Tests")
master.geometry("768x480")
# Create main frame as app
self.app = ttk.Frame(root)
self.app.pack(fill="both", expand=True)
# Create a custom font
self.mainFont = tkFont.Font(family="Helvetica", size=12)
# Initialize flags for BG and FG change
self.bgCounter = 0
def test1(self):
x = True # set fgChooser to True to make foreground red
xyz = ttk.Label(
self.app, text=f'Test case 1',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont)
xyz.pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
xyz.config(fg="black")
def test2(self):
x = True # set fgChooser to True to make foreground red
xyz = ttk.Label(
self.app, text=f'Test case 2',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont)
xyz.pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
xyz.config(fg="black")
def test3(self):
x = True # set fgChooser to True to make foreground red
xyz = ttk.Label(
self.app, text=f'Test case 3',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont)
xyz.pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
xyz.config(fg="black")
def test4(self):
x = True # set fgChooser to True to make foreground red
xyz = ttk.Label(
self.app, text=f'Test case 4',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont)
xyz.pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
xyz.config(fg="black")
def test5(self):
x = True # set fgChooser to True to make foreground red
xyz = ttk.Label(
self.app, text=f'Test case 5',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont)
xyz.pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
xyz.config(fg="black")
def repeatIt(self):
for i in range(0, 5):
# self.anotherLoop()
self.test1()
self.test2()
self.test3()
self.test4()
self.test5()
self.reset()
root.update()
time.sleep(1)
print(i)
def bgChooser(self):
# make label background alternate to white and gray for easy reading
if (self.bgCounter % 2) == 0:
return str("#fff")
return str("#ccc")
def fgChooser(self, isActive=False):
# this is where the problem is, can't seem to find a way to make a flag for foreground color of label
if isActive:
return str("#a5120d")
return str("#000")
def reset(self):
'''reset the UI'''
for child in self.app.winfo_children():
child.destroy()
root = Tk()
LoopTest = SampleTkinterLoop(root)
LoopTest.repeatIt()
root.mainloop()
所以我似乎无法弄清楚如何解决我遇到的这个难题。 我有一个简单的脚本，基本上打印出 5 个标签，每个标签打印出 1 个，停顿 2 秒。
我想做的基本上是在 'red' 中突出显示当前 运行 标签，然后当第二个标签打印出来时，第一个标签的前景应该 return 到 'black' 等等。所以基本上最后一个标签应该是红色的，之前的标签应该是黑色的。
基本上，这样做的目的是我有一个用 python 编写的自动化脚本来测试 Android 电视，我想为它制作一个简单的 GUI。我想突出显示当前的测试用例 运行。执行函数（测试用例）后，我希望它变成黑色。
代码如下：
from tkinter import *
from tkinter import ttk
import tkinter.font as tkFont
import time
class SampleTkinterLoop:
def __init__(self, master):
# Initialize master as the Tk() instance
self.master = master
master.title("Loop Tests")
master.geometry("768x480")
# Create main frame as app
self.app = ttk.Frame(root)
self.app.pack(fill="both", expand=True)
# Create a custom font
self.mainFont = tkFont.Font(family="Helvetica", size=12)
# Initialize flags for BG and FG change
self.bgCounter = 0
def test1(self):
x = True # set fgChooser to True to make foreground red
ttk.Label(
self.app, text=f'Test case 1',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont).pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
def test2(self):
x = True # set fgChooser to True to make foreground red
ttk.Label(
self.app, text=f'Test case 2',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont).pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
def test3(self):
x = True # set fgChooser to True to make foreground red
ttk.Label(
self.app, text=f'Test case 3',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont).pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
def test4(self):
x = True # set fgChooser to True to make foreground red
ttk.Label(
self.app, text=f'Test case 4',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont).pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
def test5(self):
x = True # set fgChooser to True to make foreground red
ttk.Label(
self.app, text=f'Test case 5',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont).pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
def repeatIt(self):
for i in range(0, 5):
# self.anotherLoop()
self.test1()
self.test2()
self.test3()
self.test4()
self.test5()
self.reset()
root.update()
time.sleep(1)
print(i)
def bgChooser(self):
# make label background alternate to white and gray for easy reading
if (self.bgCounter % 2) == 0:
return str("#fff")
return str("#ccc")
def fgChooser(self, isActive=False):
# this is where the problem is, can't seem to find a way to make a flag for foreground color of label
if isActive:
return str("#a5120d")
return str("#000")
def reset(self):
'''reset the UI'''
for child in self.app.winfo_children():
child.destroy()
root = Tk()
LoopTest = SampleTkinterLoop(root)
LoopTest.repeatIt()
root.mainloop()
上面的代码使所有标签都变成红色，并没有将之前的标签变成黑色。
您不需要为该任务使用 ttk。这是因为您可以稍后更改标签颜色。
例如：
进口：
from tkinter import * #<-- so you don't have to edit your full code
import tkinter as ttk #<---
import tkinter.font as tkFont
import time
您可以像这样编辑 test1 函数：
x = True
xyz = ttk.Label( #assign to a variable rather than packing <---
self.app, text=f'Test case 1',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont)
xyz.pack() #pack later <---
self.bgCounter += 1
x = False
root.update()
time.sleep(2)
xyz.config(fg="black") #change color after 2 sec <---
这是一个示例代码：
from tkinter import *
import tkinter as ttk
import tkinter.font as tkFont
import time
class SampleTkinterLoop:
def __init__(self, master):
# Initialize master as the Tk() instance
self.master = master
master.title("Loop Tests")
master.geometry("768x480")
# Create main frame as app
self.app = ttk.Frame(root)
self.app.pack(fill="both", expand=True)
# Create a custom font
self.mainFont = tkFont.Font(family="Helvetica", size=12)
# Initialize flags for BG and FG change
self.bgCounter = 0
def test1(self):
x = True # set fgChooser to True to make foreground red
xyz = ttk.Label(
self.app, text=f'Test case 1',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont)
xyz.pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
xyz.config(fg="black")
def test2(self):
x = True # set fgChooser to True to make foreground red
xyz = ttk.Label(
self.app, text=f'Test case 2',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont)
xyz.pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
xyz.config(fg="black")
def test3(self):
x = True # set fgChooser to True to make foreground red
xyz = ttk.Label(
self.app, text=f'Test case 3',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont)
xyz.pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
xyz.config(fg="black")
def test4(self):
x = True # set fgChooser to True to make foreground red
xyz = ttk.Label(
self.app, text=f'Test case 4',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont)
xyz.pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
xyz.config(fg="black")
def test5(self):
x = True # set fgChooser to True to make foreground red
xyz = ttk.Label(
self.app, text=f'Test case 5',
background=self.bgChooser(),
foreground=self.fgChooser(x),
font=self.mainFont)
xyz.pack()
self.bgCounter += 1
x = False # set it back to false to make foreround black
root.update() # allow window to catch up
time.sleep(2)
xyz.config(fg="black")
def repeatIt(self):
for i in range(0, 5):
# self.anotherLoop()
self.test1()
self.test2()
self.test3()
self.test4()
self.test5()
self.reset()
root.update()
time.sleep(1)
print(i)
def bgChooser(self):
# make label background alternate to white and gray for easy reading
if (self.bgCounter % 2) == 0:
return str("#fff")
return str("#ccc")
def fgChooser(self, isActive=False):
# this is where the problem is, can't seem to find a way to make a flag for foreground color of label
if isActive:
return str("#a5120d")
return str("#000")
def reset(self):
'''reset the UI'''
for child in self.app.winfo_children():
child.destroy()
root = Tk()
LoopTest = SampleTkinterLoop(root)
LoopTest.repeatIt()
root.mainloop()