Python IMAPLIB HTML 正文解析

Question

所以基本上我有这个连续运行的脚本，当一封新电子邮件到达收件箱时，主题中包含特定文本，它会从电子邮件中获取信息。我只设法让它从电子邮件中提取主题，但无论我尝试什么，我都无法让它获取电子邮件的正文，我相信电子邮件正文在 HTML 中，所以我尝试使用 BeautifulSoup 来解析正文，但这根本不起作用。请帮忙！！！ :( 这是我目前所拥有的：

import email
import imaplib
from bs4 import BeautifulSoup
import time
import sys

username = 'xxx.xxx@xxx.xx'
password = 'xxxxxx'

mail = imaplib.IMAP4_SSL('imap-mail.outlook.com')
(retcode, capabilities) = mail.login(username, password)
mail.list()

n=0
while True:
    mail.select('inbox')
    (retcode, messages) = mail.search(None, 'UNSEEN', '(SUBJECT "xxxxxxx- 
     ")', '(FROM "xx.xx@xxxx.xx")')
    if retcode == 'OK':
        for num in messages[0].split():
            n=n+1
            print('Processing Email ' + str(n))
            typ, data = mail.fetch(num, '(RFC822)')
            for response_part in data:
                if isinstance(response_part, tuple):
                    original = email.message_from_bytes(response_part[1])
                    print("Subject: " + original['Subject'])
                    typ, data = mail.store(num,'+FLAGS','\Seen')
                    time.sleep(120)

Answer 1

Comment: The "body" returned by imap.fetch are usually bytes, not a string, which throws an exception

更改为：

msg = email.message_from_bytes(body)

Question: I cant get it do get the body of the email

例如：

import email, imaplib

username = 'xxx.xxx@xxx.xx'
password = 'xxxxxx'
imap = imaplib.IMAP4_SSL('imap-mail.outlook.com')
imap.login(username, password)
imap.select("inbox")

resp, items = imap.search(None, "(UNSEEN)")

for n, num in enumerate(items[0].split(), 1):
    resp, data = imap.fetch(num, '(RFC822)')

    body = data[0][1]
    msg = email.message_from_string(body)
    content = msg.get_payload(decode=True)

    print("Message content[{}]:{}".format(n, content))

Python IMAPLIB HTML 正文解析

Python IMAPLIB HTML body parsing

python

imap

imaplib