XmlSerializer 并粘贴 XML 为类

Question

我有一个返回一些 xml 的 Web 服务。没有对应的xsd.

我在 visual studio 中使用选择性粘贴 -> 将 XML 粘贴为类功能来生成类以与 XmlSerializer 一起使用：

当代码执行行时

--> XmlSerializer xmlSerialize = new XmlSerializer(typeof(table)); <--
    table t = (table)xmlSerialize.Deserialize(new StringReader(soapResult));

它抛出异常：

System.InvalidOperationException: 'Unable to generate a temporary class (result=1).
error CS0030: Cannot convert type 'string[]' to 'string'
error CS0029: Cannot implicitly convert type 'string' to 'string[]'

生成的类看起来像这样：

// NOTE: Generated code may require at least .NET Framework 4.5 or .NET Core/Standard 2.0.
    /// <remarks/>
    [System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
    [System.Xml.Serialization.XmlRootAttribute(Namespace = "", IsNullable = false)]
    public partial class table
    {

        private string[] labelField;

        private string[] classnameField;

        private string[] datatypeField;

        private string[][] rowField;


        /// <remarks/>
        [System.Xml.Serialization.XmlArrayItemAttribute("d", IsNullable = false)]
        public string[] label
        {
            get
            {
                return this.labelField;
            }
            set
            {
                this.labelField = value;
            }
        }

        /// <remarks/>
        [System.Xml.Serialization.XmlArrayItemAttribute("d", IsNullable = false)]
        public string[] classname
        {
            get
            {
                return this.classnameField;
            }
            set
            {
                this.classnameField = value;
            }
        }

        /// <remarks/>
        [System.Xml.Serialization.XmlArrayItemAttribute("d", IsNullable = false)]
        public string[] datatype
        {
            get
            {
                return this.datatypeField;
            }
            set
            {
                this.datatypeField = value;
            }
        }

        /// <remarks/>
        [System.Xml.Serialization.XmlArrayItemAttribute("d", typeof(string), IsNullable = true)]
        public string[][] row
        {
            get
            {
                return this.rowField;
            }
            set
            {
                this.rowField = value;
            }
        }
    }

问题出在行字段上，因为其他字段工作正常。如果我改变

[System.Xml.Serialization.XmlArrayItemAttribute("d", typeof(string), IsNullable = true)]

到

[System.Xml.Serialization.XmlArrayItemAttribute("d", typeof(string[]), IsNullable = true)]

错误消失了，但我的对象只有一个空字符串数组。

被反序列化的 XML 数据（为简单起见进行了压缩）如下所示

<?xml version="1.0" encoding="UTF-8"?>
<table>
   <label>
      <d>JobDefinition.SearchName</d>
      <d>Job.JobDefinition</d>
   </label>
   <classname>
      <d>JobDefinition.SearchName</d>
      <d>Job.JobDefinition</d>
   </classname>
   <datatype>
      <d>String</d>
      <d>obj.JobDefinition</d>
   </datatype>
   <row>
      <d>AB_DEFG_QA_RUN</d>
      <d>A_JOB_Run</d>
   </row>
   <row>
      <d>AB_DEFG_QA_RUN</d>
      <d>B_JOB_Run</d>
   </row>
</table>

Answer 1

您的问题看起来与 to 的 Final Update 中描述的问题相同，即 xsd.exe（因此 Paste XML as 类) 无法为包含重复元素的 XML 推断正确的数据模型，此处为 <row> 和 <d>:

<table>
   <row>
      <d>Value of repeating element inside a repeating element.</d>
      <d>Value of repeating element inside a repeating element.</d>
   </row>
   <row>
      <d>Value of repeating element inside a repeating element.</d>
      <d>Value of repeating element inside a repeating element.</d>
   </row>
</table>

该答案中的建议是使用不同的代码生成工具或手动构建类。我将你的 XML 上传到 https://xmltocsharp.azurewebsites.net/，并在合并副本后类，获得了以下数据模型：

[XmlRoot(ElementName = "row")]
public class Row
{
    [XmlElement(ElementName = "d")]
    public List<string> D { get; set; }
}

[XmlRoot(ElementName = "table")]
public class Table
{
    [XmlElement(ElementName = "label")]
    public Row Label { get; set; }
    [XmlElement(ElementName = "classname")]
    public Row Classname { get; set; }
    [XmlElement(ElementName = "datatype")]
    public Row Datatype { get; set; }

    [XmlElement(ElementName = "row")]
    public List<Row> Row { get; set; }
}

使用它我可以成功反序列化和重新序列化您的 XML 而不会丢失数据。备注：

代码生成工具为 Label、Classname、Datatype 和 Row 生成了不同但相同的类。我决定将它们全部合并为一个 Row 类型，并将其用于 Table.

示例 fiddle here.

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