MYSQL SQLSTATE[42000]：语法错误或访问冲突：1064

Question

我有代码但没有本地主机，一个我无法理解的错误帮助 MYSQL 5.7.21 INNODB 代码：

$sql = DB::select('
            SELECT 
                (case when (CAST(to as time) <= CAST("'.$time.'" as time) and 
                            CAST(do as time) >= CAST("'.$time.'" as time) or 
                            (to is null and do is null)) 
                             THEN
                                  1 
                             ELSE
                                  0 
                             END) as working
            FROM 
                franchises
    ');

错误：

SQLSTATE[42000]: Syntax error or access violation: 1064 You have an 
error in your SQL syntax; check the manual that corresponds to your 
MySQL server version for the right syntax to use near 'to as time) <= 
CAST("10:15" as time) and CAST(do as time) >= CAST("10:15" as tim' at
line 2 (SQL:

Answer 1

To 是 MySQL 中的 reserved word，因此您需要将其包含在反引号中：

...case when (CAST(`to` as time)...

MYSQL SQLSTATE[42000]：语法错误或访问冲突：1064

MYSQL SQLSTATE[42000]: Syntax error or access violation: 1064

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