Kodein 构造函数注入 Kodein$NotFoundException

Question

出于某种原因，我无法让构造函数注入与 Kodein 一起工作。

这是重现异常的代码：

import org.kodein.di.Kodein
import org.kodein.di.direct
import org.kodein.di.generic.bind
import org.kodein.di.generic.instance
import org.kodein.di.generic.provider

fun main(args: Array<String>) {
    val kodein = Kodein {
        bind<Test2>() to provider { Test2() }
        bind<Test>() to provider { Test(instance()) }
    }

    val test = kodein.direct.instance<Test>()
}

class Test(val test2: Test2)
class Test2

异常：

Exception in thread "main" org.kodein.di.Kodein$NotFoundException: No binding found for bind<Test>() with ? { ? }
Registered in this Kodein container:

    at org.kodein.di.internal.KodeinContainerImpl.factory(KodeinContainerImpl.kt:174)
    at org.kodein.di.KodeinContainer$DefaultImpls.factory$default(KodeinContainer.kt:33)
    at org.kodein.di.KodeinContainer$DefaultImpls.provider(KodeinContainer.kt:80)
    at org.kodein.di.internal.KodeinContainerImpl.provider(KodeinContainerImpl.kt:7)
    at org.kodein.di.KodeinContainer$DefaultImpls.provider$default(KodeinContainer.kt:79)
    at org.kodein.di.internal.DKodeinBaseImpl.Instance(DKodeinImpl.kt:33)
    at AppKt.main(App.kt:20)

为什么这不起作用？

Answer 1

bind<Test2>() to provider { Test2() }
              ^^

这是 Kotlin 的 to 函数，生成一个 Pair，与 Kodein 的 DSL 无关 :p

Kodein 的 DSL 使用 with:

bind<Test2>() with provider { Test2() }
              ^^^^

请注意，当您将类型绑定到自身时，您可以使用更简单的语法：

bind() from provider { Test2() }

Kodein 构造函数注入 Kodein$NotFoundException

Kodein constructor injecting Kodein$NotFoundException

constructor-injection

kotlin

kodein