如何为所有模板获取相同的信息？

Question

所以在 Django 中，我有一个基本模板，其中包含一些联系方式。但是我生成的每个视图都必须有这条线。

contact = Contact.objects.first()

然后我必须将该对象添加到用模板加载的字典中。

比较好的处理方法是什么？我发现很难相信我正在以正确的方式做这件事。

例子views.py

from django.shortcuts import render
from services.models import Service, ServicesDetail
from .models import Feature, CompanyDetail, TeamMember, TeamDetail, Banner
from contact.models import ContactDetail
import json

# Create your views here.
def home(request):
    services = Service.objects
    try:
        overview = ServicesDetail.objects.first()
    except ServicesDetail.DoesNotExist:
        overview = ''
    try:
        company = CompanyDetail.objects.first()
    except CompanyDetail.DoesNotExist:
        company = ''

    features = Feature.objects

    contact_details = ContactDetail.objects.first()

    banners = Banner.objects
    return render(request, 'home.html', {'overview': overview,
                                         'services': services,
                                         'company': company,
                                         'features': features,
                                         'contact_detail': contact_details,
                                         'banners': banners})

def company(request):
    services = Service.objects
    try:
        company = CompanyDetail.objects.first()
    except CompanyDetail.DoesNotExist:
        company = ''

    features = Feature.objects
    contact_details = ContactDetail.objects.first()
    return render(request, 'company.html', {'services': services,
                                            'company': company,
                                            'features': features,
                                            'contact_detail': contact_details,})

def team(request):
    services = Service.objects
    members = TeamMember.objects
    try:
        teampage = TeamDetail.objects.first()
    except TeamDetail.DoesNotExist:
        teampage = ''
    contact_details = ContactDetail.objects.first()
    return render(request, 'team.html', {'services': services,
                                         'members': members,
                                         'teampage': teampage,
                                         'contact_detail': contact_details,})

Answer 1

不需要在每个视图都做，写自定义即可 context processor:

def contact_details(request):
    return {'contact_detail': contact_details = ContactDetail.objects.first()}

并将其添加到 TEMPLATES 设置：

TEMPLATES = [
    {
        'BACKEND': 'django.template.backends.django.DjangoTemplates',
        'DIRS': [],
        'APP_DIRS': True,
        'OPTIONS': {
            'context_processors': [
                'django.template.context_processors.debug',
                'django.template.context_processors.request',
                'django.contrib.auth.context_processors.auth',
                'django.contrib.messages.context_processors.messages',
                'path.to.processor.contact_details'
            ],
        },
    },
]

Answer 2

您可以切换到 class base template views 并编写您的自定义基础 class

class MyBaseTemplateView(TemplateView):
    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        context['contact_details'] = ContactDetail.objects.first()
        return context


class MyActualView(MyBaseTemplateView):
    template_name = 'company.html'

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        # set other specific context values for this view here
        return context

并将这些视图添加到您的 urls.py 中，如下所示：

urlpatterns = [
    path('', MyActualView.as_view(), name='myactualview'),
]

如何为所有模板获取相同的信息？

How to get the same information for all templates?

html

django

jinja2

django-2.1