如何解决属性错误'float' object has no attribute 'split' in python？

Question

当我运行下面的代码时，它给我一个错误说有属性错误：'float'对象在python中没有属性'split'。

我想知道为什么会出现这个错误。

def text_processing(df):

    """""=== Lower case ==="""
    '''First step is to transform comments into lower case'''
    df['content'] = df['content'].apply(lambda x: " ".join(x.lower() for x in x.split() if x not in stop_words))

    return df

df = text_processing(df)

错误的完整回溯：

Traceback (most recent call last):
  File "C:\Program Files\JetBrains\PyCharm Community Edition 2018.2.2\helpers\pydev\pydevd.py", line 1664, in <module>
    main()
  File "C:\Program Files\JetBrains\PyCharm Community Edition 2018.2.2\helpers\pydev\pydevd.py", line 1658, in main
    globals = debugger.run(setup['file'], None, None, is_module)
  File "C:\Program Files\JetBrains\PyCharm Community Edition 2018.2.2\helpers\pydev\pydevd.py", line 1068, in run
    pydev_imports.execfile(file, globals, locals)  # execute the script
  File "C:\Program Files\JetBrains\PyCharm Community Edition 2018.2.2\helpers\pydev\_pydev_imps\_pydev_execfile.py", line 18, in execfile
    exec(compile(contents+"\n", file, 'exec'), glob, loc)
  File "C:/Users/L31307/Documents/FYP P3_Lynn_161015H/FYP 10.10.18 (Wed) still working on it/FYP/dataanalysis/category_analysis.py", line 53, in <module>
    df = text_processing(df)
  File "C:/Users/L31307/Documents/FYP P3_Lynn_161015H/FYP 10.10.18 (Wed) still working on it/FYP/dataanalysis/category_analysis.py", line 30, in text_processing
    df['content'] = df['content'].apply(lambda x: " ".join(x.lower() for x in x.split() if x not in stop_words))
  File "C:\Users\L31307\AppData\Roaming\Python\Python37\site-packages\pandas\core\series.py", line 3194, in apply
    mapped = lib.map_infer(values, f, convert=convert_dtype)
  File "pandas/_libs/src\inference.pyx", line 1472, in pandas._libs.lib.map_infer
  File "C:/Users/L31307/Documents/FYP P3_Lynn_161015H/FYP 10.10.18 (Wed) still working on it/FYP/dataanalysis/category_analysis.py", line 30, in <lambda>
    df['content'] = df['content'].apply(lambda x: " ".join(x.lower() for x in x.split() if x not in stop_words))
AttributeError: 'float' object has no attribute 'split'

Answer 1

错误指向这一行：

df['content'] = df['content'].apply(lambda x: " ".join(x.lower() for x in x.split() \
                                    if x not in stop_words))

split 在这里用作 Python 的内置 str class 的方法。您的错误表明 df['content'] 中的一个或多个值属于 float 类型。这可能是因为存在空值，即 NaN，或非空浮点值。

一种变通方法是将浮点数字符串化，即在使用 split 之前在 x 上应用 str：

df['content'] = df['content'].apply(lambda x: " ".join(x.lower() for x in str(x).split() \
                                    if x not in stop_words))

或者，可能是更好的解决方案，明确并使用带有 try / except 子句的命名函数：

def converter(x):
    try:
        return ' '.join([x.lower() for x in str(x).split() if x not in stop_words])
    except AttributeError:
        return None  # or some other value

df['content'] = df['content'].apply(converter)

由于 pd.Series.apply 只是一个有开销的循环，您可能会发现列表理解或 map 更有效：

df['content'] = [converter(x) for x in df['content']]
df['content'] = list(map(converter, df['content']))

Answer 2

split() 是一种 python 方法，仅适用于字符串。似乎您的列 "content" 不仅包含字符串，还包含其他值，例如您无法应用 .split() 方法的浮点数。

尝试使用 str(x).split() 将值转换为字符串，或者先将整个列转换为字符串，这样效率会更高。您按如下方式执行此操作：

df['column_name'].astype(str)

如何解决属性错误'float' object has no attribute 'split' in python？

How to solve the Attribute error 'float' object has no attribute 'split' in python?

python

string

series

attributeerror

pandas